About 2/3 of all cases fall within one standard deviation of the mean, that is For example, F(0) = 5; half the area of the standardized normal curve
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the mean and the variance do not completely determine the distribution, by a normal distribution with a mean of 3 and a standard deviation of 4
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Given the mean and standard deviation of a normal curve, we'd like to approximate the proportion of data that falls within certain intervals
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1 Find the range of values that represent the middle 99 7 of the distribution SOLUTION: The middle 99 7 of data in
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mean and standard deviation, it will use the default values Example: 1 Find P(Z < -1 05), which is the area under the standard normal curve to the left of
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standard normal distribution, which has mean 0 and variance 1, will be used to determine probabilities of the general normal distribution
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In Section 5 2, you will discover how to calculate normal probabilities As the mean of the normal distribution and a is its standard deviation
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For example, if IQ's are normally distributed with a mean of 100 and a standard Usage for any normal distribution with mean µ and standard deviation ?
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Calculating Cumulative Probabilities from a Normal Distribution 2 Example: Suppose IQ's are normally distributed with a mean of 100 and standard deviation
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and its standard deviation is 1 893 / sqrt(25) = 0 379 ?That calculation gives us the standard error of the mean, i e , the estimated standard deviation of
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