[PDF] chinese remainder theorem proof rings

  • How do you prove the Chinese Remainder Theorem?

    Suppose that x and y are both solutions to all the congruences.
    As x and y give the same remainder, when divided by ni, their difference x ? y is a multiple of each ni.
    As the ni are pairwise coprime, their product N also divides x ? y, and thus x and y are congruent modulo N.

  • What is the general Chinese Remainder Theorem for rings?

    We can now state the general Chinese remainder theorem: Theorem (Chinese Remainder Theorem for Rings) Let R be commutative with 1 and I1,I2,,In be ideals of R.
    Then the map ? : R ? (R/I1) × (R/I2) ×···× (R/In) defined by ?(r)=(r + I1, r + I2, , r + In) is a ring homomorphism with kernel I1 ? I2 ?···? In.

  • What is the Chinese Remainder Theorem for two ideals?

    The Chinese Remainder Theorem requires that each of the ideals be pairwise coprime.
    This is essentially saying that the sets of points each ideal corresponds to are pairwise disjoint.13 fév. 2017

  • What is the Chinese Remainder Theorem for two ideals?

    f(x)=(x?a)Q(x)+R(a) where R(a)=f(a).
    So we have a corollary: a is a root of polynomial f(x)?(x?a)f(x).

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