[PDF] let l(d is a dfa that accepts sr whenever it accepts s show that l is turing decidable)



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Ans. If a language L is decidable there exists a decider D that decides L. Then



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If we run TM D on input ?D? then D accepts ?D? if and only if D doesn't If a language L is of Type DEC



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each terminal l ? ? the CFG G0 has a rule S ? lS in R. Also



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4.4.1 Consider the following Turing machine Create a DFA B such that L(B) = ?* ... Furthermore M will accept those DFA's whose language is.



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If H rejects accept.” 2. Page 3. 4. Consider the emptiness problem for Turing machines: ETM = { ?M?



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Accept if T accepts reject if T rejects.” Proof #2: The following TM decides ALLDFA: S = “On input ?A?



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Show that if M is a DFA that recognizes language B



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Prove that C is Turing-recognizable iff a decidable language D exists such Let T = {?M?





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Let L be the language such that every pair of adjacent 0's appear before A Turing machine M accepts an input w ? ?? if there is a sequence of states.



[PDF] Solution - CS5371 Theory of Computation

An example of a DFA in S: A DFA that accepts all strings (b) Ans To show S is decidable we construct a decider D for S as follows (Let C be a TM 



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Turing-decidable language Answer: A language A that is decided by a Turing machine; i e there is a Turing machine M such that M halts and accepts on any 



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Consider the decision problem of testing whether a DFA and a regular expression are equivalent Express this problem as a language and show that it is decidable 



[PDF] A is a DFA and L(A) = ? Want to show that

Construct a Turing machine T to show that S is decidable Let MR be the DFA that accepts the reverse of strings that are accepted by M Then L(MR) = L(M) 



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Problem 4 3: Let ALLDFA = {?A? A is a DFA that recognizes ?*} Show that ALLDFA is decidable Proof #1: The following TM decides ALLDFA: S = “On input 



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ADFA is decidable Theorem The language ADFA = {Bw B is a DFA that accepts the string w} is decidable Proof We want to build a TM M that decides ADFA:



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Theorem The set of regular languages is closed under the kleene star operation Proof Let L be a regular language We need to show that L 



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Prove that C is Turing-recognizable iff a decidable language D exists such Let T = {?M?M is a TM that accepts wR whenever it accepts w}(wR is the 





[PDF] Introduction to the Theory of Computation 3rd ed

nor do they accept any liabilities with respect to the programs S = {a ? D P(a) = TRUE} or simply S if the domain D is obvious from the context

  • How do you prove a DFA is decidable?

    E(dfa) is a decidable language. Proof: A DFA accepts some string iff reaching an accept state from the start state by >traveling along the arrows of the DFA is possible. To test this condition, we can design a >TM T that uses a marking algorithm similar to that used in Example 3.23. T= "On input , where A is a DFA: 1.

  • How do you show that a language is Turing-recognizable?

    To prove that a given language is Turing-recognizable: Construct an algorithm that accepts exactly those strings that are in the language. It must either reject or loop on any string not in the language.

  • What is the language accepted by a Turing machine explain your answer?

    A language is recursively enumerable (generated by Type-0 grammar) if it is accepted by a Turing machine. A TM decides a language if it accepts it and enters into a rejecting state for any input not in the language. A language is recursive if it is decided by a Turing machine.
  • Sipser (Theorem 5.13) shows that ALLCFG is undecidable. Define CFG G0 = (V, ?, R, S), where V = {S} and S is the starting variable. For each terminal ? ? ?, the CFG G0 has a rule S ? ?S in R. Also, G0 includes the rule S ? ?.
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