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8 Fourier Series

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1 (1 8 3) Let X have pdf f(x) = (x+2)=18 for 2 < x < 4, zero elsewhere Find E[X];E[(X + 2)3] and E[6X 2(X + 2)3] Answer: E[X] = 1 18 Z 4 22 x2 + 2xdx = 1 18 (x3 4



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