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www mathportal 2 2 2 2 2 2 2 2 2 2 2 arctan 4 0 4 4 1 2 2 4 ln 4 0 4 2 4 2 4 0 2 ax b for ac b ac b ac b ax b b ac dx for ac b ax bx c b ac ax b b ac for ac b
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散裂中子源进展汇报 March 25, 2015 Page 9 4 The result • We have a experiments with 3-years accelerator tunnel measured data in BEPC And we have done the difference between it and the result about “Survey” program computation (Unit: mm) Year Precision The min The Max The Ave The MSA 2009
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arctg z z 1 2 La réponse présente la forme d'une sinusoïde amortie de pseudo - période T pa z n = − 2 1 2 π ω on appelle pseudo - pulsation : ωωpa =−n 1 z 2 Le dépassement est un critère important pour un asservissement: L'instant du premier dépassement est T T pm z pa n == 2 1− 2 π ω sTpa KE e z ()=+z
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