Compiler warning unused variable

How do I get rid of unused variable warning?

Solution: If variable \x26lt;variable_name\x26gt; or function \x26lt;function_name\x26gt; is not used, it can be removed.
If it is only used sometimes, you can use __attribute__((unused)) .
This attribute suppresses these warnings..

How do I suppress unused function warning in GCC?

To suppress this warning use the unused attribute (Variable Attributes).
All the above -Wunused options combined.
In order to get a warning about an unused function parameter, you must either specify -Wextra -Wunused (note that -Wall implies -Wunused), or separately specify -Wunused-parameter..

How do I suppress unused warning in GCC?

To suppress the warning, cast the unused expression to void.
For example, an expression such as x[i,j] will cause a warning, but x[(void)i,j] will not..

How do you compile with unused variables?

If the unused variables are function parameters, the names can be omitted to silence warnings.
Ans: To compile with unused variables, you need to disable the compiler warning for unused variables..

How do you compile with unused variables?

If there are a large number of unused variables or functions, which can happen with ported code, you can add the -Wno-unused compiler option to your makefile.
This option suppresses all unused warnings..

How do you deal with unused parameters?

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1. You can use the __attribute__((unused)) annotation on the parameter.
This is fugly as all hell, but it is at least unambiguous.
2. Use the -Wno-unused-parameter compiler flag
3. Don't name the parameter
4. My preference
5. Bonus: in combination with the previous point, I tend to name unused params ' _ ' (and ' __ ', and so on)

How to handle unused parameter in C?

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1. You can use the __attribute__((unused)) annotation on the parameter.
This is fugly as all hell, but it is at least unambiguous.
2. Use the -Wno-unused-parameter compiler flag.
But please don't .
3. Don't name the parameter.
Something like int fn(char *c, float) {…

How to suppress unused variable warning in gcc?

To suppress this warning use the unused attribute (Variable Attributes).
All the above -Wunused options combined.
In order to get a warning about an unused function parameter, you must either specify -Wextra -Wunused (note that -Wall implies -Wunused), or separately specify -Wunused-parameter..

Why is unused variable an error?

Variables that are declared and not used anywhere in the code are most likely an error due to incomplete refactoring.
Such variables take up space in the code and can lead to confusion by readers..