May 24, 2017 complex analytic structure on it. complex-analysisfunctional-equationsmodular-formsmobius-transformationmodular-functionShare.What is the "$\tau$" of this elliptic curve - Mathematics Stack ExchangeFind a branch cut where $f(z)=\log_{\tau}(z^3 - 2)$ is holomorphic at complex analysis - Why is not $\eta(\tau+1)=\eta(\tau)$ although Show that there exists 0<τ<1 such that for all 0More results from math.stackexchange.com
May 24, 2017From this, I'm wondering if j is locally the square of a coordinate around i. This makes sense if you look at the fundamental domain for H mod What is the "$\tau$" of this elliptic curve - Mathematics Stack Exchangecomplex analysis - Why is not $\eta(\tau+1)=\eta(\tau)$ although Show that there exists 0<τ<1 such that for all 0λ(τ) as a rational function of j(τ) - Mathematics Stack ExchangeMore results from math.stackexchange.com
Oct 13, 2011More or less by definition, τ(λ) is the ratio of the periods of E(λ):y2=x(x−1)(x−λ). The periods are the integrals of dx/y over a pair of Solving the functional equation $\tau \left(\frac{-1}{z}\right)complex analysis - Why is not $\eta(\tau+1)=\eta(\tau)$ although complex analysis - Why $\int_0^{\infty} f(t)dt = \lim_{\tau \to \infty }g_\ Why locally $\tau\mapsto-1/\tau$ is a 180-degree rotation around $iMore results from math.stackexchange.com
Oct 13, 2011More or less by definition, τ(λ) is the ratio of the periods of E(λ):y2=x(x−1)(x−λ). The periods are the integrals of dx/y over a pair of Solving the functional equation $\tau \left(\frac{-1}{z}\right)λ(τ) as a rational function of j(τ) - Mathematics Stack Exchangecomplex analysis - Why is not $\eta(\tau+1)=\eta(\tau)$ although Functional equations of λ(τ) - Mathematics Stack ExchangeMore results from math.stackexchange.com
Oct 13, 2011More or less by definition, τ(λ) is the ratio of the periods of E(λ):y2=x(x−1)(x−λ). The periods are the integrals of dx/y over a pair of Solving the functional equation $\tau \left(\frac{-1}{z}\right)λ(τ) as a rational function of j(τ) - Mathematics Stack Exchangecomplex analysis - Why is not $\eta(\tau+1)=\eta(\tau)$ although Every $\tau$ in the U.H.P. is equivalent to *exactly one* point in the More results from math.stackexchange.com