constexpr lambda capture


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  • What does lambda capture do?

    Capture clause
    A lambda can introduce new variables in its body (in C++14), and it can also access, or capture, variables from the surrounding scope.
    A lambda begins with the capture clause.
    It specifies which variables are captured, and whether the capture is by value or by reference.

  • How does constexpr work in C++?

    constexpr indicates that the value, or return value, is constant and, where possible, is computed at compile time.
    A constexpr integral value can be used wherever a const integer is required, such as in template arguments and array declarations.

  • To capture a variable by reference, we prepend an ampersand ( & ) to the variable name in the capture.
    Unlike variables that are captured by value, variables that are captured by reference are non-const, unless the variable they're capturing is const .

  • Can lambda be a constexpr in C++?

    The C++17 version allowed the lambda expressions to be used in constant expressions.
    C++ lambda can be used in a constexpr or declared as a constexpr.
    If a lambda expression satisfies all the requirements of a constant expression, then it will be an implicit constexpr, even without specifying constexpr.11 oct. 2022

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