cone equation in spherical coordinates
What is the equation for spherical coordinates?
To convert a point from spherical coordinates to Cartesian coordinates, use equations x=ρsinφcosθ,y=ρsinφsinθ, and z=ρcosφ.
To convert a point from Cartesian coordinates to spherical coordinates, use equations ρ2=x2+y2+z2,tanθ=yx, and φ=arccos(z√x2+y2+z2).What is the equation of the cone Z?
Transcribed image text: Given: The equation of the cone z=x2+y2 is given in cylindrical coordinates as z=r and in spherical coordinates as ϕ=4π 1.
Use cylindrical coordinates x=rcosθ,y=rsinθ, and z=z to give a parametrization of this cone.To find the surface area of a cone in spherical coordinates, you can use the formula: SA = πr2sinθ, where r is the radius of the base of the cone and θ is the angle between the cone's axis and the vertical axis.
What is the Cartesian equation of a cone?
Cone.
Cartesian equation of a cone with vertex O: f(x, y, z) = 0 with f homogeneous.
In particular: z = f(x, y) with f homogeneous of degree 1.
Cartesian parametrization: (directrix ).
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Solutions #8
In polar coordinates this equation becomes r = ?. 8 ? r2 ?? 2r2 = 8 ?? r = 2. Hence |
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6.17** Find the geodesics on the cone whose equation in cylindrical polar coordinates is z = ?p. [Let the required curve have the form = (p).] |
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Solutions
In polar coordinates, this equation becomes r = √ 8 − r2 ⇐⇒ 2r2 = 8 ⇐⇒ r = 2 Hence, we can compute the volume of the ice cream cone by finding the |
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