roots of second order equation

What is the formula for the roots of a second order polynomial?
The roots can be found from the quadratic formula: x₁_,₂ = (-b ± √b² - 4ac) / 2a, In addition to the four arithmetic operations, the formula includes a square root.
The expression under the square root, D = b² - 4ac - known as the discriminant - may be positive, zero, or negative.
A quadratic equation is a second order equation written as ax² + bx + c = 0 where a, b, and c are coefficients of real numbers and a ≠ 0.

How do you find the roots of a second order equation?

Important Formulas for Quadratic Equation Roots include:
ax² + bx + c = 0 is a quadratic equation.
Use the formula x = (-b ± √ (b² – 4ac) )/2a. to calculate the roots.
D = b² – 4ac is the discriminant.

A quadratic equation with real or complex coefficients has two solutions, called roots. These two solutions may or may not be distinct, and they may or may not Quadratic formula · Completing the square · Solving quadratic equations Autres questions

Repeated roots of the characteristic equation Second order differential equations Khan Academy

Complex roots of the characteristic equations 1 Second order differential equations Khan Academy

Second Order Linear Differential Equations

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NOTES ON SECOND ORDER LINEAR DIFFERENTIAL

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