chinese remainder theorem example 3 congruences


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PDF Math 127: Chinese Remainder Theorem

The Chinese Remainder Theorem gives us a tool to consider multiple such congruences work as we did in Example 2 to rewrite this equation as a x ≡ b (mod n )

PDF Linear Congruences Chinese Remainder Theorem Algorithms

Recap - linear congruence ax ≡ b mod m has solution if and only if g = (a m) divides b How do we find these solutions? Case 1: g = (a m) = 1 Then invert a 

  • What is the remainder theorem in linear congruence?

    The Chinese remainder theorem is a theorem which gives a unique solution to simultaneous linear congruences with coprime moduli.
    In its basic form, the Chinese remainder theorem will determine a number p that, when divided by some given divisors, leaves given remainders.

  • Can Chinese remainder theorem solve congruences?

    The Chinese remainder theorem says we can uniquely solve every pair of congruences having relatively prime moduli. x ≡ a mod m, x ≡ b mod n has a solution, and this solution is uniquely determined modulo mn.
    What is important here is that m and n are relatively prime.
    There are no constraints at all on a and b.

  • Cryptography: The CRT is used in several cryptographic systems to generate and verify digital signatures.
    For example, the RSA cryptosystem uses CRT to speed up the decryption process.
    It computes the ciphertext modulo of two different primes and then combines the two results using the CRT.

  • What is an example of the Chinese remainder theorem?

    For example, if we know that the remainder of n divided by 3 is 2, the remainder of n divided by 5 is 3, and the remainder of n divided by 7 is 2, then without knowing the value of n, we can determine that the remainder of n divided by 105 (the product of 3, 5, and 7) is 23.

  • Example: Solve the simultaneous congruences x ≡ 6 (mod 11), x ≡ 13 (mod 16), x ≡ 9 (mod 21), x ≡ 19 (mod 25). Solution: Since 11, 16, 21, and 25 are pairwise relatively prime, the Chinese Remainder Theorem tells us that there is a unique solution modulo m, where m = 11⋅16⋅21⋅25 = 92400.
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