chinese remainder theorem proof by induction


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PDF The Chinese Remainder Theorem

14 déc 2022 · The Chinese Remainder Theorem says that certain systems of simultaneous congruences with dif-

PDF Chinese Remainder Theorem RSA cryptosystem

We use induction to prove an infinite family of statements The outline for induction goes as follows: Let P(n) be a statement about the integer n and suppose 

PDF Chinese remainder theorem

A proof of the Chinese remainder theorem Proof First we show there is We argue by induction on r The base case r = 2 is Theorem 1 1 which has been 

PDF Chinese Remainder Theorem

We prove the last part by strong induction: Let P(n) be the statement 20 + 5k can be written as 10a + 25b for a b ∈ Z≥0 Our base cases are P(0) : 20 + 5(0) 

  • What is Chinese remainder theorem powers?

    Theorem (Chinese Remainder Theorem): Let m and n be integers and co-prime.
    Then for any integers a and b , the congruences, x≡a(modm) x ≡ a ( mod m ) and x≡b(modn) x ≡ b ( mod n ) have a unique solution 0≤x<mn 0 ≤ x < m n .

  • What is the Chinese remainder theorem by induction?

    The Chinese remainder theorem asserts that if the ni are pairwise coprime, and if a1, , ak are integers such that 0 ≤ ai < ni for every i, then there is one and only one integer x, such that 0 ≤ x < N and the remainder of the Euclidean division of x by ni is ai for every i.

  • Example: Solve the simultaneous congruences x ≡ 6 (mod 11), x ≡ 13 (mod 16), x ≡ 9 (mod 21), x ≡ 19 (mod 25).
    Solution: Since 11, 16, 21, and 25 are pairwise relatively prime, the Chinese Remainder Theorem tells us that there is a unique solution modulo m, where m = 11⋅16⋅21⋅25 = 92400.

  • Is Chinese remainder theorem unique?

    At this point, since the moduli 3, 4, and 11 have the property that every two are relatively prime, the Chinese Remainder Theorem states that there is a unique solution to these congruences among the integers between 0 and 131 (here 3⋅4⋅11=132).

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