how to determine if a linear transformation is surjective


The rank of a linear transformation plays an important role in determining whether it is injective, whether it is surjective, and whether it is bijective. Note  Questions d'autres utilisateurs
  • How do you know if a linear transformation is surjective?

    Suppose that T:U?V T : U ? V is a linear transformation. Then T is surjective if and only if the range of T equals the codomain, R(T)=V R ( T ) = V .
  • How do you know if a linear transformation is surjective or injective?

    A map is said to be:

    1surjective if its range (i.e., the set of values it actually takes) coincides with its codomain (i.e., the set of values it may potentially take);2injective if it maps distinct elements of the domain into distinct elements of the codomain;3bijective if it is both injective and surjective.
  • How do you prove surjection?

    To prove that a given function is surjective, we must show that B ? R; then it will be true that R = B. We must therefore show that an arbitrary member of the codomain is a member of the range, that is, that it is the image of some member of the domain.
  • A linear transformation can be bijective only if its domain and co-domain space have the same dimension, so that its matrix is a square matrix, and that square matrix has full rank.
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