how to prove a language is decidable


ADFA is decidable. Theorem. The language. ADFA = {B,w. B is a DFA that accepts the string w} is decidable. Proof. We want to build a TM M that decides ADFA:.Autres questions
  • How do you prove language is decidable?

    How can you prove a language is decidable? A language L is decidable if there exists a TM M such that for all strings w: – If w ? L, M enters qAccept. – If w ? L, M enters qReject.
  • What is the rule to prove a particular language is a decidable language?

    A language is called Decidable or Recursive if there is a Turing machine which accepts and halts on every input string w. Every decidable language is Turing-Acceptable.
  • How do you know if a problem is decidable?

    A problem asks a yes/no question about some input. The problem is decidable if there is a program that always halts and always answers the ques- tion correctly.
  • E(dfa) is a decidable language. Proof: A DFA accepts some string iff reaching an accept state from the start state by >traveling along the arrows of the DFA is possible. To test this condition, we can design a >TM T that uses a marking algorithm similar to that used in Example 3.23. T= "On input , where A is a DFA: 1.
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