Problem 3 Write regular expressions for the following languages: (c) The set of strings of 0's and 1's whose number of 0's is divisible by five and whose
29 sept 2015 · (b) The set of all strings whose tenth symbol from the left end is a 1 3 (d) The set of strings such that the number of 0's is divisible by five, and
HW Sols
Construct a DFA that accepts all strings over {0,1} decimal, is divisible by 5 (or, multiple of 5) 3 – The set of all strings such that each block of five consecutive symbols contains at least two 0's of all strings of 0's and 1's whose number of
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Homework 3 Solutions 1 Give NFAs with the specified number of states recognizing each of (c) The language { w ∈ Σ∗ w contains at least two 0s, or exactly two 1s } with six Note that M′ accepts the string 100 ∈ C = { w w does not end with 00 }, so Thus, we first create a DFA state corresponding to the set {1, 2}:
hwsoln
(b) the set of strings in {a} * whose length is divisible by either 2 or 7; (e) the set of strings in {O, 1, 2} * that are ternary (base 3) representa- (c) {x I x contains an even number of a's or an odd number of b's} A context-sensitive grammar (CSG ) or type 1 grammar is a type 0 (Sanity check: the string has five parse trees )
number 0s read modulo 2, the other indicating the number of 1s read modulo 3 binary strings divisible by 3, the other accepting ternary strings divisible by 4 Solution: The language is identical to the set of strings w such that w mod 12
lab bis sol
Ashutosh Gupta and S Akshay Compile date: 2019-01-22 1 In the lecture, we added an (a) the set of binary strings whose number of 0's divisible by five
tut sheets
Question 1 [3 marks] Use the product construction to construct a deterministic finite automaton (DFA) that accepts all binary strings with an even number of 0's
solution assignment
Chapter 3 SNA Regular Expressions and Languages ** We begin this chapter by a single 0 followed by any number of l's or a single 1 followed by any number b) The set of strings of O's and l's whose number of O's is divisible by five
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Recognize strings representing numbers: Σ = {0,1,2,3 0, ,9 0, ,9 Note: 0, ,9 means 0,1,2,3,4,5,6,7,8,9: 10 transitions Proof idea: Complement the set of accept states ○ Example Is L = {w in {0,1}* : w is divisible by 3 OR w starts with
slides regular
29 sept. 2015 (b) The set of all strings with three consecutive 0's (not ... such that the number of 0's is divisible by five and the number of 1's.
such that each block of five consecutive symbols contain at least. {0 (c) The set of strings of 0's and 1's whose number of 0's is divisible by five and.
Example: 01101 and 111 are strings from the binary alphabet ? = {01} ?k: the set of strings of length k
1?(01?01?)? — the set of all binary strings with an even number of 0s. • 0 +1(0 +1)?00 — the set of all non-negative binary numerals divisible by 4 and
c) The set of strings of 0's and l's that do not contain 11 as a substring. d) The set of strings of 0's and l's whose number of 0's is divisible by five.
Construct a DFA that accepts all strings over {01} The set of all strings such that each block of five ... The number of 0's in it.
(0 + 1)?: set of all strings over {0 1}. (0 + 1)?001(0 + 1)?: strings 0? + (0?10?10?10?)?: strings with number of 1's divisible by 3. ?0: {}.
8 févr. 2007 Solution: Any string in the language must be composed of 0 or more blocks each hav- ing exactly five 0's and an arbitrary number of 1's between ...
15 janv. 2015 b) The set of strings of 0's and 1's whose number of 0's is divisible by five. Exercise 2 (Ex 3.1.3 page 92). Write regular expressions for ...
The set of strings of 0's and 1's whose number of 0's is divisible by five. * Exercises above are from Introduction to Automata Theory Languages
Sep 29 2015 · The set of all strings whose tenth symbol from the left end is a 1 The set of strings that either begin or end (or both) with 01 The set of strings such that the number of 0's is divisible by ve and the number of 1'sis divisible by 3 Exercise 2 2 8 on page 54 of Hopcroft et al
Pick string = 1p Then we can break string into u v w such that v is not empty and u v < k Suppose v = m Then u w = p – m If the language really is regular the string u vp-m w must be in the language But u vp-m w = p – m+ (p-m)m which can be factored into (m+1)(p-m) Thus this string does not have a length which is prime and
Homework 1 Problems