What is the vapor pressure of water at 110 °C?
The vapor pressure of pure water at 110 °C is 1070 torr= 1.41 atm (being 760 torr= 1atm). A solution of ethylene glycol and water has a vapor pressure of 1.00 atm at 110 °C. On the other side, if a solute has a measurable vapor pressure, the vapor pressure of its solution is always less than that of the pure solvent.
What is the vapor pressure of ethylene glycol at 110 °C?
The vapor pressure of pure water at 110 °C is 1070 torr. A solution of ethylene glycol and water has a vapor pressure of 1.00 atm at 110 °C. Assuming that Raoult’s law is obeyed, what is the mole fraction of ethylene glycol in the solution? g Considering the Roult's law, the mole fraction of ethylene glycol in the solution is 0.291
How do you use Raoult's law to calculate vapor pressure?
Use Raoult’s law to calculate the vapor pressure of the solution. A A 30.2% solution of ethylene glycol contains 302 g of ethylene glycol per kilogram of solution; the remainder (698 g) is water. To use Raoult’s law to calculate the vapor pressure of the solution, we must know the mole fraction of water.
What is the relationship between solution composition and vapor pressure?
The relationship between solution composition and vapor pressure is therefore where PA is the vapor pressure of component A of the solution (in this case the solvent), XA is the mole fraction of A in solution, and P0 A is the vapor pressure of pure A. Equation 13.6.1 is known as Raoult’s law, after the French chemist who developed it.