[PDF] Heat and Heat Capacity Consider two bodies at different





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[PDF] Heat and Heat Capacity Consider two bodies at different 127920_3ch15_part2.pdf

Heat and Heat CapacityConsider two bodies at different temperatures in thermal contact. Then internal or thermal energy from the hot body will flow to the cold body. The energy transferred is called heat.In thermodynamics heat always refers to an energy transfer. It is technically incorrectto say a body has a certain amount of heat.One can increase the temperature of a body by increasing the internal energy through heat transfer (e.g.(heating a liquid with a flame) or by doing work on the body (e.g. stirring a liquid, moving one surface past another friction, or bending a metal wire etc). For the moment we assume no work is being done and restrict the discussion to heat transfer. (W=0) We use symbol Q for a finite amount of heat transfer whereas an infinitesimal amount of heat is dQ. The common units o are the cal (calorie) or Btu (British thermal unit)1 calis heat required to raise the temperature of 1gm of water from 14.5 oCto 15.5oC.kcal=1000cal is one food energy calorie1Btuis the heat required to raise one pound water from 63oF to 64oF.1cal=4.186 J1Btu=778ft.lb= = 252 cal

Change in Internal Energy of a body equals heat transfer + work done(U=Q+W)

Work=Force x distance

Heat

Specific Heat CapacityConsider a body of mass m at temperature To.How much heat Q is required to raise the temperature by an infinitesimal amount dT?. mcdTdQdQscales with the mass of an object since it takes twice as much energy change the temperature of body with twice the mass. The constant of proportionality c is called the specific heat capacity. c depends in detail on the material properties (i.e. constituent atoms, interactions between them, structure etc). In general it also depends on the temperature To but for small finitechanges in the temperature T=T-To (away from any phase transition) it can be assumed to be a constant so that TmcQSpecific heat of water at 15oC is 1 cal/gCor 4190J/kg.K or 1 Btu/lb.Fo.See table 15-3 for a list of heat capacities.Example 15-8. Consider a 23 mg Simicrochip absorbing 7.4 mW. What will T rise be after one minute if you don't design any cooling mechanism? KKkgJkgsJsmcQT27/705102360104.7613

Molar Heat Capacity (C)Similarly one can define a molar heat capacity C=McWhere M is the mass per mole of a substance. Then using m=nMwhere n is the number of molesTnCTnMcQFor water C=Mc=(0.018kg/mole) 4190 J/kg.K=75.4 J/mole.KHeat capacities measured at constant pressure are denoted cpor Cp. In gases heat capacities can also be measured at constant volume and are then denoted cvor Cv.. In general cvand cpare different. Note from table 15-3 heat capacities of all the elements are all about the same. Al (M=27 g/mole) is 24.6 J/mole.Kwhereas Ag(M=108 g/mole) is 25.3 J/mole.K. Thus the heat capacity depends on the number of atoms rather than their mass!This is the rule of Delong and Petitwhich we discuss later.

Latent Heat and Phase TransitionsAs the temperature of substance passes through certain values (transition temperatures Tc) its physical properties may change suddenly as a result of a phase transition. It exists in one phase below Tcand another phase above Tc. e.gwater vapor condenses into liquid water below 100 oCand water freezes into ice at 0oC. There are many different kinds of phase transitionsin nature. The most well known type (call first order) involves a latent heat. This is the energy or heat per unit mass required to covert the substance from one phase to another at the transition temperature at TcLatent heat is given the symbol L . UcL

Consider what happens when one supplies a steadyflow of heat into a body. Below Tctemp rises steadily according to cvof the lower phase. At Tcthe temperature stops increasing, the two phases coexist the amount of the lower phase decreases while that of the upper phase increases.

Latent heats associated with vaporization and freezing t

Latent heat associated with freezing is call the heatof fusionand denoted Lf. For water:Lf=3.34 x 105 J/kg=79.6 cal/gHeat of vaporizationis denoted Lv. For waterLv=2.256 x 106 J/kg=539 cal/g. Consider a block of ice mass m being heated at a constant rate R. What is the temperature as function of time? At a phase transition the temperature stays constant for a time t during which the two phases coexist. All the energy goes into changing one phase to another.RmLtv/

Example1Consider two bodies masses at different temperatures TCand TH. Bring them into thermal equilibrium. What is final temperature T given they have masses m1and m2and heat capacities cCand cHrespectively.Assume no phase transition.

HHCCHHHCCCHHHCHCHHHHHCCCCC

mcmcTmcTmcTTmcTTmcTTmcQUTTmcQU

T:obtain weTfor Solving0)()( thus)()(:0UU i.e. equlibrium reachingafter bodies)(both system theofenergy internal in the change no implieson conservatiEnergy HC

Exercise : Repeat this for three bodies, m1, m2and m3.

Example 2:Now assume the colder body (C) is a solid (e.g. ice) at the melting temperature and that all the ice meltswhen put in thermal equilibrium with hot body (H). What is the final temperature given the latent heat of fusion is Lf?

:find weTfor Solving 0.UU of sum thesystem theofenergy internal totalin the change no is theresince before As)()(HCHHCCfCCCCHHHHHHHCCCfCC

cmcmLmTcmTcmTTTcmUTTcmLmU

Note this isthe similar to the previous example exceptthe latent heat term lowers the average temperature. Question: What is T if only a fraction (f) of the solid melts when the two bodies reach thermal equilibrium?What are UC and UH ? Question:What if you don't know if all the ice melts or not?

Latent heat cont'd Example 3How much heat is required to bring of ice at -50oCinto steam? kJ

4663Total -------------------------------------------------------------3384kJ2256kJ/kg1.5kgmLQ water boil 4 StepkJ628100KKkg4.186kJ/1.5kgmcQ :C010C0 3 Step501kJ334kJ/kg 1.5kgmLQ icemelt Step2150kJ50K K2kJ/kg1.5kgmcQ :C0C50- 1 Stepv4water3oof2ice1oo

What is the temperature if you only supply 1000kJ?

C55.6C55.6C0T55.6K TTKkg4.186kJ/1.5kgkJ 349over.left kJ 349 so icemelt just to501kJ)(150kJ651kJooo

Heat TransferHeat transfer from one body to another may take placein 3 distinct ways conduction, convection and radiation.Conductioninvolves no change in atomic positions but energy of atomic vibrations (and free electrons)moves from hot regions to colder regions. i.e. regions of high energy density to low energy. Considera conducting rod of length L and area A connecting between two bodies at THand TC.

Fig. 15-13Then the rate of heat flow dQ/dtfrom hot to coldis called heat current or H and experimentally is given by:where k is called the thermal conductivity and depends only on the properties of the material and not the dimensions. k has units W/m.K. A good conductor like Cu has k=385 W/m.Kwhereas a good insulator like glass has k=0.8 W/m.KLTTkAHCH

Example. What is the rate at which ice melts insidea 2 cm thick stryrofoamcooler. (k=0.01W/m.K from table 15-5) with an area is 0.8m2given the outside temperature is 30oC?

skgkgJsJH/LRsJWmCCmKmWHfoo/106.3/1034.3/12by given is melts iceat which rate The/121202.0)030()80.0)(./01.0(552LTTkAHCH

Thermal resistance One can rewrite the heat flow equation so that it is similarto Ohm's law for electricity where the voltage drop (V) across a resistor with current I is given by:

L/kAR resistance thermal the where;HR T :anlogyIn IR Vtte

Note this definition of thermal resistance is different than in the text where R=L/k.We will call this the R-factor or Rf(see below). Thermal resistances of two substances add in series just the way electrical resistances do. Suppose one has two bars end to end between the hot and cold resevoirs. What is the heat flow?

Let Txbe the temperature at the interface between two materials labeled a and b. The key point is that in the steady state the heat current flowing in bar a is the same as in bar bin order for energy to be conserved. bbbbbbCXaaaaaaXHbaA/kLR where;RH TTA/kLR where;RHTTonconservatienergy by HHHAdding the last two equations with H=Ha=Hbyields:)RH(RTTbaCHNow you can solve for H and Tx. Exercise this for repeat for 3 bodies a,band c. It can be generalized to n different substances in series. n321totaltotalCH...RRRRR whereHRTT

R-factor (Rf) In Industry the R-factor is defined as:fCHtf)/RT-A(TH that so .AR kLRThis gives a way to rate the insulation value of a certainthickness of a material. The SI units of Rfare m2.K/W.whereas in commercial applications theyare in ft2.oF.h/Btu but usually quoted withoutunits. e.g. a 6 inch layer of fiberglass has an R-factor of 19meaning 19 ft2.oF.h/Btu. Heat current through several layers of different substancesis obtained by adding the R-factors just like thermal resistances, Rt.totfCHnf2f1ftotfR)TA(TH....RRRRExample:What is the heat flow through a wall panel2ft wide and 8ft high composed of 6in fibreglass(R=19)and 3/8 in gypsum (R=0.32) with 20 oCon one side and 0oC on other? .29W03600s1055JhBtu18.7W29.8Btu/hBtu/hF..32)ft(19.0F3616ftHo2o2

Thermal resistors in parallelSuppose the two resistors are in parallel as follows

stCutottotCHstCHststCuCHCuCustCuR1R1R1 whereRTT11)( L)T(TAkL)T(TAk HHHstCuCHRRTTIn other words thermal resistors in parallel add likeelectrical resistors in parallel. Put in the numbers using table 15-5 where kCu=385 W/m.Kand kst=50.2W/m.K

ConvectionOnly liquids and gases can transfer heat by convectionsince motion of atoms/molecules is required. In general there is no simple theory for convection. Some experimental facts are:1.The heat flow from convection scales with area.2.The atoms of a gas/liquid near the solid surface are slowed by viscosity. This leads to a quasi-stationary layer of gas near the surface presents a surface resistance to heat flow from convection. The layer is decreased if the gas/liquid is forced.Example: Redo the calculation of heat flow from the wall panel taking into account the R-factor for stationary air (e.g. inside a house) is Rf,in=0.68 whereasfor blowing air(outside) Rf,out=0.17. 8.3W28.5Btu/hBtu/hF.0.17)ft0.680.32(19.0F3616ftHo2o2compared to 8.7 W without the surface resistance.

RadiationAny body at finite T will radiate electromagnetic energy (light) even in a vacuum.This is another means by which energy may be transferred from a hot body to a cold body. Consider a sphere at T=Ts. The body emits so called black body radiation with a spectrum as follows:

The radiation emitted for a body of surface area A is given by the Stefan Boltzmanlaw:where T is absolute temperature in K, e is the emissivity, and is the Stefan Boltzmanconstant equal to:425KW/m10)5.67051(19

s

I(High TLow TK/T0.2898cmmax

4TAeH

Radiation Cont'dEmissivitye is a property of the materialand equal to a number between 0 and 1. A black body, which by definition absorbs everything, has e=1 whereas reflective materials have e values less than 1. Now suppose the body is surrounded by another body at temperature To which radiates onto the inner sphere.

If To=Ts radiation emitted by the inner sphere must equal to the radiation absorbed,If the inner and out spheres are not at the same T then the net radiation given off by the inner sphere is: Example: Consider a tungsten sphere (e=0.35) and radius 1.5 cm in a large evacuated enclosure with walls at 26.8oC. What power is needed to keep the temperature of the tungsten sphere at 3000K?

404404TTAeTAeTAeHssnet

Ts Example (Cont'd) W4545 300300035.0/1067.5)105.1(4444242822404KKmWmTTeAHs This document was created with Win2PDF available at http://www.daneprairie.com. The unregistered version of Win2PDF is for evaluation or non-commercial use only.

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