1 nov 2004 · What this analysis teaches is that in order to separate the Schr?dinger equation of the one-electron atom, we need to transform the kinetic
This is a separation technique to separate an insoluble substance from a An atom is neutral because it has the same number of electrons and protons
Because of their small mass, the behavior of electrons in atoms and which had formerly been considered separate, were now recognized as
Question: How are electrons 'arranged' in an atom? The equation indicates the energy required to separate the electron (q1) from
Helium atom with two electrons 1 and 2 at positions r2 and r2 So the energy levels are split by the exchange energy ?ab with the normalized
required to release electron from atom or ion potentials of separate elements included into material electron in an atom, taking it to a higher
A wave function for an electron in an atom is called an atomic orbital; this atomic orbital describes a region of space in which there is a high probability
o The neutrons in an atom have very little influence on the chemical behavior of the atom c Electrons ? Each electron has a ?1 electrical charge (1 unit of
atom? Consider using some or all of the following terms in your description: The equation indicates the energy required to separate the electron (q1) from
How can we determine energy levels of a multi-electron atom? We could start electron In jj coupling, separate energy shifts independent of total J and MJ,
separating into multiplets of n2-fold degeneracy, where n denotes the principle quantum number For a hydrogen-like atom, with just a single electron, 2s +1=2
2 5: Simplified model of a Helium (He) Atom He Mass number Atomic number Element symbol Electron distribution diagram (b) Separate electron orbitals
Atoms will covalently bond until their outer energy level is full • Atoms covalently bonded as a molecule are more stable than they were as separate atoms
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Lecture12
Atomicstructure
Atomicstructure:background
Ourstudiesof hydrogen-likeatom srevealedthat thespectrumof theHamiltonian, ˆ H 0 = ˆp 2 2m - 1
4π?
0 Ze 2 r ischaract erizedbylargen 2 -folddegeneracy. However,althoughthenon-relativisticSchr¨odingerHamiltonian providesausefulplatform, theformulation isalittle toona¨ıve. TheHamiltonianis subjecttoseveral classesof"co rrections",which leadtoimp ortantphysical ramifications(whichreachbeyondthe realmofatomic physics).
Inthislecture, weoutline thesee
ff ects,beforemoving ontodiscuss multi-electronatomsin thenext.
Atomicstructure:hydrogenatomrevisited
Aswithany centrallysymmetricp otential,stationary solutionsof ˆ H 0 indexby quantumnumbersn?m,ψ n?m (r)=R n? (r)Y ?m (θ,φ).
Foratomichydrogen,n
2 -degenerateenergylevels setby E n =-Ry 1 n 2 ,Ry= ? e 2
4π?
0 ? 2 m 2? 2 = e 2
4π?
0 1 2a 0 wheremisreducedmass (ca.electron mass),anda 0 =
4π?0
e 2 ? 2 m .
Forhighersingle-electronions(He
+ ,Li 2+ ,etc.),E n =-Z 2Ry n 2 .
Allowedcombinationsofquantumnumbers:
n?Subshell(s) 101 s
20,12s2p
30,1,23s3p3d
n0···(n-1)ns···
Atomicstructure:hydrogenatomrevisited
However,treatmentofhydrogenatominherentlynon-relativistic : ˆ H 0 = ˆp 2 2m - 1
4π?
0 Ze 2 r isonlythe leadingtermin relativistictreatment( Diractheory ). Suchrelativisticco rrectionsbegin toimpactwhentheelectron becomesrelativistic,i.e.v≂c. Since,for Coulombpotential,2?k.e.?=-?p.e.?(virialtheore m), 1 2 mv 2 =?k.e.?=-E 000 =Z 2
Ry.Usingidentit y,
Z 2 Ry= 1 2 mc 2 (Zα) 2 , α= e 2
4π?
0 1 ?c ? 1 137
whereαdenotesthefinestructureconstant ,we find v c =Zα.
The"real"hyd rogenatom: outline
Termsofhigherorder in
v c =Zαproviderelativisticco rrections whichleadto liftingof thedegeneracy . Thesecorrections (knownasfine-structure)derivefrom three (superficially)di ff erentsources: (a)relativisticcorrections tothekineticenergy; (b)couplingbet weenspinandorbitaldegreesoffreedom; (c)andacontribution knownas theDa rwinterm. (a)Relativisticco rrections tokineticenergy
Fromtherelativisticenergy-momentum invariant,
E= ? p 2 c 2 +m 2 c 4 =mc 2 + p 2 2m - 1 8 (p 2 ) 2 m 3 c 2 +···, wecananticipatetheleading correctionto thenon-relativistic
Hamiltonianisgiven by
ˆ H 1 =- 1 8 (ˆp 2 ) 2 m 3 c 2
Therelativescale ofperturbation
? ˆ H 1 ? ? ˆ H 0 ? ? p 2 m 2 c 2 = v 2 c 2 ?(Zα) 2 whereα= e 2
4π?0
1 ?c ? 1 137
. i.e. ˆ H 1 isonlya smallperturbation for smallatomicnumb er,Z. (a)Relativisticco rrections tokineticenergy ˆ H 1 =- 1 8 (ˆp 2 ) 2 m 3 c 2
Since[
ˆ H 1 , ˆ L 2 ]=0 and[ ˆ H 1 , ˆ L z ]=0, ?n?m|[ ˆ H 1 , ˆ L 2 ]|n? ? m ? ?=? 2 [? ? (? ? +1)-?(?+1)]?n?m| ˆ H 1 |n? ? m ? ?=0 ?n?m|[ ˆ H 1 , ˆ L z ]|n? ? m ? ?=?(m ? -m)?n?m| ˆ H 1 |n? ? m ? ?=0
Therefore,theo
ff -diagonalmatrixelem entsvanish: ?n?m| ˆ H 1 |n? ? m ? ?=0for??=? ? orm?=m ? andwe canestimateenergyshiftwithout havingtoinvok e degenerateperturbation theory. (a)Relativisticco rrections tokineticenergy
Makinguseof theidentit y,
ˆ H 1 =- 1 8 (ˆp 2 ) 2 m 3 c 2 =- 1 2mc 2 ? ˆ H 0 -V(r) ? 2 ,V(r)=- Ze 2
4π?
0 1 r scaleofresulting energyshift canbe obtainedfromfirst order perturbationtheory, ?n?m| ˆ H 1 |n?m?=- 1 2mc 2 ? E 2 n -2E n ?V(r)? n? +?V 2 (r)? n? ?
Usingtheidentities,
? 1 r ? n? = Z a 0 n 2 , ? 1 r 2 ? n? = Z 2 a 2 0 n 3 (?+1/2) . resultingenergyshift acquiresangula rmomentumdep endence: ? ˆ H 1 ? n?m =- mc 2 2 ? Zα n ? 4 ? n ?+1/2 - 3 4 ? (b)Spin-orbit coupling Spindegreeof freedomofelectron emergesnaturallyfrom relativisticformulation ofquantummechanics.Alongsidethe spin, thisform ulationleadstoafurtherrelativisticcorrection which involvescouplingb etw eenspinandorbitaldegreesoffreedom. ForageneralpotentialV(r),thisspin-o rbitcoupling isgivenby: ˆ H 2 = 1 2m 2 c 2 1 r (∂ r V) ˆ L· ˆ S
Forahydrogen-likeatom,V(r)=-
1
4π?0
Ze 2 r and ˆ H 2 = 1 2m 2 c 2 1
4π?
0 Ze 2 r 3 ˆ L· ˆ S (b)Spin-orbit coupling:physicalorigin Physically,aselectronmoves throughelectric fieldofnucle us,
E=-?V(r)=-ˆe
r (∂ r
V),inits restframeit willexp eriencea
magneticfield,B= 1 c 2 v×E. Inthisfield, thespinmagnetic momentofthe electron,µ s =- e m S, leadstoan additionalinteraction energy, -µ s
·B=-
e (mc) 2
S·(p׈e
r (∂ r V))= e (mc) 2 1 r (∂ r
V)L·S
wherewe haveusedtherelationp׈e r =- 1 r L. Additionalfactor of1/2derivesfrom furtherrelativistice ffect knownasThomasprecession . Thosediscontentwith heuristicderviationneed onlywait forDirac formulation... (b)Spin-orbit coupling ˆ H 2 = 1 2m 2 c 2 1
4π?
0 Ze 2 r 3 ˆ L· ˆ S Withoutspin-orbit interaction,eigenstatesofhydrogen-likeatoms canbe expressedinbasisofmutually commutingoperators, ˆ H 0 , ˆ L 2 , ˆ L z , ˆ S 2 ,and ˆ S z . However,withspin-orbit,totalHamiltoniannolongercommutes with ˆ L z or ˆ S z -usefulto exploitdegeneracy of ˆ H 0 toswitchto new basisinwhich ˆ L· ˆ
Sisdiagonal.
Achievedby turningtobasisofeigenstates oftheop erators, ˆ H 0 , ˆ J 2 , ˆ J z , ˆ L 2 ,and ˆ S 2 ,where ˆ J= ˆ L+ ˆ
S.Since
ˆ J 2 = ˆ L 2 + ˆ S 2 +2 ˆ L· ˆ S,it followsthat, ˆ L· ˆ S= 1 2 ( ˆ J 2 - ˆ L 2 - ˆ S 2 )= 1 2 (j(j+1)-?(?+1)-s(s+1)) (b)Spin-orbit coupling ˆ L· ˆ S= 1 2 ( ˆ J 2 - ˆ L 2 - ˆ S 2 )= 1 2 (j(j+1)-?(?+1)-s(s+1)) ˆ H 2 = 1 2m 2 c 2 1
4π?
0 Ze 2 r 3 ˆ L· ˆ S Combiningspin1 /2withangula rmomentum?,totalangula r momentumcantak evaluesj=?±1/2.Corresp ondingbasisstates |j=?±1/2,m j , ??diagonalizeoperato r, ˆ L· ˆ
S|j=?±1/2,m
j , ??= ? 2 2 ? ? -?-1 ? |?±1/2,m j , ??
Onceagain,o
ff -diagonalmatrixelements of ˆ H 2 vanishallowing correctiontobecomputed infirsto rderperturbationtheory. ?H 2 ? n,j=?±1/2,m j , ? = 1 2m 2 c 2 ? 2 2 ? ? -?-1 ? Ze 2
4π?
0 ? 1 r 3 ? n? (b)Spin-orbit coupling ?H 2 ? n,j=?±1/2,m j , ? = 1 2m 2 c 2 ? 2 2 ? ? -?-1 ? Ze 2
4π?
0 ? 1 r 3 ? n?
Makinguseof identity,
? 1 r 3 ? n? = ? mcαZ ?n ? 3 1 ?(?+1/2)(?+1) , ? >0 ? ˆ H 2 ? n,j=?±1/2,m j , ? = 1 4 mc 2 ? Zα n ? 4 n j+1/2 ? 1 j j=?+1/2 - 1 j+1 j=?-1/2
Rewritingexpression for?
ˆ H 1 ?innewbasis |n,j=?±1/2,m j , ??, ? ˆ H 1 ? n,j=?±1/2,m j , ? =- 1 2 mc 2 ? Zα n ? 4 n ? 1 j j=?+1/2 1 j+1 j=?-1/2 .
Combiningtheseexp ressions,for ?>0,we have
? ˆ H 1 + ˆ H 2 ? n,j=?±1/2,m j , ? = 1 2 mc 2 (Zα) 4 n 4 ? 3 4 - n j+1/2 ? whilefor ?=0,w eretainjust ? ˆ H 1 ? (c)Darwin term Finalrelativisticco rrectiona risesfrom"Zitterbewegung"of electron -giggling- whichsmea rse ff ectivepotential feltbyelectron, ˆ H 3 = ? 2 8m 2 c 2 ? 2 V= ? 2 8m 2 c 2 eQ nuclear (r) ? 0 = π? 2 2m 2 c 2 Ze 2
4π?
0 δ (3) (r)
Sinceperturbation actsonlyatorigin,it e
ff ectsonly?=0states, ? ˆ H 3 ? nj=1/2,m j ?=0 = π? 2 2m 2 c 2 Ze 2
4π?
0 |ψ n00 (0)| 2 = 1 2 mc 2 (Zα) 4 n 3 Thistermis formallyide nticalto thatwhichwouldbe obtained from? ˆ H 2 ?at?=0.As aresult,combining allthree contributions, ΔE n,j=?±1/2,m j , ? = 1 2 mc 2 ? αZ n ? 4 ? 3 4 - n j+1/2 ? independentof?andm j .
Spectroscopicnotation
Todiscussenergyshiftsfo rpa rticularstates, itishelpful to introducesomenomenclature fromatomicphysics. Forastatewithprincipalquantum number n,totalspin s,orbital angularmomentum?,andtotal angularmomentum j,onema y definethestate bythe spectroscopicnotation, n 2s+1 L j Forahydrogen-likeatom,withjust asingleelectron, 2s+1= 2.In thiscase,the factor 2s+1is oftenjustdropp edfo rbrevit y.
Relativisticcorrections
ΔE n,j=?±1/2,m j , ? = 1 2 mc 2 ? αZ n ? 4 ? 3 4 - n j+1/2 ?
Foragivenn,relativisticco rrectionsdep end
onlyonjandn.
Forn=1,?=0and j=1/2:Both1 S
1/2 states,withm j =±1/2,experience negative energyshiftof - 1 4 Z 4 α 2 Ry.
Forn=2,?=0,1:Withj=1/2,both 2S
1/2 and2P 1/2 stateshaveshift, - 5 64
Z 4 α 2 Ry, while2P 3/2 experiencesashift- 1 64
Z 4 α 2 Ry. (Further)relativisticcorrections:Lambshift Perturbativecorrections predictedbyDiractheorypredict that,for hydrogen,the2 S 1/2 and2P 1/2 statesshouldremain degenerate. However,in1951,anexperimentalstudyb yWillisLamb discovered that2P 1/2 stateisslightly lower thanthe 2S 1/2 state-Lamb shift.
Mightseemthat suchatiny e
ff ect wouldbeinsignificant,but shift providedconsiderable insightinto quantumelectrodynamics .
Lambshift
Withinframewo rkofquantumelectrodynamics,Coulomb
interactionismediated byexchange ofphotons- "gaugeparticles". Interactionofelectron withelectromagnetic fieldcaninduce a "self-interaction"?effectivesmearing ofelectronposition, ?(δr) 2 ?? 2α π ? ? mc ? 2 ln 1 αZ ,
δr≂10
-5 a 0 Causeselectronspin g-factortobeslightly differentfrom2. Thereisalso aslightw eakeningof theforce ontheelectron whenit isveryclose tothenucleus, causing2 S 1/2 statetob eslightlyhigher inenergythan the2 P 1/2 state. ΔE Lamb ? 1 2 mc 2 ? αZ n ? 4 n× ? 8 3π
αln
1 αZ ? δ ? ,0
Hyperfinestructure
Finally,weshouldaddress thepotentialinfluenc eofthe nuclear spin,I,whichleads toanuclea rmagnetic moment, M=g N e 2M N I wherenucleushas massM N andgyromagneticratio g N .
Sincenucleushas internalstructure, g
N isnotsimply 2.Fo rp roton, solenuclear constituentofatomichydrogen,g p ≈5.56.Even thoughneutronis chargeneutral, g n ≈-3.83.
Magneticmomentgenerates vectorp otentialA=-
µ0 4π
M×?(1/r)
andmagneticfield
B=?×A=
µ 0 4π ?
3r(r·M)-r
2 M r 5 + 8π 3 Mδ (3) (r) ?
Hyperfineinteraction
B=?×A=
µ 0 4π ?
3r(r·M)-r
2 M r 5 + 8π 3 Mδ (3) (r) ? Asaresult, weobtain hyperfineinteraction withorbitalandspin degreesoffreedom ofelect ron, ˆ H hyp = e 2m ( ˆ L+2 ˆ
S)·B
Energylevelshift oftheground statecanb eestimatedusing perturbationtheory.If weconsider(forsimplicity)justthe ?=0 states,onlylast terminBcontributesatlo westo rder,andleadsto ? ˆ H hyp ? n,1/2,0 = µ 0 4π g N e 2M N e m 8π 3 |ψ n00 (0)| 2 ˆ S· ˆ I/? 2
Hyperfineinteraction
? ˆ H hyp ? n,1/2,0 = µ 0 4π g N e 2M N e m 8π 3 |ψ n00 (0)| 2 ˆ S· ˆ I/? 2
With|ψ
n00 (0)| 2 = 1 πn 3 (
Zαmc
? ) 3 ,we obtain ? ˆ H hyp ? n,1/2,0 = 1 2 mc 2 ? Zα n ? 4 n× 8 3 g N m M N ˆ S· ˆ I/? 2 showingscaleofperturbation suppressed overfines tructureby factorm/M N ≂10 -3 . Finally,aswithspin-orbit interaction,ifw esetF=I+S, 1 ? 2
S·I=
1 2? 2 (F 2 -S 2 -I 2 )= 1 2 (F(F+1)-3/4-I(I+1)) = 1 2 ?
IF=I+1/2
-I-1F=I-1/2
Summaryofatomicenergyscales
Grossstructure:Dictatedby
orbitalkineticandpotential energies,ca.1 -10eV.
Finestructure:Relativistic
corrections(spin-orbit,etc.) splitdegeneratemultiplets leadingtosmall shiftin energy, ca.10 -4 -10 -5 eV.
Hyperfinestructure:
Interactionofelectron
magneticmomentwith field generatedby nuclearspinleads tofurthersplitting of multiplets,ca.10 -7 -10 -8 eV
Lecture13-14
Multi-electronatoms
Background
Howcanwedetermine energyleve lsofamulti-electron atom? Wecouldstartwith hydrogenicenergylevels foratomofnuclear chargeZ,andsta rtfillingelectrons fromlowestlevels, accounting forPauliexclusion. Degeneracyfor quantumnumbers(n,?)is2 ×(2?+1).Each energylevel,n,accommodates 2×n 2 electrons: n?Degeneracyinshell Cumulativetotal 102 2
20,1(1+ 3)×2=8 10
30,1,2(1+ 3+5) ×2=18 28
40,1,2,3(1+ 3+5 +7) ×2=32 60
Expectatomscontaining2,10, 28o r60electrons wouldb e especiallystableandthat, inatomscontaining onemore electron, outermostelectro nwouldbelesstightly bound.
Background:ionizationener giesof elements
Instead,findnoble gases( Z=2,10, 18,36···)are especially stable,andelements containingonemo reelectron(alk alimetals) significantlylesstightly bound.
Background
Failuretopredict stableelectronconfigurationsreflects omissionof electron-electroninte raction(cf.ourdiscussion ofhelium). Infact,first ionizationenergiesof atomsshow onlyaw eak dependenceonZ-outermostelectrons are almostcompletely shieldedfromnuclear charge: E ff ectivenuclea rchargevariesasZ e ff ≂(1+γ) Z whereγ>0 characterizes"ine ff ectivenessofs creening";i.e.ionization energy I Z =-E Z ≂Z 2 e ff ≂(1+2 γZ)(cf.exp eriment).
Multi-electronatoms
Leavingaside(fo rno w)relativistice
ff ects,Hamiltonianfo r multi-electronatomgiven by ˆ H= ? i ? - ? 2 2m ? 2 i - 1
4π?
0 Ze 2 r i ? + ? i
4π? 0 e 2 r ij wherer ij ≡ |r i -r j |. Inadditionto nuclearbinding potential,there isafurtherCoulomb interactionbet weenelectrons. Aswe haveseenwithhelium,thiscontribution canhaveimp ortant consequencesonsp ectraandspin structureofwavefunction. However,electron-electroninteractionmakesproblem"many-bo dy" incharacter andanalyticallyintractable-we must developsome approximationscheme(eventhoughe ff ectsmay notbesmall!). Multi-electronatoms: outline
Centralfieldapp roximation
Self-consistentfieldmetho d- Hartreeapproximation
Structureofthe perio dictable
Couplingschemes:
1 LScouplingand Hund'srules
2 jjcoupling Atomicspectra:selectionrules
Zeemane
ff ectrevisited Centralfieldapp roximation
Electroninteractioncontains larges pherically symmetriccomponent arisingfrom"coreelect rons".Since ? ? m=-? |Y lm (θ,φ)| 2 =const. closedshellhassphericallysymmetric chargedistribution. Thissuggestsa "partitioning"of theHamiltonian,
ˆ H= ˆ H 0 + ˆ H 1 , with ˆ H 0 = ? i ? - ? 2 2m ? 2 i - 1 4π?
0 Ze 2 r i +U i (r i ) ? ˆ H 1 = ? i4π? 0 e 2 r ij - ? i U i (r i ) wheretheradially-symmetric "single-electronp otentials",U i (r), accommodate"averagee ff ect"ofother electrons,i.e. ˆ H 1 issmall. Centralfieldapp roximation
ˆ H 0 = ? i ? - ? 2 2m ? 2 i - 1 4π?
0 Ze 2 r i +U i (r i ) ? ˆ H 1 = ? i4π? 0 e 2 r ij - ? i U i (r i ) Sincesingle-part icleHamiltonian
ˆ H 0 continuestocommute withthe angularmomentumoperator, [ ˆ H 0 , ˆ L]=0, itseigenfunctionsre main
indexedby quantumnumbers(n,?,m ? ,m s ). However,sincee
ff ectivepotential, V(r)+U i (r),isno longer Coulomb-like,?valuesfor agivennneednotb edegenerate. Buthow dowefixU
i (r);thep otentialenergyexp eriencedbyeach electrondepends onthewavefunctionofall theotherelectrons, whichisonly knownafter theSchr¨ odingerequationhasbeensolved. Thissuggestsan iterativeapproach tosolvingthe problem. Self-consistentfield method
Beforeembarkingonthis programme,weshould
firstconsiderour ambitions: Thedevelopmentof computationschemes to
addressquantummechanics ofmany-pa rticle systemsisa specialist (andchallenging)topic commontophysics andchemis try. Ourinteresthere ismerely intheoutcomeofsuchinvestigations, andtheirramifi cationsfo ratomicphysics. Wewillthereforediscuss (general)p rinciplesofthemethodology, butthedetailed technicalaspects ofthe approachneed notbe committedtomemo ry! Self-consistentfield method
Tounderstandhowthe potentialsU
i (r)canb eestimated,w ewill followavariationalapproach duetoHartree: Ifelectronsa re(for now)considereddistinguishable,w avefunction canbe factorizedinto(normalized) productstate, Ψ ({r i })=ψ i1 (r 1 )ψ i2 (r 2 )···ψ i N (r N ) wherethequantum numbers, i≡n?m ? m s ,indexindividual state occupancies. Notethat
Ψ ({r i })isnot aprop erlyantisymmetrized Slater determinant-exclusion principletak enintoaccount onlyinsofar thatwe haveassigneddi ff erentquantumnumb ers,n?m ? m s . Inthisapp roximation,if U
i (r)=0, thegroundstate would involve fillingthelo westshells withelectrons. Self-consistentfield method
Ψ ({r i })=ψ i1 (r 1 )ψ i2 (r 2 )···ψ i N (r N ) Variationalgroundstateenergy:
E=?Ψ|
ˆ H|Ψ?=
? i ? d 3 rψ ? i ? - ? 2 ? 2 2m - 1 4π?
0 Ze 2 r ? ψ i + 1 4π?
0 ? iLatterimposed bysetofLagrange multipliers,ε i , δ δψ
? i ? E-ε
i ?? d 3 r|ψ i (r)| 2 -1 ?? =0 Self-consistentfield method
δ δψ
? i ? E-ε
i ?? d 3 r|ψ i (r)| 2 -1 ?? =0 Followingvariation,obtainHartreeequations,
? - ? 2 ? 2 2m - 1 4π?
0 Ze 2 r ? ψ i + 1 4π?
0 ? j?=i ? d 3 r ? |ψ j (r ? )| 2 e 2 |r-r ? | ψ i (r) =ε i ψ i (r) Amongstallp ossibletrialfunctions ψ
i ,setthat minimizesene rgy determinedby e ff ectivepotential, U i (r)= 1 4π?
0 ? j?=i ? d 3 r ? |ψ j (r ? )| 2 e 2 |r-r ? | Tosimplifyprocedure, usefultoengineer radialsymmetryby replacingU i (r)by sphericalaverage,U i (r)= ? dΩ 4π U i (r). Self-consistentfield method
? - ? 2 ? 2 2m - 1 4π?
0 Ze 2 r ? ψ i + 1 4π?
0 ? j?=i ? d 3 r ? |ψ j (r ? )| 2 e 2 |r-r ? | ψ i (r) =ε i ψ i (r) TofixLagrangemultipliers ,ε
i ,we canmultiplyHartreeequations byψ ? i (r)andintegrate, ? i = ? d 3 rψ ? i ? - ? 2 ? 2 2m - 1 4π?
0 Ze 2 r ? ψ i + 1 4π?
0 ? j?=i ? d 3 r ? d 3 r|ψ j (r ? )| 2 e 2 |r-r ? | |ψ i (r)| 2 Fromthisresult,we find
E= ? i ? i - 1 4π?
0 ? iSelf-consistentfield method Insummary ,withintheHartreeframework, themulti-electron Hamiltonianisreplaced by thee
ff ectivesingle-particle Hamiltonian, ˆ H 0 = ? i ? - ? 2 2m ? 2 i - 1 4π?
0 Ze 2 r i +U i (r i ) ? wherethecentral potentials U i dependself-consistentlyonthe single-particlewavefunctions, U i (r)= ? dΩ 4π 1 4π?
0 ? j?=i ? d 3 r ? |ψ j (r ? )| 2 e 2 |r-r ? | OnceU i sare found,perturbationtheory canbe appliedtoresidual Coulombinteraction,
ˆ H 1 = ? i4π? 0 e 2 r ij - ? i U i (r i ) Hartree-Fockmethod
Animprove mentonthisprocedurecanb eachievedb yintro ducting atrialva riationalstatew avefunctioninvolving aSlaterdeterminant, Ψ = 1 ⎷ N! ? ? ? ? ? ? ? ? ? ψ 1 (r 1 )ψ 1 (r 2 )ψ 1 (r 3 )··· ψ 2 (r 1 )ψ 2 (r 2 )ψ 2 (r 3 )··· ψ 3 (r 1 )ψ 3 (r 2 )ψ 3 (r 3 )··· . . . . . . . . . . . . ? ? ? ? ? ? ? ? ? whereψ k (r i ),withi=1,2···N,denotethe single-particle wavefunctionsforelectroni,andk=(n?m ? m s ) Avariational analysisleadstoHartree-Fockequationswith additionalexchangecontribution, ε i ψ i (r)= ? - ? 2 2m ? 2 i - 1 4π?
0 Ze 2 r i ? ψ i (r) + ? j?=i ? d 3 r ? j 1 4π?
0 e 2 |r-r ? | ψ ? j (r ? ) ? ψ j (r ? )ψ i (r)-ψ j (r)ψ i (r ? )δ ms i ,ms j ? Centralfieldapp roximation: conclusions
Althoughstatescha racterizedby quantumnumbersn?m
? m s , Hartree-Fockcalculationsshowthatthosewithdi
ff erent?forgiven narenownon-degenerate- large?valuesmore effectivelyscreened andliehighe rin energy. Statescorresp ondingtoparticularnreferredtoas ashell,andthose belongington,?areasubshell.Energylevels ordered as Subshellname1 s2s2p3s3p4s3d4p5s4d···
n=12 233 43 454 ··· ?=00 101 02 102 ··· Degeneracy22 62 6210 6210 ···
Cumulative24 101218 203036 3848···
Centralfieldapp roximation: conclusions
Subshellname1 s2s2p3s3p4s3d4p5s4d···
Cumulative24 101218 203036 3848···
7s 6s 5s 4s 3s 2s 1s 7p 6p 5p 4p 3p 2p 7d 6d 5d 4d 3d ···
6f 5f 4f ···
5g ? ? ?? ? ? ? ?? ? ? ? ?? ? ? ? ? ?? ? ? ? ? ? ?? ? ? ? ? ? ? ?? ? ? ? ? ? ? ?? ? ? ? ? ? ? ? ?? Periodictable
Canuseenergy sequenceto
predictgroundstateelectron configuration-fill levels accountingfor exclusion aufbauprinciple . Sadly,thereareexceptions to
rule:e.g.Cu (Z=29) expectedtohaveconfiguration (Ar)(4s) 2 (3d) 9 ,actuallyhas (Ar)(4s) 1 (3d) 10 . 1H(1s)13.6
2He(1s)
2 24.6
3LiHe(2s)5.4
4BeHe(2s)
2 9.3 5BHe(2s)
2 (2p)8.3 6CHe(2s)
2 (2p) 2 11.3 7NHe(2s)
2 (2p) 3 14.5 8OHe(2s)
2 (2p) 4 13.6 9FHe(2s)
2 (2p) 5 17.4 10NeHe(2s)
2 (2p) 6 21.6
11NaNe(3s)5.1
12MgNe(3s)
2 7.6 14SiNe(3s)
2 (3p) 2 8.1 16SNe(3s)
2 (3p) 4 10.4 18ArNe(3s)
2 (3p) 6 15.8 19KAr(4s)4.3
Periodictable
Aufbauprinciple formsbasisofPeriodictableofelements: elementswith similarelectronconfigurationsin outermostshells havesimilar chemicalproperties. Couplingschemes
Theaufbaup rinciplep redictsgroundstateoccupationof subshells- butdoes notspecifyspinand orbitalangula rmomentaofsubshells. Todealwiththisquestion, we mustconsiderspin-o rbitandresidual Coulombinteractionb etween outerelectrons.
Hamiltonianfor multi-electronatomcanbewritten as,
ˆ H≈
ˆ H 0 + ? i4π? 0 e 2 r ij - ? i U i (r) ???? ˆ H 1 + ? i ξ i (r i ) ˆ L i · ˆ S i ???? ˆ H 2 where ˆ H 0 includescentralfield terms, ˆ H 1 isresidualCoulomb interaction,and ˆ H 2 isspin-orbit interaction. Couplingschemes
ˆ H≈
ˆ H 0 + ? i4π? 0 e 2 r ij - ? i U i (r) ???? ˆ H 1 + ? i ξ i (r i ) ˆ L i · ˆ S i ???? ˆ H 2 Forlightatoms,
ˆ H 1 ? ˆ H 2 ,cantreat ˆ H 2 asap erturbationon ˆ H 0 + ˆ H 1 -known asLS(orRussell-Saunders)coupling. Forheavyatoms(orionizedlight atoms),
ˆ H 2 ? ˆ H 1 ,electrons becomerelativisticandspin-orbit interactiondominates- jj coupling. Bothscenarios areapproximations -realatomsdonotalw aysconformto this"comparatively simple"picture. Couplingschemes:LS coupling
ˆ H≈
ˆ H 0 + ? i4π? 0 e 2 r ij - ? i U i (r) ???? ˆ H 1 + ? i ξ i (r i ) ˆ L i · ˆ S i ???? ˆ H 2 Since ˆ Hcommuteswith setoftotalangular momenta,
ˆ J 2 , ˆ L 2 ,and ˆ S 2 ,energylevels ofmulti-electron atomsa recharacterized by quantumnumbers L,S,J. Theirordering inenergysetbyHund'srules.
Asrulesempirical, thereare exceptions.Moreover, asatomicmass increasesandelectrons becomerelativistic, spin-orbitinteractions becomeincreasinglyimportant furtherunderminingrules. Couplingschemes:LS couplingand Hund'srules
ˆ H≈
ˆ H 0 + ? i4π? 0 e 2 r ij - ? i U i (r) ???? ˆ H 1 + ? i ξ i (r i ) ˆ L i · ˆ S i ???? ˆ H 2 1 Combinespinsto obtainp ossiblevaluesof totalspinS.(Remember thatclosedshells contributezerospin.) Thelargest permittedvalueofSlieslow estinenergy.
Physically:maximisingSmakesspinwavefunctionas symmetricas possible:tendstomake spatialwavefunction antisymmetric,reduces Coulombrepulsion(cf. helium).
Couplingschemes:LS couplingand Hund'srules
ˆ H≈
ˆ H 0 + ? i4π? 0 e 2 r ij - ? i U i (r) ???? ˆ H 1 + ? i ξ i (r i ) ˆ L i · ˆ S i ???? ˆ H 2 2 ForeachvalueofS,findthe possiblevalues oftotal angular momentumL.(Rememb erthatclosedshellscontributezeroorbital angularmomentum.) Thelargest permittedvalueofLlieslow estinenergy.
Physically:maximisingLalsotendsto keepthe electronsapa rt. Indecidingon permitted valuesofLandS,we alsohavetoensure thatboth quantumstatisticsandtheexclusion principleis respected, i.e.totalelectron wavefunction mustbe antisymmetricunder particleexchange. Couplingschemes:LS couplingand Hund'srules
ˆ H≈
ˆ H 0 + ? i4π? 0 e 2 r ij - ? i U i (r) ???? ˆ H 1 + ? i ξ i (r i ) ˆ L i · ˆ S i ???? ˆ H 2 3 CoupleLandStoobtainvalue sof J(hencenameof scheme). (Rememberthatclosedshells contributezeroangula rmomentum.) Ifsubshellis lessthanhalf full,smallestvalue ofJlieslow est inenergy;otherwise, largest valuelieslo west. Energyseparation fordi
ff erentJarisesfromtreatingspin-orbit term asap erturbation(finestructure), ?Jm J LS| ? i ξ i (r i ) ˆ L i · ˆ S i |Jm J LS?=ζ(L,S)?Jm
J LS| ˆ L· ˆ S|Jm J LS? =ζ(L,S)[J(J+1)-L(L+1)-S(S+1)]/2 Sincesignof ζ(L,S)changesacco rdingto thewhetherthesubshell ismore orlessthanhalf-filled, thethirdHund'sruleis established. LScoupling- Example:helium
Heliumhasground stateelectronconfiguration
(1s) 2 ,i.e.L=S=J=0. N.B.Fo ranycompletelyfilledsubshell,
L=S=0and henceJ=0.
Forexcitedstate,e.g.(1s)
1 (2p) 1 ,canhave S=1o rS=0,with S=1state lyinglow erin energyaccording toHund'srules. Combiningorbital angularmomentagivesL=1and, withS=0, J=1,while withS=1,J=0,1,2withJ=0lo westin energy.
Inspectroscopic notation
2S+1 L J ,fourp ossiblestates, 3 P 0 3 P 1 3 P 2 and 1 P 1 wherethree 3 Pstatessepa ratedby spin-orbitinteraction,
andsinglet 1 Pstatelies muchhigherin energydue toCoulomb.
Land´eintervalrule
Sinceseparation ofenergiesforstatesof di
ff erentJarisesfrom spin-orbittermcontribution ˆ H 2 (finestructure), ? |J,m J ,L,S| ? i ξ i (r i ) ˆ L i · ˆ S i |J,m J ,L,S? = ζ(L,S)
2 [J(J+1)-L(L+1)-S(S+1)] separationbetween pairofadjacentlevelsinafinestructure multipletisp ropo rtionaltolargeroftwoJvalues, Δ J ?J(J+1)-(J-1)J=2J e.g.sepa rationbetween 3 P 2 and 3 P 1 ,and 3 P 1 and 3 P 0 shouldbe in ratio2:1. LScoupling- Example:ca rbon
Carbonhasgroundstateelectronconfiguration
(1s) 2 (2s) 2 (2p) 2 . Withtw oidenticalelectronsinsame unfilled
subshell,wavefunc tionmustbeantisymmetric. Totalspincaneither be singletS=0(antisymmetric) orone ofthe tripletS=1states (symmetric). Toformantisymmetrictotalangular
momentumstate ,twoelectronsmust havedi ff erentvaluesof m ? Inspectingthevaluesofm
L wecan deducethatL=1. m (1) ? m (2) ? m L 101
1-10 0-1-1 Toformsymmetrictotalangular
momentumstate ,twoelectronsmay haveanyvalues ofm ? Inspectingthevaluesof m
L weinfer thatL=2o r0. m (1) ? m (2) ? m L 112
101
1-10 000 0-1-1 -1-1-2 LScoupling- Example:ca rbon
Carbonhasgroundstateelectronconfiguration
(1s) 2 (2s) 2 (2p) 2 . Withtw oidenticalelectronsinsame unfilled
subshell,wavefunc tionmustbeantisymmetric. Toensureantisymmetryofw avefunction,w emusttherefo retake S=1with L=1and S=0with L=2o r0.
Toaccountforfine structure,state swithS=1and L=1can be combinedintosingle J=0state, threeJ=1states, andfiveJ=2 statesleadingto terms 3 P 0 , 3 P 1 ,and 3 P 2 respectively. SimilarlytheS=0,L=2state canb ecombined togivefiveJ=2 states, 1 D 2 ,whileS=0,L=0state givessingle J=0state, 1 S 0 . LScoupling- Example:ca rbon
Measuredenergylevels:
E/cm -1 1 S 0 20649
1 D 2 10195
3 P 2 43
3 P 1 16 3 P 0 0 Land´eintervalruleapproximatelyob eyedb y
finestructuretriplet, andseparation betw een LandSvaluescausedb yCoulomb repulsion
ismuchgreaterthanspin-o rbite ffect. LScoupling- Example:ca rbon
Forexcitedstatesofcarbon, e.g.(2 p)
1 (3p) 1 ,electronsa reno longerequivalentb ecausethey havedi ff erentradialw avefunctions. Wecannowcombine anyof S=0,1withany ofL=0,1,2,
yieldingthefollo wingterms (inorderofincreasingenergy ,according toHund'srules): 3 D 1,2,3 3 P 0,1,2 3 S 1 1 D 2 1 P 1 1 S 0 Recap:atomicstructure
Ourstudiesof theenergy spectrum ofatomichydroge nusingthe non-relativisticSchr¨ odingerequationshow edthatstatesare organisedinashellstructure, indexedb yap rinciplequantum numbernandcharacterise dbyann 2 -folddegeneracy. Toaddresstheelectronicstructure ofmultielectronatoms, wehave toaccommodate twoclassesofadditional e ff ects: 1 Evenhydrogenic(i.e. single-electron)atoms aresubjec tto correctionsfromrelativistice ff ects(spin-orbitcoupling,etc.) - finestructure,vacuumfluctuations ofEMfield -Lambshift , andinteractionwith nuclear spin-hyperfinestructurewhich togetherconspireto liftstate degeneracy. 2 Inaddition,in multielectronatoms, thedirectCoulomb interactionbet weenelectronsleadtoscreeningofthenuclear charge,andrearrangethe orderingof theshellstructure. Recap:atomicstructure
Althoughelectron-electroninteractions make themultielectron systemformally intractable,thesphericalsymmetryoffilled core electronstatesjustifies centralfieldapp roximation inwhichthe principlee ff ectofinteractions iscapturedb yasingle-pa rticle potential, ˆ H 0 = ? i ? - ? 2 ? 2 i 2m - Ze 2 4π?
0 r i +U i (r i ) ? , ˆ H 1 = ? i4π? 0 r ij - ? i U i (r i ) Numericalstudies(based onself-consistent Hartree-Fo ckscheme) provideasimplephenomenologyto describeenergy orderingof core subshells-aufbauprinciple Influenceofresidual electroninteraction,
ˆ H 1 ,andrelativistic spin-orbitcorrections ˆ H 2 = ? i ξ(r
i ) ˆ L i · ˆ S i onvalencestates canthen beaddressed withinperturbation theory. Recap:atomicstructure
ˆ H≈
ˆ H 0 + ? i4π? 0 e 2 r ij - ? i U i (r) ???? ˆ H 1 + ? i ξ i (r i ) ˆ L i · ˆ S i ???? ˆ H 2 Forlightatoms,
ˆ H 1 ? ˆ H 2 ,cantreat ˆ H 2 asap erturbationon ˆ H 0 + ˆ H 1 -known asLS(orRussell-Saunders)coupling. Forheavyatoms(orionizedlight atoms),
ˆ H 2 ? ˆ H 1 ,electrons becomerelativisticandspin-orbit interactiondominates- jj coupling. Recap:atomicstructure
ˆ H≈
ˆ H 0 + ? i4π? 0 e 2 r ij - ? i U i (r) ???? ˆ H 1 + ? i ξ i (r i ) ˆ L i · ˆ S i ???? ˆ H 2 InLScoupling, thegroundstate electronconfigureis specifiedb y anemperical setofrulesknownas Hund'srules.Subjectto Pauli exclusion: 1 Thelarges tpermittedvalueoftotalSlieslow estinenergy. 2 Thelarges tpermittedvalueoftotalLlieslow estinenergy. 3 Ifsubshellis lessthan halffull,smallest valueoftotal Jlies lowestinenergy;otherwiselargestvaluelies lowest. LScoupling- Example:nitrogen
Nitrogenhasground stateelectron
configuration(1s) 2 (2s) 2 (2p) 3 . Themaximalvalue ofspinis S=3/2
whileLcantake values3,2,1and 0. Sincespinw avefunction(being maximal)issymmetric,spatial wavefunctionmustbe antisymmetric-allthreestate swith m ? =1,0,-1mustb einvolved. Wemustthereforehave L=0and J=3/2withthe term,
4 S 3/2 . jjcouplingscheme ˆ H≈
ˆ H 0 + ? i4π? 0 e 2 r ij - ? i U i (r) ???? ˆ H 1 + ? i ξ i (r i ) ˆ L i · ˆ S i ???? ˆ H 2 Whenrelativistice
ff ectsdominatere sidualelectrostaticinteraction, ˆ H 1 ,(i.e.heavy elements)electronsmove independently incentral field,subjectto spin-orbit interaction. Inthislimit,statesare both eigenstatesof ˆ J 2 (asbefo re),andalsoof ˆ J 2 i foreachelectron. Injjcoupling,separate energyshiftsindependentof totalJandM J , ΔE=?n
i ? i s i j i Jm J | ? i ξ(r
i ) ˆ L i · ˆ S i |n i ? i s i j i Jm J ?= ? i ΔE i where ΔE i =ζ(n i , ? i )[j i (j i +1)-? i (? i +1)-s i (s i +1)]/2 Thedegeneracywith respectto Jisthenlifted bythe small electrostaticinteractionb etw eenelectrons, ˆ H 1 . jjcouplingscheme:Example Considerconfiguration( np)
2 (cf.ca rboninLSscheme):Combining s=1/2with?=1,each electroncan havej=1/2or 3/2. Ifelectronshave samejvalue,theya reequivalent,so wehaveto takecareofsymm etry: (a)j 1 =j 2 =3/2?J=3,2,1,0,ofwhich J=2,0are antisymmetric. (b)j 1 =j 2 =1/2?J=1,0,ofwhich J=0is antisymmetric. (c)j 1 =1/2,j 2 =3/2?J=2,1. TakingintoaccountPauli exclusion,injjcoupling(wherethe term iswritten( j 1 ,j 2 ) J ),we havethefollowingterms: (1/2,1/2) 0 (3/2,1/2) 1 (3/2,1/2) 2 (3/2,3/2) 2 (3/2,3/2) 0 inorder ofincreasingenergy. jjcouplingscheme:Example (1/2,1/2) 0 (3/2,1/2) 1 (3/2,1/2) 2 (3/2,3/2) 2 (3/2,3/2) 0 BothLSand jjcouplinggivesame Jvalues(tw ostateswithJ=0, twowithJ=2and onewithJ=1)and insameo rder. However,patternoflevelsdi
ff erent:inLS couplingwe foundatriplet( 3 P 0 , 3 P 1 , 3 P 2 )and twosinglets( 1 D 2 and 1 S 0 ),whilein idealjj scenario,wehave twodoubletsanda singlet. Thesetsof statesint woschemes mustbe
expressibleaslinear combinationsof oneanother, andphysicalstates forreal atomlik elytodi ff er fromeitherapp roximation -e.g.jjcouplingnot seeninPb(6 p) 2 butisseen inCr 18+ whichhas sameconfigurationas carbon, (2p) 2 . Atomicspectra
Atomicspectraresultfrom transitionsbetween di
ff erentelectronic statesofan atomviaemission or absorptionof photons. Inemissionspectra ,atomis excitedby somem eans(e.g. thermallythroughcollisions), andoneobse rvesdiscrete spectral linesinlight emittedasatoms relax. Inabsorptionspectra,oneilluminates atomsusinga broad wavebandsource,andobserves darkabsorptionlinesin the spectrumoftransmittedlight. Atomsexcitedinthisp rocess subsequentlydeca yby emitting photonsinrandom directions- fluorescence. Atomicspectra:selectionrules
Basictheory governingemissionandabsorption willbe outlinedindetail whenwe studyradiativetransitions.Herewe anticipatesomeresults: Inelectricdipole approximation,rateof transitionsisp ropo rtional tomatrixelements ofelectric dipoleop erator, ˆ d=-e ? i r i , Γ?ω
3 | ?ψ f | ˆ d|ψ i ? | 2 , ω=|E
f -E i | Formofdipoleoperator,
ˆ dmeansthatsome matrixe lementsvanish ?selectionrules.Fo ratransitiontotakeplace: 1 Paritymustchange
2 ΔJ=±1,0(but0 →0isnot allowed) andΔM
J =±1,0 Atomicstatesalways eigenstatesofpa rityand
ˆ J 2 ,soselection rules canbe regardedasabsolutelyvalid inelectricdipoletransitions. Atomicspectra:selectionrules
Inspecific couplingschemes,furtherselectionrulesapply .Inthe caseofideal LScoupling,w ealsorequire: 1 ΔS=0and ΔM
S =0 Followsfromconservationoftotalspinin transition.
2 ΔL=±1,0(but0 →0isnot allowed) andΔM
L =±1,0 Followsfrom1.andrulesrelatingtoJ.
3 Δ? i =±1ifonly electroniisinvolvedin transition. Followsfromparitychange rulesinc etheparityofatomis productofparitiesofseparate electronwavefunctions, (-1) ? i . However,sinceLScouplingisonlyanappro ximation,theserules shouldthemselvesb eregarded asapproximate. Atomicspectra:singleelectron atoms
For"singleelectronatoms",e.g.alkalimetalssuchassodium, andalsohy drogen,ground stateis(ns) 1 . Groundstatehas term
2 S 1/2 whileexcited states alldoubletswith J=L±1/2(exceptfo rsstates whichhaveJ=1/2). Sinceparit ygivenby(-1)
? ,allow edtransitions involve Δ?=±1,i.e.s↔p,p↔d,etc.(La rger
changesin?contraveneΔJrule.) Thes↔ptransitionsare alldoublets.In
sodium,transition3s↔3pgivesriseto familiar yellowsodium"D-lines"at589 nm. Atomicspectra:singleelectron atoms
p↔dtransitionsinvolvet wo doublets, 2 P 1/2,3/2
and 2 D 3/2,5/2
.How ever,the 2 P 1/2 ↔ 2 D 5/2 transitionforbidden by ΔJ rule,soline isactually atriplet. Asnincreases,levelsapp roachthose for
hydrogen,asnuc lear chargeisincreasingly screenedby innerelectrons. Inanabso rptionspectrum, atomsstart
fromgroundstate, soonlyns→n ? plines seen.Inemission, atomsa reexcitedinto essentiallyalltheir excitedlevels, somany morelineswillbe seen inthes pectrum. Zeemaneffect:revisited
Toconcludesurveyofatomic structure,w enow returntoconsider how atomicspectra areinfluencedbya magneticfield? Beginwithhydrogen-lik eatomsinvolving justasingleelectron.Ina magneticfield, ˆ H= ˆ H 0 + ˆ H rel. + ˆ H Zeeman
,where ˆ H Zeeman
=- e 2mc B( ˆ L z +2 ˆ S z )=-µ B B( ˆ L z +2 ˆ S z )/? denotesZeeman term. Sincewe aredealingwithconfinedelec trons,wehaveneglected the diamagneticcontributionto theHamiltonian. Dependingonscaleofmagnetic field,the spin-orbitterm in ˆ H rel. or theZeemanterm maydominate thespectrum oftheatom. Zeemaneffect:revisited
ˆ H Zeeman
=- e 2mc B( ˆ L z +2 ˆ S z )=-µ B B( ˆ L z +2 ˆ S z )/? Previouslywe haveseenthat,toleadingo rder,relativistic correctionsleadtofine-structureenergy shift, ΔE rel. n,j = 1 2 mc 2 ? Zα n ? 4 ? 3 4 - n j+1/2 ? forstates|n,j=?±1/2,m j , ??. Forweakmagneticfields,we canalsotreatZeemanenergyin frameworkofperturbationtheory: Althoughstateswith commonj(e.g.2S
1/2 and2P 1/2 )are degenerate,spatialw avefunctionshavedi ff erentparity,and o ff -diagonalmatrixelements of ˆ H Zeeman
vanish-avoids needfor degenerateperturbation theory. Zeemaneffect:revisited
ˆ H Zeeman
=- e 2mc B( ˆ L z +2 ˆ S z )=-µ B B( ˆ L z +2 ˆ S z )/?=-µ B B( ˆ J z + ˆ S z )/? Makinguseof identity, (exercise-refer backtoadditionofangular momentumandspin) ?n,j=?±1/2,m j , ?| ˆ S z |n,j=?±1/2,m j , ??=± ?m j 2?+1 weobtainthefollowing expressionfo rthefirst orderenergyshift, ΔE Zeeman
j=?±1,m j , ? =?±1/2,m j , ??=µ B Bm j ? 1± 1 2?+1 ? i.e.alldegenerate levelssplitb yfield. Incontrastto the"no rmal"Zeeman e
ff ect,themagnitude ofthe splittingnow dependson?. Zeemaneffect:revisited
ˆ H Zeeman
=- e 2mc B( ˆ L z +2 ˆ S z )=-µ B B( ˆ L z +2 ˆ S z )/?=-µ B B( ˆ J z + ˆ S z )/? Formulti-electronatominweak field,unperturbedstates givenby |J,M J ,L,S?,whereJ,L,Srefertototal angular momenta. TodetermineZeemanshift, needtodetermine ?
ˆ S z ?,pre sentingan opportunityutoreviseangularmomenta: 1 Firstwe notethattheoperato r2
ˆ L· ˆ S= ˆ J 2 - ˆ L 2 - ˆ S 2 isdiagonalin thebasisof states,|J,M J ,L,S?. 2 Therefore,recallingthat[
ˆ S i , ˆ S j ]=i?? ijk ˆ S k and[ ˆ L i , ˆ S k ]=0, it followsthatthematrixelement ofthefollo wingoperato rvanishes, ˆ S( ˆ L· ˆ S)-( ˆ L· ˆ S) ˆ S= ˆ L j [ ˆ S i , ˆ S j ]=i?? ijk ˆ L j ˆ S k ≡-i? ˆ S× ˆ L Zeemaneffect:revisited
-i? ˆ S× ˆ L≡
ˆ S( ˆ L· ˆ S)-( ˆ L· ˆ S) ˆ S 3 Moreover,since[
ˆ L· ˆ S, ˆ J]=0, itfollows thatthe matrixelementof
thefollow ingoperatoralsovanishes, -i?( ˆ S× ˆ L)×
ˆ J= ˆ S× ˆ J( ˆ L· ˆ S)-( ˆ L· ˆ S) ˆ S× ˆ J 4 Ifwe expandlefthandside,we thusfind thatthematrix elementof thefollow ingoperatoralsovanishes, ( ˆ S× ˆ L)×
ˆ J= ˆ L( ˆ S· ˆ J)- ˆ S( ˆ L· ˆ J) ˆ L= ˆ J- ˆ S = ˆ J( ˆ S· ˆ J)- ˆ S ˆ J 2 5 Therefore,itfollowsthat ?
ˆ S ˆ J 2 ?=? ˆ J( ˆ S· ˆ J)?.With
ˆ S· ˆ J= 1 2 ( ˆ J 2 + ˆ S 2 - ˆ L 2 ),we have? ˆ S z ?? ˆ J 2 ?=? ˆ J z ?? ˆ S· ˆ J?,i.e.
? ˆ S z ?=? ˆ J z ? J(J+1)+ S(S+1)-L(L+1)
2J(J+1)
Zeemaneffect:revisited
? ˆ S z ?=? ˆ J z ? J(J+1)+ S(S+1)-L(L+1)
2J(J+1)
Asaresult, wecan deducethat,at firstorderinperturbation theory,theenergyshiftarising fromtheZeem antermis givenby ΔE J,M J ,L,S =µ B B?( ˆ J z + ˆ S z )?/?=µ B g J M J B wheree ff ectiveLand´eg-factor g J =1+ J(J+1)+ S(S+1)-L(L+1)
2J(J+1)
N.B.for hydrogen(S=1/2andJ=L±1/2),we recoverprevious result. Example:atomicsp ectraof sodium
ΔE J,M J ,L,S =µ B g J M J B
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