[PDF] Hardy-Weinberg Problems - Penguin Prof Pages





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[PDF] Hardy-Weinberg Equilibrium Problems - Houston ISD

The frequency of two alleles in a gene pool is 0 19 (A) and 0 81(a) Assume that the population is in Hardy-Weinberg equilibrium (a) Calculate the percentage 




[PDF] Hardy-Weinberg Equilibrium

If the allele frequencies are the same for both generations then the population is in Hardy-Weinberg Equilibrium Example 1b: Recall: the previous generation 

[PDF] Hardy-Weinberg Practice Problems - The Wheatley School

Hardy-Weinberg Practice Problems 1 A population of rabbits may be brown (the dominant What is the frequency of each genotype in this population?

[PDF] MORE Hardy-Weinberg Practice Problems

In a small population of 5000 bears, the recessive allele frequency for coat color is 0 34 a What is the frequency of heterozygotes in this population? 0 45

[PDF] Hardy-Weinberg Practice Problems

Problem 6: In a population that meets Hardy-Weinberg equilibrium, the allele frequency is 0 36 dominant and 0 64 recessive How many individuals in a population 




[PDF] PRACTICE PROBLEMS IN POPULATION GENETICS 1 In a study of

b) Calculate the expected allele frequencies and genotype frequencies if the population were in Hardy-Weinberg equilibrium

[PDF] allele frequencies, Hardy-Weinberg, and haploid selection models

Practice problems: allele frequencies, Hardy-Weinberg, and haploid selection models An answer key will be posted, but don't be tempted to peak before doing 

[PDF] Practice problems I: Solutions - UBC Zoology

A population consists of 35 red plants, 54 pink plants, and 67 white plants Calculate the genotype and allele frequencies Is this population in Hardy-Weinberg 

[PDF] AP Biology Hardy-Weinberg Practice Problems – ANSWER KEY 1

White coloring is caused by the recessive genotype, "aa" Calculate allelic and genotypic frequencies for this population q = 0 592 or 59 2 frequency of “a” 




[PDF] Hardy-Weinberg Practice Problems

8 oct 2015 · Hardy-Weinberg Practice Problems Show your work for the following a What is the frequency of the AA genotype in this population?

[PDF] AP Biology Hardy-Weinberg Practice Problems - Nauset Schools

C The frequency of the "A" allele (p) p = 0 4 or 40 D The frequencies of the genotypes "AA" (p2) and "Aa" (2pq) p2 = AA = 0 16 or 16 2pq = Aa = 48 or 48

[PDF] Hardy-Weinberg Problems - Penguin Prof Pages

Hardy, Weinberg and Castle determined that the frequencies of alleles and Penguin Prof Helpful Hints: Solving Hardy-Weinberg Problems Penguin Prof Helpful Hints: Solving Hardy-Weinberg Problems Page 1 Page 2 Sample Problem

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[PDF] Hardy-Weinberg Problems - Penguin Prof Pages 7035_3solving_hardy_weinberg_problems.pdf

Introduction

Hardy, Weinberg and Castle determined that the frequencies of alleles and genotypes in a

767<3);1659-4)15;0-:)4-6=-9;14-/1=-5;0);+-9;)15)::<47;165:)9-4-;

A!9/)51:4:)9-,17361,

A-5-9);165:)9-565 6=-93)7715/

A"67<3);1654<:;*-3)9/-

A 61441/9);16569-41/9);165

A 64<;);16515;0-/-5-6.15;-9-:;

A 65);<9)3:-3-+;1656++<9:15,1=1,<)3:9-796,<+-);-8<)39);-:

A);15/1:9)5,64

Overview

How to solve Hardy-Weinberg Problems:

-;-9415-;0-)33-3-: 9-8<-5+?6.;0-,6415)5;)33-3-1:,-:1/5);-,):'p' 9-8<-5+?6.;0-9-+-::1=-)33-3-1:,-:1/5);-,):q' 33-31+9-8<-5+?#<3-9-8<-5+?6.)$ 15;0-767<3);165 p + q = 1

3. Genotype Frequency Rule (Frequency of a GENOTYPE in the population):

7878 $14731.?;01::;);-4-5;<:15/;0-!9<3-B72+ pq + pq +q2= 1 p2+ 2pq + q2= 1 p2= frequency of homozygous dominant genotype

78.9-8<-5+?6.0-;-96@?/6<:/-56;?7-

82= frequency of homozygous recessive genotypePenguin Prof Helpful Hints: Solving Hardy-W

einberg ProblemsPenguin Prof Helpful Hints: Solving Hardy-Weinberg ProblemsPage 1

Sample Problem

In a population of 130,000 magical mice, green fur is dominant over orange. If there are 300 orange

41+-15)767<3);1656.   .15,;0-.6336>15/)::<4-767<3);1651:15)9,? &-15*-9/

-8<131*91<4 9-8<-5+?6.,6415)5;/9--5)33-3- 9-8<-5+?6.9-+-::1=-69)5/-)33-3-  9-8<-5+?6.0646@?/6<:,6415)5;0-;-96@?/6<:)5,0646@?/6<:9-+-::1=-/-56;?7-:

Step 1: Assign the Alleles

•?+65=-5;165>-<:-;0-,6415)5;70-56;?7-;65)4-;0-)33-3-: 5;01:+):-/9--51: ,6415)5;6=-969)5/-:6>-33<:-.69/9--5.<9)5,/.6969)5/-.<9 A::1/57;6*-;0-.9-8<-5+?6.;0-/9--5.<9)33-3- A::1/58;6*-;0-.9-8<-5+?6./;0-69)5/-.<9)33-3-

Penguin Prof Helpful Hints: Solving Hardy-W

einberg ProblemsPenguin Prof Helpful Hints: Solving Hardy-Weinberg ProblemsPage 2

Step 2: Calculate q

The number of homozygous recessive individuals is q2, NOT q. To find q, take the square root of q2.

Step 3: Calculate p

Once you haveq,findingpis easy! The sum of the frequencies of both alleles must equal 1. Step 4: Use p and q to calculate the remaining genotypes I always suggest that you calculate q2even though that's what you started with. Realize that

96<5,15/>133/1=-?6<:31/0;3?,1..-9-5;=)3<-:)5,)33/-56;?7-.9-8<-5+1-:4)?56;'%(

-8<)3 *-+)<:-6.;01: ;:.15-

Penguin Prof Helpful Hints: Solving Hardy-W

einberg ProblemsPenguin Prof Helpful Hints: Solving Hardy-Weinberg ProblemsPage 3

That's it! Answer the questions:

1.9-8<-5+?6.,6415)5;/9--5)33-3-

 9-8<-5+?6.9-+-::1=-69)5/-)33-3-   9-8<-5+?6.-)+0/-56;?7-

A0646@?/6<:,6415)5;



A0-;-96@?/6<:



A0646@?/6<:9-+-::1=-

Need More Help?

Check out my video%0-)9,? &-15*-9/"915+173-65;0-"-5/<15"96.(6<%<*-+0)55-3 66, 3<+2

Penguin Prof Helpful Hints: Solving Hardy-W

einberg ProblemsPenguin Prof Helpful Hints: Solving Hardy-Weinberg ProblemsPage 4

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