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2 3 1 Factorise polynomial expressions 2 3 2 Divide a polynomial by a linear or quadratic factor 2 3 3 Apply the remainder theorem 2 3
It's worth pointing out that cubic equations are not so easy to solve If the equation in Example 3 were quadratic, we could use the quadratic formula, but it's
The graph suggests that the function has three zeros, one of which is x = 2 It's easy to show that f(2) = 0, but the other two zeros seem to be less
4 2 8 - The Factor Theorem 4 2 - Algebra - Solving Equations Leaving Certificate Mathematics Higher Level ONLY 4 2 - Algebra - Solving Equations
as simple as it was for quadratics remainder and factor theorems to factorise and to solve From the above examples, we saw that a polynomial
Factor theorem state with proof examples and solutions factorise the minus As mercury can see factoring the difference of two squares is pretty easy
By the definition of Gf we can do this without intro- ducing into F' two edges with a common end We thus construct a 1-factor of G' Conversely suppose G' has
the following are all examples of quadratic equations o 2 2 ? 3 ? 5 = 0 we will use the Zero Factor Theorem to solve quadratic equations
An important consequence of the Factor Theorem is that finding the zeros of a polynomial is really the same thing as factoring it into linear factors