A Normal distribution is described by a Normal density curve Any particular Normal distribution is completely specified by two numbers: its mean ???? and its standard deviation ???? The mean of a Normal distribution is the center of the symmetric Normal curve The standard deviation is the distance from the center to the change-
have a normal distribution • The normal distribution is easy to work with mathematically In many practical cases, the methods developed using normal theory work quite well even when the distribution is not normal • There is a very strong connection between the size of a sample N and the extent to which a sampling distribution approaches
calculated over intervals rather than for speci c values of the random variable Although many types of probability density functions commonly occur, we will restrict our attention to random variables with Normal Distributions and the probabilities will correspond to areas under a Normal Curve (or normal density function)
Normal Distributions37 from the menu to standardize By selecting “Subtract mean and divide by standard deviation” the command calculated the standardized values, z=(x?x)s The results can be stored in C2 The standardized vocabulary scores (or z?score) will tell how far above or below the mean a particular score falls
Perhaps the most important ideal distribution used is the 'normal' distribution (Figure 6 1) Once one understands the characteristics of the normal distribution, knowledge of other distributions is easily obtained Figure 6 1 The normal distribution Most people are familiar with the normal distribution described as a “bell-shaped curve,”
.1 of BPS is a histogram of the scores of all 947 seventh-grade students in Gary, Indiana, on the vo-
cabulary part of the Iowa Test of Basic Skills. To see how well the Normal density describes these data, we can select Graph Histogram and select the With Fit option to obtain a histo- gram with a Normal curve fitted to the data. ȱ 35Inȱtheȱfollowingȱdialogȱbox,ȱselectȱtheȱvariableȱtoȱbeȱgraphedȱandȱclickȱOK.ȱȱMinitabȱwillȱ
produceȱaȱhistogramȱwithȱaȱNormalȱdensityȱcurveȱforȱtheȱvariable.ȱȱTheȱNormalȱdensityȱcurveȱ
selectedȱwillȱbeȱbasedȱonȱtheȱdata'sȱmeanȱandȱstandardȱdeviation.ȱ ȱTheȱsmoothȱcurveȱdrawnȱthroughȱtheȱhistogramȱisȱaȱgoodȱdescriptionȱofȱtheȱoverallȱpatȬ
ternȱofȱtheȱdata.ȱȱItȱwillȱbeȱeasierȱtoȱuseȱtheȱdensityȱcurveȱinsteadȱofȱtheȱhistogramȱforȱsomeȱcalȬ
culations.ȱ vocabulary score Fr e q u e n c yMinitabȱcanȱbeȱusedȱtoȱperformȱNormalȱdistributionȱcalculations.ȱȱIfȱdataȱinȱaȱcolumnȱ
areȱNormallyȱdistributed,ȱthenȱtheȱdataȱcanȱbeȱstandardizedȱtoȱobtainȱdataȱwithȱaȱstandardȱ
Normalȱdistribution,ȱthatȱis,ȱthoseȱwithȱmeanȱequalȱtoȱzeroȱandȱstandardȱdeviationȱequalȱtoȱone.ȱȱ
Theȱstandardizedȱvocabularyȱscoresȱ(orȱzȬscore)ȱwillȱtellȱhowȱfarȱaboveȱorȱbelowȱtheȱ
meanȱaȱparticularȱscoreȱfalls.ȱȱTheȱmeasureȱisȱinȱunitsȱofȱstandardȱdeviations.ȱȱTheȱfirstȱstudentȱ
hasȱaȱscoreȱofȱ5.8,ȱaȱvalueȱthatȱisȱbelowȱtheȱmeanȱ(zȱ=ȱ0.67213).ȱȱTheȱsecondȱscore,ȱ6.3,ȱisȱalsoȱ
belowȱtheȱmean,ȱbutȱtheȱthird,ȱ7.8,ȱisȱaboveȱtheȱmeanȱ(zȱ=ȱ0.61713).ȱȱȱ
ȱWeȱcouldȱexamineȱtheȱstandardizedȱvaluesȱtoȱseeȱhowȱwellȱtheyȱobeyȱtheȱ68Ȭ95Ȭ99.7ȱ
rule.ȱȱApproximatelyȱ68%ȱofȱtheȱstandardizedȱvaluesȱshouldȱhaveȱvaluesȱbetweenȱ-1ȱandȱ+1,ȱ
Anotherȱwayȱtoȱobtainȱstandardizedȱvaluesȱ(zȬscores)ȱisȱtoȱuseȱMinitab'sȱcalculator.ȱȱ
Fromȱtheȱfollowingȱdescriptiveȱinformation,ȱweȱcanȱstandardizeȱtheȱvocabularyȱscoresȱbyȱsubȬ
tractingȱtheȱmeanȱ(6.8427)ȱandȱdividingȱbyȱtheȱstandardȱdeviationȱ(1.5513).ȱȱȱ
ToȱstandardizeȱusingȱMinitab'sȱcalculator,ȱselectȱCalcȱȱCalculatorȱfromȱtheȱmenuȱandȱ
enterȱtheȱappropriateȱexpressionȱillustratedȱinȱtheȱfollowingȱdialogȱbox.ȱ
YouȱcanȱuseȱMinitabȱtoȱdoȱprobabilityȱcalculationsȱforȱtheȱNormalȱdistributionȱbyȱselectȬ
ingȱȱ CalcȱȱProbabilityȱDistributionsȱȱNormalȱfromȱtheȱmenu.ȱȱBothȱforwardȱandȱbackwardȱprobabilitiesȱcanȱbeȱcalculated.ȱ
ȱExampleȱ3.4ȱinȱBPSȱconcernsȱtheȱheightsȱofȱyoungȱwomen.ȱȱTheȱheightsȱareȱapproxiȬ
matelyȱNormalȱwithȱaȱmeanȱofȱaboutȱ64ȱinchesȱandȱaȱstandardȱdeviationȱofȱ2.7ȱinches.ȱȱToȱfindȱ
theȱproportionȱofȱwomenȱwhoȱareȱlessȱthanȱ70ȱinchesȱtall,ȱweȱselectȱCalcȱȱProbabilityȱDistriȬ
butionsȱȱNormalȱfromȱtheȱmenu.ȱȱInȱtheȱdialogȱbox,ȱweȱselectȱCumulativeȱprobability,ȱfillȱinȱ
theȱMean,ȱStandardȱdeviation,ȱandȱInputȱconstantȱboxesȱasȱfollows.ȱAfterȱclickingȱonȱOK,ȱweȱobtainȱtheȱfollowingȱinformationȱinȱMinitab'sȱSessionȱwindow.ȱȱTheȱ
resultȱsaysȱthatȱtheȱproportionȱofȱwomenȱwhoȱareȱlessȱthanȱ70ȱinchesȱtallȱisȱ.986866.ȱȱThisȱisȱ
slightlyȱdifferentȱfromȱtheȱresultȱthatȱwouldȱbeȱobtainedȱusingȱTableȱAȱsinceȱitȱisȱnotȱrequiredȱtoȱ
roundȱtheȱstandardizedȱvalue.ȱWeȱcanȱalsoȱuseȱMinitabȱtoȱdoȱbackwardȱcalculations.ȱȱExampleȱ3.8ȱofȱBPSȱshowsȱscoresȱonȱtheȱ
SATȱverbalȱtestȱinȱ2002.ȱȱTheȱscoresȱfollowȱapproximatelyȱtheȱN(504,ȱ110)ȱdistributionȱandȱwe'dȱ
likeȱtoȱfindȱhowȱhighȱaȱstudentȱmustȱscoreȱȱtoȱplaceȱinȱtheȱtopȱ10%ȱofȱallȱstudentsȱtakingȱtheȱ
SAT.ȱȱAgain,ȱweȱselectȱCalcȱȱProbabilityȱDistributionsȱȱNormalȱfromȱtheȱmenu.ȱȱSinceȱweȱ
areȱdoingȱaȱbackwardȱcalculation,ȱweȱcheckȱInverseȱcumulativeȱprobability.ȱȱWeȱfillȱinȱtheȱ
Mean,ȱStandardȱdeviation,ȱandȱInputȱconstantȱboxesȱasȱfollows.ȱȱNoticeȱthatȱsinceȱweȱwantȱtheȱ
valueȱforȱtheȱtopȱ10%,ȱtheȱinputȱconstantȱisȱ0.9ȱcorrespondingȱtoȱ90%ȱbelowȱtheȱcalculatedȱ
value.ȱAfterȱclickingȱonȱOKȱinȱtheȱdialogȱbox,ȱweȱobtainȱtheȱfollowingȱresultsȱinȱtheȱSessionȱwindow.ȱȱ
Weȱseeȱthatȱaȱstudentȱmustȱscoreȱaboveȱ644.971ȱ(i.e.,ȱ645ȱorȱabove)ȱtoȱbeȱinȱtheȱtopȱ10%.ȱ
ofȱobservationsȱfromȱaȱstandardȱNormalȱdistributionȱthatȱsatisfiesȱeachȱofȱtheȱfollowingȱ
statements.ȱInȱeachȱcase,ȱsketchȱaȱstandardȱNormalȱcurveȱwithȱyourȱvalueȱofȱzȱmarkedȱ
onȱtheȱaxis.ȱ(a)ȱȱTheȱpointȱzȱwithȱ25%ȱofȱtheȱobservationsȱfallingȱbelowȱit.ȱ
(b)ȱȱTheȱpointȱzȱwithȱ40%ȱofȱtheȱobservationsȱfallingȱaboveȱit.ȱ
ȱwithȱȱ=ȱ100ȱandȱȱ=ȱ15.ȱȱSelectȱCalcȱȱProbabilityȱDistributionsȱȱNormalȱfromȱtheȱ
menuȱtoȱanswerȱtheȱfollowingȱquestions.ȱ (a)ȱȱWhatȱscoresȱfallȱinȱtheȱlowestȱ25%ȱofȱtheȱdistribution?ȱ (b)ȱȱHowȱhighȱaȱscoreȱisȱneededȱtoȱbeȱinȱtheȱhighestȱ5%?ȱ ȱlevelsȱofȱcompression.ȱWeȱmightȱexpectȱtheȱpenetrabilityȱofȱspecimensȱofȱtheȱsameȱsoilȱatȱ
theȱsameȱlevelȱofȱcompressionȱtoȱfollowȱaȱNormalȱdistribution.ȱȱSelectȱGraphȱȱHistoȬ
gramȱfromȱtheȱmenuȱandȱselectȱWithȱFitȱandȱGroupsȱtoȱmakeȱaȱhistogramsȱofȱtheȱdataȱ
forȱlooseȱandȱforȱintermediateȱcompression.ȱDoesȱeitherȱsampleȱseemȱroughlyȱNormal?ȱ
DoesȱeitherȱappearȱdistinctlyȱnonȬNormal?ȱIfȱso,ȱwhatȱkindȱofȱdepartureȱfromȱNormalityȱ
doesȱyourȱgraphȱshow?ȱ ȱ(a)ȱȱWeȱexpectȱIQȱscoresȱtoȱbeȱapproximatelyȱNormal.ȱSelectȱGraphȱȱHistogramȱ
fromȱtheȱmenuȱandȱselectȱWithȱFitȱȱtoȱmakeȱaȱhistogramȱwithȱtheȱcorrespondingȱ
normalȱdenisityȱcurveȱtoȱseeȱthatȱthereȱareȱnoȱmajorȱdeparturesȱfromȱNormality.ȱ
(b)ȱȱNonetheless,ȱproportionsȱcalculatedȱfromȱaȱNormalȱdistributionȱareȱnotȱalwaysȱ
veryȱaccurateȱforȱsmallȱnumbersȱofȱobservations.ȱȱSelectȱCalcȱȱStandardizeȱtoȱ
findȱtheȱstandizedȱvaluesȱforȱtheseȱIQȱscores.ȱWhatȱproportionsȱofȱtheȱscoresȱareȱ
withinȱoneȱstandardȱdeviationȱandȱwithinȱtwoȱstandardȱdeviationsȱofȱtheȱmean?ȱ
WhatȱwouldȱtheseȱproportionsȱbeȱinȱanȱexactlyȱNormalȱdistribution?ȱ ȱofȱobservationsȱfromȱaȱstandardȱNormalȱdistributionȱthatȱfallsȱinȱeachȱofȱtheȱfollowingȱ
regions.ȱInȱeachȱcase,ȱsketchȱaȱstandardȱNormalȱcurveȱandȱshadeȱtheȱareaȱrepresentingȱ
theȱregion.ȱ (a)ȱȱzȱǂȱƺ2.25ȱ (b)ȱȱzȱǃȱƺ2.25ȱ (c)ȱȱzȱ>ȱ1.77ȱ (d)ȱȱƺ2.25ȱ<ȱzȱ<ȱ1.77ȱ ȱ(a)ȱȱȱFindȱtheȱnumberȱzȱsuchȱthatȱtheȱproportionȱofȱobservationsȱthatȱareȱlessȱthanȱzȱinȱ
aȱstandardȱNormalȱdistributionȱisȱ0.8.ȱ(b)ȱȱȱFindȱtheȱnumberȱzȱsuchȱthatȱ35%ȱofȱallȱobservationsȱfromȱaȱstandardȱNormalȱdisȬ
tributionȱareȱgreaterȱthanȱz.ȱ ȱMenȱtheȱsameȱageȱhaveȱheightsȱdistributedȱasȱN(69.3,ȱ2.8).ȱSelectȱCalcȱȱProbabilityȱ
DistributionsȱȱNormalȱfromȱtheȱmenuȱtoȱfindȱtheȱpercentȱofȱyoungȱwomenȱareȱtallerȱ
thanȱtheȱmeanȱheightȱofȱyoungȱmen?ȱ ȱMenȱtheȱsameȱageȱhaveȱheightsȱdistributedȱasȱN(69.3,ȱ2.8).ȱSelectȱCalcȱȱProbabilityȱ
DistributionsȱȱNormalȱfromȱtheȱmenuȱtoȱfindȱtheȱpercentȱofȱyoungȱmenȱareȱshorterȱ
thanȱtheȱmeanȱheightȱofȱyoungȱwomen.ȱ ȱtheȱpercentȱofȱobservationsȱinȱtheȱtails.ȱSupposeȱthatȱaȱcollegeȱisȱlookingȱforȱapplicantsȱ
withȱSATȱmathȱscoresȱ750ȱandȱabove.ȱȱSelectȱCalcȱȱProbabilityȱDistributionsȱȱNorȬ
malȱfromȱtheȱmenuȱtoȱanswerȱtheȱfollowingȱquestions.ȱ(a)ȱȱInȱ2004,ȱtheȱscoresȱofȱmenȱonȱtheȱmathȱSATȱfollowedȱtheȱN(537,ȱ116)ȱdistribution.ȱ
Whatȱpercentȱofȱmenȱscoredȱ750ȱorȱbetter?ȱ(b)ȱȱWomenȇsȱSATȱmathȱscoresȱthatȱyearȱhadȱtheȱN(501,ȱ110)ȱdistribution.ȱWhatȱperȬ
centȱofȱwomenȱscoredȱ750ȱorȱbetter?ȱYouȱseeȱthatȱtheȱpercentȱofȱmenȱaboveȱ750ȱisȱ
almostȱthreeȱtimesȱtheȱpercentȱofȱwomenȱwithȱsuchȱhighȱscores.ȱWhyȱthisȱisȱtrueȱ
isȱcontroversial.ȱ ȱdiagnoseȱosteoporosis,ȱanȱelaborateȱapparatusȱmeasuresȱboneȱmineralȱdensityȱ(BMD).ȱ
BMDȱisȱusuallyȱreportedȱinȱstandardizedȱform.ȱTheȱstandardizationȱisȱbasedȱonȱaȱpopuȬ
lationȱofȱhealthyȱyoungȱadults.ȱTheȱWorldȱHealthȱOrganizationȱ(WHO)ȱcriterionȱforȱosȬ
teoporosisȱisȱaȱBMDȱ2.5ȱstandardȱdeviationsȱbelowȱtheȱmeanȱforȱyoungȱadults.ȱBMDȱ
measurementsȱinȱaȱpopulationȱofȱpeoplesimilarȱinȱageȱandȱsexȱroughlyȱfollowȱaȱNormalȱ
distribution.ȱSelectȱCalcȱȱProbabilityȱDistributionsȱȱNormalȱfromȱtheȱmenuȱtoȱanȬ
swerȱtheȱfollowingȱquestions.ȱ(a)ȱȱWhatȱpercentȱofȱhealthyȱyoungȱadultsȱhaveȱosteoporosisȱbyȱtheȱWHOȱcriterion?ȱ
(b)ȱȱWomenȱagesȱ70ȱtoȱ79ȱareȱofȱcourseȱnotȱyoungȱadults.ȱTheȱmeanȱBMDȱinȱthisȱageȱ
isȱaboutȱƺ2ȱonȱtheȱstandardȱscaleȱforȱyoungȱadults.ȱSupposeȱthatȱtheȱstandardȱdeȬ
viationȱisȱtheȱsameȱasȱforȱyoungȱadults.ȱWhatȱpercentȱofȱthisȱolderȱpopulationȱhasȱ
osteoporosis?ȱ ȱ