Let's write a program to ask the user for an integer, and then print out whether that number is EVEN or ODD If we divide an even number by 2, what will the
Write a python script that accepts a list of integers separated by spaces Convert this into a list of integers but square each element Print this list
Since the int() function cannot accept a string that doesn't appear as an integer, an error is produced as shown in lines 12 through 14 (Although line 10 is
The print function can accept any number of positional arguments, Python integers are variable-precision, so you can do computations that would
Purpose of this article: Learn how to take input from users and systems in Python Accepts integers, floats, characters, and string input from the user
8 avr 2019 · Python uses an interpreter to convert its instructions types, hence the print function accepts integer (16) along with strings here
Python integers can have an arbitrary number of digits Lists are just one of many kinds of indexable objects in Python that can accept cross-
What we are doing is taking the int value of myAge and adding 1 to it, and then we are converting that value to a string data type, allowing us to concatenate
ii) Let L be a list, each element of which is a list of ints In Python, the assignment statement L[0][0]=3 mutates the list L
index: A 0-based integer to access an element from an array index 0 1 2 3 4 5 6 7 8 9 Accept the array of integers to reverse as a parameter
1436_6PythonLab2.pdf LAB 2 - Loops Let"s write a program to ask the user for an integer, and then print out whether that number is EVEN or ODD. If we divide an even number by 2, what will the remainder be? def main(): x = input("Input an integer: ") if x % 2 == 0: print "EVEN" else: print "ODD" Recall that, in Python, 7 % 3 gives us the remainder when 7 is divided by 3, which is 1. Now suppose we wish to change our program so that it asks the user to enter 8 integers (one at a time), and then prints out how many of those integers were even numbers. For example, if the user enters the following integers
19, 6, 9, 20, 13, 7, 6, 1
then our program should print out 3, since 3 of those numbers were even. Clearly, our program should use a loop that runs 8 times. And one thing we know we need to do 8 times is to ask the user to enter an integer. We can write this in Python as: for times in range(8): x = input("Input an integer: ") What will our program need to remember as it runs? It does not need to remember all the numbers that have been entered so far. But it will need to remember how many of the numbers entered so far have been even. Let"s call this count, since we"re counting how many values are even. We should initialize count to be 0, because at the beginning of the program, zero even integers have been entered. At the end of the program, count should represent the total number of even integers entered. count = 0 for times in range(8): x = input("Input an integer: ") print count, "integers were even" How should the value of x (an integer entered by the user) influence the value of count (the total number of even integers entered so far)? Suppose count is 2, and the user then enters the integer 7. Because 7 is odd, count should not change. On the other hand, if the user now enters 6 (an even number), count should increment from 2 to 3, representing that now 3 even integers have been entered so far. We can increment count by finding the value of count + 1 and storing this result in count. count = count + 1 This behavior (incrementing count) should only run if x (the entered integer) is even. if x % 2 == 0: count = count + 1 And we should perform this test each time the user enters an integer, so our final program reads as follows. def main(): count = 0 for times in range(8): x = input("Input an integer: ") if x % 2 == 0: count = count + 1 print count, "integers were even"
Here"s a flowchart depicting our algorithm: