[PDF] EXAMPLE: ELECTROMAGNETIC SOLENOID




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[PDF] Solenoids, electromagnets and electromagnetic windings

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[PDF] EXAMPLE: ELECTROMAGNETIC SOLENOID

On the mechanical side, a force is required to displace the armature from its center position —the device looks like a spring

[PDF] EXAMPLE: ELECTROMAGNETIC SOLENOID 86796_39ad757109f959fbcbb125e8d1d055e8c_solenoid.pdf

EXAMPLE: ELECTROMAGNETIC SOLENOID A common electromechanical actuator for linear (translational) motion

is a solenoid. Current in the coil sets up a magnetic field that tends to center the mo vable armature. Electromagnetic Solenoid page 1 © Neville Hogan

On the electrical side the device behaves like an inductor - but the inductance depends on the position of the movable armature.

This "position-modulated inductor" is properly represented by a tw o-port energy-storage element with an electrical port and a mechanical port. On the mechanical side, a force is required to displace the armature fro m its

center position - the device looks like a spring. An inductor may be represented by a gyrator (coupling the electrical an

d magnetic domains) and a capacitor representing magnetic energy storage.

A bond graph for this model is as follows.

F GY e= . i N C m agnetic domaine l ect r ica l domain F m echanica l domain x. . Electromagnetic Solenoid page 2 © Neville Hogan E

QUIVALENT BEHAVIOR

: To find an equivalent model without the magnetic domain bring the magnet ic behavior into the electrical domain.

a capacitor through a gyrator behaves like an inductor the mechanical side still behaves like a spring. This model can be represented by a (new) multiport element with "mi

xed" behavior - like an inertia (inductor) on one port - like a capacitor (spring) on the other i IC e l ect r ica l domain F m echanica l domain x. e= . This element is often simply called a "multiport IC". Electromagnetic Solenoid page 3 © Neville Hogan C

ONSTITUTIVE EQUATIONS

- two needed i = i(, x) F = F(, x) Electrical constitutive equation - assume electrical linearity i = L(x) where L(x) is a position-dependent inductance. Mechanical constitutive equation - find the total stored energy. E = 2

2 L(x)

Force is the gradient of energy with respect to displacement. 22
xLxxL 2Ȝ xEF Electromagnetic Solenoid page 4 © Neville Hogan We need to know the function L(x) relating inductance to armature posi tion. With the armature centered, idealized coil inductance (neglecting fring ing effects) is L = N 2

µrµoA/l

where N is number of turns, µr is relative permeability, µo is the permeability of air or vacuum, A is coil cross sectional area and l is coil length. With the armature removed - displaced an infinite distance - idealized coil inductance is L = N 2

µoA/l

In practice µr >> µo so L >> L

Electromagnetic Solenoid page 5 © Neville Hogan We expect the inductance to be large with the armature centered and to decline smoothly to a small value as the armature is withdrawn to either side. The precise form of L(x) may be determined in several ways - by experiment - using Finite-Element codes to compute the magnetic field for differe nt armature positions. Electromagnetic Solenoid page 6 © Neville Hogan

An approximation:

For pedagogic simplicity we will use the following function.

L(x) = L e-(x/xc)2

where xc is a characteristic length of the armature and it has been assumed that L 0 CAUTION! This is not accurate! It has no better justification than that - it is analytically simple - it has approximately the right shape. Electromagnetic Solenoid page 7 © Neville Hogan

Mechanical constitutive equation:

2xx 2 c c Lex2x xxL 2xxxx 2 c2 2 c2 c LL x2x

2ȜF

ee 2 cxx 2

LxxeȜF

2 c This equation implies that force grows without bound as armature displacement increases. Electromagnetic Solenoid page 8 © Neville Hogan D

OES THIS MAKE SENSE PHYSICALLY

? Shouldn't the force should decline as the armature is removed? C

HECK FOR ERRORS

: Multiport stores energy, therefore should obey Maxwell's reciprocity.

Partial derivatives:

2 cxx Lxxe2 xi 2 c 2 cxx

Lxxe2F

2 c - identical, as required. Electromagnetic Solenoid page 9 © Neville Hogan The answer to this puzzle lies in our implicit assumptions - that displacement and flux linkage are independent input variables. If the flux density could be held constant, the force would grow with separation - but this is unlikely. It requires current to grow without bound as armature displacement increases. Electromagnetic Solenoid page 10 © Neville Hogan

For example:

include the inevitable resistance of the coil assume a constant voltage input ecoil i IC F Se1 R ein x . at steady state for fixed x, the current is constant, not voltage. ˙ steady-state = e coil,steady-state = e in - i coil,steady-state R = 0 i coil,steady-state = e in R Electromagnetic Solenoid page 11 © Neville Hogan

To express force as a function of current,

F = F(i, x) we may use the electrical constitutive equation to eliminate flux linkag e. 2 cxx 2 xLxeiF 2 c

In this case, if x < xc

- force increases as x is increased if x > xc - force declines rapidly to zero consistent with common experience. Electromagnetic Solenoid page 12 © Neville Hogan N OTES : Behavior (e.g., force-displacement relation) depends on boundary conditions. Force as a function of current and displacement corresponds to different ial causality on the inertia side of the multiport. ecoil i IC Fx. Electromagnetic Solenoid page 13 © Neville Hogan
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