38 Relation between Dimensions of Coil and Plunger 82 39 Relation of Pull to Position of Plunger in Solenoid 85 40 Calculation of the Pull Curve
The paper presents the construction and characteristics of a solenoid electromagnet with ferromagnetic disc placed in the coil The presence if the disc leads
The force between a magnetic material and a magnet is always of attraction The force is greater the nearer it is to the magnet and is strongest nearest to the
It is the magnetic force obtained in the solenoid after finishing the stroke using standard power Contact surface between the electromagnet and the
Charts, plotted from the formulas, reduce to a minimum the calculations necessary in designing a winding THE DETAILS of design of electromagnets and
Elucidated forces acting between wires carrying electric currents Michael Faraday (1791-1867) Discovered electromagnetic induction Heinrich Lenz
On the mechanical side, a force is required to displace the armature from its center position —the device looks like a spring
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EXAMPLE: ELECTROMAGNETIC SOLENOID A common electromechanical actuator for linear (translational) motion
is a solenoid. Current in the coil sets up a magnetic field that tends to center the mo vable armature. Electromagnetic Solenoid page 1 © Neville Hogan
On the electrical side the device behaves like an inductor - but the inductance depends on the position of the movable armature.
This "position-modulated inductor" is properly represented by a tw o-port energy-storage element with an electrical port and a mechanical port. On the mechanical side, a force is required to displace the armature fro m its
center position - the device looks like a spring. An inductor may be represented by a gyrator (coupling the electrical an
d magnetic domains) and a capacitor representing magnetic energy storage.
A bond graph for this model is as follows.
F GY e= . i N C m agnetic domaine l ect r ica l domain F m echanica l domain x. . Electromagnetic Solenoid page 2 © Neville Hogan E
QUIVALENT BEHAVIOR
: To find an equivalent model without the magnetic domain bring the magnet ic behavior into the electrical domain.
a capacitor through a gyrator behaves like an inductor the mechanical side still behaves like a spring. This model can be represented by a (new) multiport element with "mi
xed" behavior - like an inertia (inductor) on one port - like a capacitor (spring) on the other i IC e l ect r ica l domain F m echanica l domain x. e= . This element is often simply called a "multiport IC". Electromagnetic Solenoid page 3 © Neville Hogan C
ONSTITUTIVE EQUATIONS
- two needed i = i(, x) F = F(, x) Electrical constitutive equation - assume electrical linearity i = L(x) where L(x) is a position-dependent inductance. Mechanical constitutive equation - find the total stored energy. E = 2
2 L(x)
Force is the gradient of energy with respect to displacement. 22
xLxxL 2Ȝ xEF Electromagnetic Solenoid page 4 © Neville Hogan We need to know the function L(x) relating inductance to armature posi tion. With the armature centered, idealized coil inductance (neglecting fring ing effects) is L = N 2
µrµoA/l
where N is number of turns, µr is relative permeability, µo is the permeability of air or vacuum, A is coil cross sectional area and l is coil length. With the armature removed - displaced an infinite distance - idealized coil inductance is L = N 2
µoA/l
In practice µr >> µo so L >> L
Electromagnetic Solenoid page 5 © Neville Hogan We expect the inductance to be large with the armature centered and to decline smoothly to a small value as the armature is withdrawn to either side. The precise form of L(x) may be determined in several ways - by experiment - using Finite-Element codes to compute the magnetic field for differe nt armature positions. Electromagnetic Solenoid page 6 © Neville Hogan
An approximation:
For pedagogic simplicity we will use the following function.
L(x) = L e-(x/xc)2
where xc is a characteristic length of the armature and it has been assumed that L 0 CAUTION! This is not accurate! It has no better justification than that - it is analytically simple - it has approximately the right shape. Electromagnetic Solenoid page 7 © Neville Hogan
Mechanical constitutive equation:
2xx 2 c c Lex2x xxL 2xxxx 2 c2 2 c2 c LL x2x
2ȜF
ee 2 cxx 2
LxxeȜF
2 c This equation implies that force grows without bound as armature displacement increases. Electromagnetic Solenoid page 8 © Neville Hogan D
OES THIS MAKE SENSE PHYSICALLY
? Shouldn't the force should decline as the armature is removed? C
HECK FOR ERRORS
: Multiport stores energy, therefore should obey Maxwell's reciprocity.
Partial derivatives:
2 cxx Lxxe2 xi 2 c 2 cxx
Lxxe2F
2 c - identical, as required. Electromagnetic Solenoid page 9 © Neville Hogan The answer to this puzzle lies in our implicit assumptions - that displacement and flux linkage are independent input variables. If the flux density could be held constant, the force would grow with separation - but this is unlikely. It requires current to grow without bound as armature displacement increases. Electromagnetic Solenoid page 10 © Neville Hogan
For example:
include the inevitable resistance of the coil assume a constant voltage input ecoil i IC F Se1 R ein x . at steady state for fixed x, the current is constant, not voltage. ˙ steady-state = e coil,steady-state = e in - i coil,steady-state R = 0 i coil,steady-state = e in R Electromagnetic Solenoid page 11 © Neville Hogan
To express force as a function of current,
F = F(i, x) we may use the electrical constitutive equation to eliminate flux linkag e. 2 cxx 2 xLxeiF 2 c
In this case, if x < xc
- force increases as x is increased if x > xc - force declines rapidly to zero consistent with common experience. Electromagnetic Solenoid page 12 © Neville Hogan N OTES : Behavior (e.g., force-displacement relation) depends on boundary conditions. Force as a function of current and displacement corresponds to different ial causality on the inertia side of the multiport. ecoil i IC Fx. Electromagnetic Solenoid page 13 © Neville Hogan