[PDF] Quadratic Formula.pdf Solve each equation with the





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jemh104.pdf

Quadratic equations arise in several situations in the world around us and in different fields of mathematics. Let us consider a few examples.



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Quadratic Equations in Engineering. Example: (PHY 24.00 - Physics ME 2210 - Dynamics) Now have three methods to solve the quadratic equation.



1_VII_d_Solving Quadratic Equations by Quadratic Formula

1. VII. d. Solving Quadratic Equations by Quadratic. Formula Examples I. We can use the completing the square method to solve a quadratic equation.



Quadratic Formula.pdf

Solve each equation with the quadratic formula. 1) m. 2 ? 5m ? 14 = 0. 2) b. 2 ? 4b 



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Quadratic equations have just one unknown but contain a square term as well as linear terms. For example



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Simplify and solve. Example: Since we cannot take the square root of a negative number the equation cannot be solved further 





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as the solution to the equation ax2 +bx=c. We can use the quadratic formula to solve any quadratic this is shown in the fol- lowing examples. Example 2.



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Elementary Algebra Skill. Solving Quadratic Equations Using the Quadratic Formula. Solve each equation with the quadratic formula. 1) 3n. 2 ? 5n ? 8 = 0.



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Example 1: Use the quadratic functiony= 2x2?16x+ 45 to answer the following Determine if the function opens upward or downward Find the vertex of the parabola Find the maximum value Find the minimum value Find thex-intercepts Solution: Opens upward sincea= 2>0 (b) Thex-value of the vertex is found byx=?b =?(?16) = 4 2a2?2



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quadratic equation is a polynomial equation of the form Whereis called the leading term (or constantterm) Additionallyis call the +linear term +=and is called the constant coefficient SECTION 13 1: THE SQUARE ROOT PROPERTY SOLVE BASIC QUADRATIC EQUATIONS USING SQUAREROOT PROPERTY Squareroot? property LetandThen



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Using the Quadratic Formula Date_____ Period____ Solve each equation with the quadratic formula 1) m2 ? 5m ? 14 = 0 {7 ?2} 2) b2 ? 4b + 4 = 0 {2} 3) 2m2 + 2m ? 12 = 0 {2 ?3} 4) 2x2 ? 3x ? 5 = 0 {5 2 ?1} 5) x2 + 4x + 3 = 0 {?1 ?3} 6) 2x2 + 3x ? 20 = 0 {5 2 ?4} 7) 4b2 + 8b + 7 = 4 {? 1 2 ? 3 2}



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A quadratic equation takes the form ax2 +bx+c =0 where a b and c are numbers The number a cannot be zero In this unit we will look at how to solve quadratic equations using four methods: • solution by factorisation • solution by completing the square • solution using a formula • solution using graphs



Quadratic Equation in Real Life Overview & Examples - Studycom

SOLVING QUADRATIC EQUATIONS In this brush-up exercise we will review three different ways to solve a quadratic equation EXAMPLE 1: Solve: 6 2+ ?15=0 SOLUTION We check to see if we can factor and find that 6 2+ ?15=0 in factored form is (2 ?3)(3 +5)=0 We now apply the principle of zero products: 2 ?3=0 3 +5=0

The quadratic formula is:

When working on solving quadratic equations, it is advisable to use the quadratic formula onlywhen factoring fails.

Positive Discriminant

There are 2 real roots, and 2 x-intercepts.

Zero Discriminant

©Tutoring and Learning Centre, George Brown College, 2020 | www.georgebrown.ca/tlc

There are 2 equal real roots, and 1 x-intercept.

Negative Discriminant

There are no real roots, and no x-intercepts.

Example 1:

Step 1:

Determine the values of a, b and c.

©Tutoring and Learning Centre, George Brown College, 2020 | www.georgebrown.ca/tlc

Example:

Step 2:

Plug in the values for a, b and c into the quadratic formula.

Example:

Step 3:

Simplify and solve.

Example:

Example 2:

Step 1:

Determine the values of a, b, and c.

©Tutoring and Learning Centre, George Brown College, 2020 | www.georgebrown.ca/tlc

Example:

Step 2:

Step 3:

Simplify and solve.

Example:

Since we cannot take the square root of a negative number, the equation cannot be solved further using the set of real numbers. (Note: imaginary numbers are not discussed in this hand-out).

Step 4:

State the final answer.

Example:

Since there are no real solutions for this equation, there are no x-intercepts.

Example 3:

Step 1:

Determine the values of a, b and c.

Example:

©Tutoring and Learning Centre, George Brown College, 2020 | www.georgebrown.ca/tlc

Step 2:

Plug in the values for a, b and c into the quadratic formula.

Example:

Step 3:

Simplify and solve.

Example:

x = 4.5

Step 4:

Practice Questions:

1) Solve using the quadratic formula. Round to 2 decimal places, if necessary.

2) Find the x-intercept(s) of each quadratic relation (if any) using the quadratic

formula. ©Tutoring and Learning Centre, George Brown College, 2020 | www.georgebrown.ca/tlc

Answers:

= -0.58 = 2.58

1c) X = -0.67

1d) no real solutions

1e) X1 = 0.06 X2 = 2.'94

2a) {-3.5, 0)

2c) (-0.81, 0) and (0.53, 0)

The quadratic formula can be

derirved by completing the square and isolati11g1 x in the standard form of a quadratic rellation, y = ax 2 + bx + c,. when y =

2b) no x-intercepts

Where does the quadratic formula come from?

Step 1:

Step 2:

Step 3:

©Tutoring and Learning Centre, George Brown College, 2020 | www.georgebrown.ca/tlc

Step 4:

Step 5:

Step 6:

Step 7:

Take the square root of both sides of the equation.

Step 8:

©Tutoring and Learning Centre, George Brown College, 2020 | www.georgebrown.ca/tlc

Step 9:

Since both terms on the right side of the equation have a common denominator, add and subtract the two terms. ©Tutoring and Learning Centre, George Brown College, 2020 | www.georgebrown.ca/tlcquotesdbs_dbs17.pdfusesText_23
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