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X(x) :=P(X=x);
X i2NpX(xi) =P(S) = 1:
??X?? EX:=X fx:pX(x)>0gxp X(x) pX(x) =8
:12 ; x= 1 12 ; x= 00;??? ????? ?????? ??x?
?????EX= (1)(12 ) + (0)(12 ) =12 18 X?EX= (0)12
+ (1)14 + (2)18 + (3)1161 +x+x2+x3+=11x:
1 + 2x+ 3x2+=1(1x)2:
EX= 1(14
) + 2(18 ) + 3(116 14 h1 + 2(
12 ) + 3(14 ) +i 14 1(112 )2= 1:EX=XxP(X=x) = (3)(13
) + (4)(13 ) + (10)(13 ) =173 1 X n=11n(n+ 1)= 1: EX=1X n=1nP(X=n) =1X n=1n1n(n+ 1)=1X n=11n+ 1= +1; EX=X fx:pX(x)>0gxpX(x) =1X
i=1x ipX(xi): EX=X !2SX(!)P(f!g): EX=1X i=1x ip(xi) =1X i=1x iP(X=xi) =1X i=1x i X !2SiP(f!g)! 1X i=1 X !2Six iP(f!g)! =1X i=1X !2SiX(!)P(f!g) X !2SX(!)P(f!g); i=1x iP(X=xi) =X !2SX(!)P(f!g) a2R? ???? ???E[X+Y] =EX+EY? ????E[aX] =aEX? f!2S:X(!) =xg \ f!2S:Y(!) =yg: ?????? ??fxigi2N??? ?????? ????X?? ??????? ??? ??fyjgj2N??? ?????? ????Y?? ??????? EZ=1X k=1z kP(Z=zk) =1X k=1 1X i=1z kP(Z=zk;X=xi)! 1X k=1 1X i=1z kP(X=xi;Y=zkxi)! 1X k=11 X i=11 X j=1z kP(X=xi;Y=zkxi;Y=yj): ???P(X=xi;Y=zkxi;Y=yj)???? ?? ?? ??????zkxi=yj? ??? ???? ????(i;j)? ???j 1 X k=1z kP(X=xi;Y=zkxi;Y=yj) 1X k=1(xi+yj)P(X=xi;Y=zkxi;Y=yj) = (xi+yj)P(X=xi;Y=yj): EZ=1X i=11 X j=1(xi+yj)P(X=xi;Y=yj) 1 X i=11 X j=1x iP(X=xi;Y=yj) +1X i=11 X j=1y jP(X=xi;Y=yj) 1X i=1x i 1X j=1P(X=xi;Y=yj)! +1X j=1y j 1X i=1P(X=xi;Y=yj)! 1X i=1x iP(X=xi) +1X j=1y jP(Y=yj) =EX+EY;E[X+Y] =X
!2S(X(!) +Y(!))P(!) X !2S(X(!)P(!) +Y(!)P(!)) X !2SX(!)P(!) +X !2SY(!)P(!) =EX+EY: ???a2R?? ????E[aX] =X
!2S(aX(!))P(!) =aX !2SX(!)P(!) =aEX ?P(Y= 4) =16EX2=EY= (1)16
+ (4)16 ++ (36)16EX2= (12)16
+ (22)16 ++ (62)16 ;P(X=1) =14 ;P(X= 1) = 38;P(X= 2) =14 ? ???? ??Y=X2?P(Y= 1) =58 ???P(Y= 4) =38
EX2= (1)58
+ (4)38 = (1)214 + (1)238 + (2)218 + (2)214 ??? ???? ?? ???? ????EX2=PEg(X) =1X
i=1g(xi)P(X=xi) =1X EY=X yyP(Y=y) =X yyX fx:g(x)=ygP(X=x) X xg(x)P(X=x):Eg(X) =1X
i=1cp(xi) =c1XVar(X) =E(XM)2
??X EXn=X x:pX(x)>0x npX(x): ??????? ??????? ???? ? ???? ???? ??? ???X= 1?? ?? ??? ??????X=1?? ?? ??? ?????? ????EX= 0? ??XEX=X? ??? ????VarX=EX2= (1)212 + (1)212 = 1? ? ??XEX?????? 52;32 ;12 ;12 ;32 ;52 16
VarX= (52
)216 + (32 )216 + (12 )216 + (12 )216 + (32 )216 + (52 )216 =3512VarX=EX2(EX)2:
VarX=EX22E(XM) +E(M2)
=EX22M2+M2=EX2(EX)2: X=(1?? ??????? ?? ????? ???
0?? ??????? ?? ????? ????
???? ?????X??? ?? ??? ?????? ??????? ????X??? ?????? ??? ????? ??[0;1)?P(X= 0) =P((T;T;T)) =12
3=18P(X= 1) =P((T;T;H);(T;H;T);(H;T;T)) =38
P(X= 2) =P((T;H;H);(H;H;T);(H;T;H)) =38
P(X= 3) =P((H;H;H)) =18
P(X=k) =12
nn k pX(x) =8
:12 x= 0 12 x= 1; pX(i) =eii!;i= 0;1;2;:::;
???? P(X= 0)?P(X= 0) =pX(0) =e00!
=e: ???? P(X >2)?P(X >2) = 1P(X62)
= 1P(X= 0)P(X= 1)P(X= 2) = 1pX(0)pX(1)pX(2) = 1ee2e2E[X] =X
x:p(x)>0xpX(x) =1X
i=1x ipX(xi):EX= 0pX(0) + 1pX(1) =P(T):
EX= 116
+ 216 ++ 616 =16 (1 + 2 + 3 + 4 + 5 + 6) =216 =72 = 3:5: ????X??? ???? ??? ??????0;1;2;3:::????P(X= 0) =23 ?P(X= 1) =29 ;:::;P(X=n) = 23EX= 0pX(0) + 1pX(1) + 2pX(2) +
= 023 + 1232+ 223
3+ 323
4+ 232
1 + 213
+ 3132+ 413
3+ 291 + 2x+ 3x2+;?????x=13
291(1x)2=29
1132=22 2=12
X(4) = 3? ???X(5) =X(6) = 5?
pX(3) =pX(5) =13
EX= 113
+ 313 + 513 =93 = 3:EX=X(1)P(f1g) ++X(6)P(f6g) = 116
+ 116 + 316 + 316 + 516 + 116 = 3: FX(x) :=P(X6x);
??? ???x2R?F(x0) =X
x6x0p X(x): pX(0) =P(X= 0) =18
pX(1) =P(X= 1) =38
pX(2) =P(X= 2) =38
pX(3) =P(X= 3) =18
???? ??? ??? ???X??? ???? ??? ????? ?? ??? ???? FX(x) =8
>>>>:01< x <0; 1806x <1;
4816x <2;
7826x <3;
1 36x <1:
??limx!1F(x) = 1? ??limx!1F(x) = 0? FX(x) =8
>>>>:0x <0; x206x <1;
2316x <2;
111226x <3;
1 36x:
??????? P(X <3)? = limn!1FX31n =111210123400:20:40:60:81
????? ??? ??? ?????? ???FX(x)?? ??????? ????? ??????? P(X= 1)?P(X= 1) =P(X61)P(X <1) =FX(1)limx!1x2
=23 12 =16 ??????? P(2< X64)?P(2< X64) =FX(4)FX(2) =112
P(X=1) = 0:2;
P(X= 0) = 0:5;
P(X= 1) = 0:3:
???Y=X2? ???E[Y]? ????pY(1) = 0:2 + 0:3 = 0:5???pY(0) = 0:5? ?????E[Y] = 00:5 + 10:5 = 0:5?quotesdbs_dbs19.pdfusesText_25[PDF] show the mechanism of acid hydrolysis of ester
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