[PDF] Nondeterministic Finite Automata





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Equivalence of DFAs and NFAs

A non-deterministic finite automaton (NFA) is also Two automata are equivalent if their ... Theorem: Every NFA has an equivalent DFA.



1 Nondeterministic Finite Automata

Find an equivalent deterministic finite automaton. 1.3 Example. Here is a nondeterministic automaton with ? arrows: q r s.



On Equivalence Checking of Nondeterministic Finite Automata

However the problem is much easier when restricted to deterministic finite automata (DFA) where nondeterminism is ruled out. Checking language equiva- lence 



1 Minimizing Finite Automata

Define strings equivalent with respect to a deterministic finite au- Here is an example of a non-minimal finite automaton:.



Forward Bisimulations for Nondeterministic Symbolic Finite Automata

bisimulations of nondeterministic symbolic finite automata. We propose three algorithms. deterministic s-NFA that is equivalent to M [13 Theorem 2].



Non-deterministic Finite Automata

We call this a non-deterministic finite automata (NFA). We say it accepts input x if and only if there exists a path that accepts x. What is the language of 









Size of nondeterministic and deterministic automata for certain

deterministic finite automata (DFA) and nondeterministic finite automata (NFA) these states are equivalent: ?i



Notes on Finite Automata - Rensselaer Polytechnic Institute

3 Equivalence of deterministic and non-deterministic automata De?nition 1 Two automata are equivalent if they accept the same language (functional identity) Given an NDFA we construct an equivalent DFA using a two-step transfor-mation: Step 1: construct an equivalent NDFA without transitions of length > 1; a b S A B C E bb e a a a a b a b



Finite Automata - Washington State University

Non-deterministic Finite Automata (NFA) A Non-deterministic Finite Automaton (NFA) is of course “non-deterministic” Implying that the machine can exist in moreImplying that the machine can exist in more than one state at the same time Outgoing transitions could be non-deterministic q i 1 1 q j • Each transition function therefore



Nondeterministic Finite Automata

Equivalence of DFA’s NFA’s A DFA can be turned into an NFA that accepts the same language If ? D(q a) = p let the NFA have ? N(q a) = {p} Then the NFA is always in a set containing exactly one state – the state the DFA is in after reading the same input

What is the state cost of conversion of nondeterministic finite automata?

It is well-known that the state cost of the conversion of nondeterministic finite automata (1nfas) into equivalent deterministic finite automata (1dfas) is exponential: using the classical subset construction [1], from each n -state 1 nfa we can build an equivalent 1 dfa with 2 n states. Furthermore, this cost cannot be reduced in the worst case.

What is a deterministic finite state automaton?

Formal Definition of A Deterministic Finite State Automaton Definition 1.1 A final state automaton is a 5-tuple , where: 1. Q is a finite set of states; 2. ? is a finite set called the alphabet, 3. ?: Q x ? -> Q is the transition function, 4. q0 ? Q is the start state, 5. F?Q is the set of accept states.

What is the difference between finite state automata and NFA?

This means that there was never any choice about what to do at any step in the computation. e.g. ?(q0, a)=q1 But in a nondeterministic finite state automaton (NFA), a state may have zero, one, or many exiting arrows for each alphabet symbol.

Is the Parikh equivalent 1 DFA a ? polynomially many states?

Furthermore, we prove that this cost is tight. Actually, as a preliminary step, we obtain a result which is interesting per se: if each word accepted by the given 1 nfa A contains at least two different symbols, i.e., it is nonunary, then the Parikh equivalent 1 dfa A ? can be obtained with polynomially many states.

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