Chapter 8: Factoring and Quadratic Equations
Check To check your factored answers multiply your factors out. You should get your original expression as a result. Reading Math. Factoring with More. Than
Chapter 8 Resource Masters
factors must equal 0. 10. A quadratic trinomial has a degree of 4. 11. To solve an equation such as x2 = 8 + 2x take the square root of both sides.
Untitled
How to find the roots of a quadratic equation if they exist. 8-2. The process of changing a sum to a product is called factoring. Can every.
CHAPTER 8 Quadratic Equations and Functions
begun in Chapter 5 when we solved polynomial equations in one variable by factoring. Two additional methods of solving quadratic equations are.
Get Ready for Chapter 8
Fadoring and Quadratit Equations Make this. Foldable to help you organize your Chapter 8 notes about factoring and quadratic equations. Begin with.
STUDENT TEXT AND HOMEWORK HELPER
Solve quadratic equations having real solutions by factoring taking square roots
Whole chapter 8 review Answer key
Ch. 8 Review Compare the widths of the graphs of the given quadratic functions. ... 14. Solve each quadratic equation by factoring. (8-6).
Quadratic Equations and Functions
In Chapter 8 we revisit quadratic equations. In earlier chapters we solved quadratic equations by factoring and applying the zero product rule. In this.
Chapter 8 part 2 group quiz answer key
2) Solve the quadratic equation by factoring. 3) Solve the quadratic equation using square roots. x² -2x = 24. 2.
Study Guide and Review - Chapter 8
Solve each equation by factoring. Confirm your answers using a graphing calculator. 69. a. 2. ? 25 = 0. SOLUTION:.
Searches related to chapter 8 factoring and quadratic equations answers
CHAPTER 8 Quadratic Equations Functions and Inequalities Section 8 1 Solving Quadratic Equations: Factoring and Special Forms Solutions to Even-Numbered Exercises 287 20 z 3 8 8 z 3 8z 3 0 8z 3 z 1 0 8 z2 5z 3 0 4 z2 1 4z2 5z 2 2z 1 2z 1 4z2 5z 2 22 z ±12 z ±144 z2 144 18 u 4 u 4 0 0 u 4 u 1 0 u2 5u 4 6 5u u2 10 6 6u u u2 10 6 u 1 u 10 2
Quadratic
Equations
and Functions8.1Square Root Property and Completing the Square
8.2Quadratic Formula
8.3Equations in Quadratic Form
8.4Graphs of Quadratic Functions
8.5Vertex of a Parabola and Applications551
881.raeqsu( __________ root property)
2.eitgcompln( __________ the square)
3.dqatriuac( ________ formula)
4.taiicidsrmnn
5.aobrplaa(shape of a quadratic function)
6.xteerv(maximum or minimum point on the graph of a parabola)
7.sxia( ________ of symmetry)
1b 2 ?4ac2 IAmiL2872X_ch08_551-618 9/30/06 06:46 AM Page 551CONFIRMING PAGES1. Solving Quadratic Equations by Using
the Square Root Property In Section 5.8 we learned how to solve a quadratic equation by factoring and ap- plying the zero product rule. For example,Set one side equal to zero.
Factor.
orSet each factor equal to zero. orThe solutions are and
It is important to note that the zero product rule can only be used if t he equa- tion is factorable. In this section and Section 8.2, we will learn how to solve quad- ratic equations, factorable and nonfactorable.The first technique utilizes the
square root property.x??9.x?9x??9x?9x?9?0x?9?0 1x?921x?92?0x 2 ?81?0x 2 ?81The Square Root Property
For any real number,k,if .
Note:The solution may also be written as read xequals "plus or minus the square root of k x??1k, x 2 ?k, then x?1k or x??1kSection 8.1Square Root Property and Completing
the SquareConcepts
1.Solving Quadratic Equations by
Using the Square Root Property
2.Solving Quadratic Equations by
Completing the Square
3.Literal Equations
Avoiding Mistakes:
A common mistake is to forget
the symbol when solving the equation : x??1k x 2 ?k?Solving Quadratic Equations by Using
the Square Root Property Use the square root property to solve the equations. a.b.c.Solution:
a.The equation is in the formApply the square root property.
The solutions are Notice that this is the same solution obtained by factoring and applying the zero product rule. b.Rewrite the equation to fit the formThe equation is now in the form
Apply the square root property.
??5ix??1?25 x 2 ?k.x 2 ??253x 2 ??75x 2 ?k.3x 2 ?75?0x?9 and x??9. x??9 x??181 x 2 ?k.x 2 ?811w?32 2 ?203x 2 ?75?0x 2 ?81Example 1
552Chapter 8Quadratic Equations and Functions
IA miL2872X_ch08_551-618 9/30/06 06:46 AM Page 552CONFIRMING PAGES
The solutions are .
Check :Check: c.The equation is in the form whereApply the square root property.
Simplify the radical.
Solve for
wThe solutions are
Use the square root property to solve the equations.1.2.3.
2. Solving Quadratic Equations by Completing
the Square In Example 1(c) we used the square root property to solve an equation where the square of a binomial was equal to a constant. The square of a binomial is the factored form of a perfect square trinomi al. For example:Perfect Square
TrinomialFactored Form
For a perfect square trinomial with a leading coefficient of 1, the constant term is the square of one-half the linear term coefficient. For example: In general an expression of the form is a perfect square trinomial if .The process to create a perfect square trinomial is called completing the square .n?1 1 2 b2 2 x 2 ?bx?n3 1 2 110242 x 2 ?10x?251p?72 2 p 2 ?14p?491t?32 2 t 2 ?6t?91x?52 2 x 2 ?10x?251w?32 2 ?20 1t?52 2 ?188x 2 ?72?0a 2 ?100
Skill Practice
w??3?215 and w??3?215.w??3 ? 215 w?3??215 w?3??22 2 ?5 w?3??120 x?1w?32.x 2 ?k,1w?32 2 ?20?75?75?0?75?75?031?252?75?031?252?75?03125i
22?75?03125i
22?75?031
5 i2 2 ?75?0315i2 2 ?75?03x 2 ?75?03x 2 ?75?0x??5ix?5ix?5i and x??5iSkill Practice Answers
1.2.3.t?5?312x??3ia??10
square of a binomialconstant Section 8.1Square Root Property and Completing the Square553 IA miL2872X_ch08_551-618 9/30/06 06:46 AM Page 553CONFIRMING PAGES
Completing the Square
Determine the value of nthat makes the polynomial a perfect square trinomial. Then factor the expression as the square of a binomial. a.b. c.d.Solution:
The expressions are in the form The value of nequals the square of one-half the linear term coefficient a.Factored form
b.Factored form
c.Factored form
d.Factored form
Determine the value of
nthat makes the polynomial a perfect square trinomial.Then factor. 4.5. 6.7. The process of completing the square can be used to write a quadratic equ a- tion in the form Then the square root prop- erty can be used to solve the equation. The following steps outline the procedure.1x?h2 2 ?k.1a?02ax 2 ?bx?c?0 w 2 ?7 3w? na 2 ?5a?n y 2 ?16y?nx 2 ?20x?nSkill Practice
ax?2 7b 2 n?3 1 2 1? 4 7 242 ?1? 2 7 2 2 4 49
x 2 ?4 7 x? 4 49
x 2 ?4 7 x?n ax?11 2b 2 n?3 1 2 11124
2 ?1 11 2 2 2 121
4 x 2 ?11x? 121
4 x 2 ?11x?n
1x?132
2 n?3 1 21?2624
2 ?1?132 2 ?169.x 2 ?26x?169 x 2 ?26x?n 1x?62 2 n?3 1 2 112242 ?162 2 ?36x 2 ?12x?36 x 2 ?12x?n 1 1 2 b2 2 .x 2 ?bx?n.x 2 ?4 7x? nx 2 ?11x?n x 2 ?26x?nx 2 ?12x?n
Example 2
Skill Practice Answers
4. 5. 6.7.n?49
36; aw?76b
2 n?254; aa?52b
2 n?64; 1y?82 2 n?100; 1x?102 2554Chapter 8Quadratic Equations and Functions
IA miL2872X_ch08_551-618 9/30/06 06:46 AM Page 554CONFIRMING PAGES
Solving a Quadratic Equation in the Form ax
2 ?bx?c?0(a?0) by Completing the Square and Applying the Square Root Property1.Divide both sides by ato make the leading coefficient 1.
2.Isolate the variable terms on one side of the equation.
3.Complete the square. (Add the square of one-half the linear term
coefficient to both sides of the equation. Then factor the resulting perfect square trinomial.)4.Apply the square root property and solve for x.
Solving Quadratic Equations by Completing the
Square and Applying the Square Root Property
Solve the quadratic equations by completing the square and applying the square root property. a.b.Solution:
a.Step 1:Since the leading coefficient
ais equal to 1, we do not have to divide by a. We can proceed to step 2.Step 2:Isolate the variable terms onone side.
Step 3:To complete the square, add
to both sides of the equation.Factor the perfect square
trinomial.Step 4:Apply the square root property.
Simplify the radical.
Solve for
x The solutions are imaginary numbers and can be written as and b. x 2 ?13 2 x?15 2?0 4 x 24?26x4?304?04 4x
2 ?26x?30?0 4xquotesdbs_dbs21.pdfusesText_27[PDF] chapter introduction example
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