[PDF] Le Châteliers Principle Le Châtelier's Principle.





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Les enseignants devraient souligner qu'il faut utiliser le principe de Le Chatelier pour répondre aux questions qui demandent de prédire la direction du 

Le Châtelier"s Principle

Question 1.Suppose the reactionR

P, for whichKeq=[P][R]is at equilibrium and that we add some additionalR, what happens to the concentration ofP? Why?

Answer.

If we addR, then the system no longer is at equilibrium. As increasingRgivesQ < K, we have

too many reactants and not enough products. The reaction, therefore, shift to the right and converts some of

the additionalRtoPuntilQ=Kand equilibrium is reestablished.

Consider this set of equilibrium reactions

AgCl(s)

Ag+(aq) +Cl-(aq)

Ag +(aq) + 2NH3(aq)

Ag(NH3)+2(aq)

NH

3(aq) +H2O(l)

OH-(aq) +NH+4(aq)

Question 2.If you add 0.1 M NaCl to a solution of 0.01 M AgNO3in a test-tube, what happens? Why?

Answer.

A precipitate of AgCl forms to establish the equilibrium required by the reactionAgCl(s) Ag +(aq) +Cl-(aq). Question 3.Now, if you add 3 M NH3to the test-tube from Question 2, what happens? Why?

Answer.

Adding NH3pushes the reactionAg+(aq) + 2NH3(aq)

Ag(NH3)+2(aq)to the right. This, in

turn, decreases the concentration of Ag+, which forces the first reaction to shift to the right to make more

Ag+. If we add enough NH3, the precipitate of AgCl eventually will dissolve. Question 4.If you add 6 M HNO3to the test-tube from Question 3, what happens? Why?

Answer.

Adding HNO3, a strong acid, will decrease the concentration of OH-in the reactionNH3(aq) +

H2O(l)

OH-(aq) +NH+4(aq), causing it to shift to the right. This decreases the concentraiton of NH3, which causes the reactionAg+(aq) + 2NH3(aq) Ag(NH3)+2(aq)to shift to the left. This frees up some

Ag+, which then reprecipitates as AgCl.

Question 5.

Suppose you have the aqueous reactionR1(aq)+R2(aq)

P(aq)with an equilibrium constant

of[P][R1][R2]. What happens to the concentrations ofR1andR2if the volume of the mixture decreases by evaporation? Is the system still at equilibrium? If not, what happens? Why?

Answer.

If we allow the volume to decrease by evaporation, then the concentrations ofR1,R2, andPall

increase (same moles in a smaller volume). Because the denominator has two species and the numerator has

just one species, the resultingQis now smaller thanK, which shifts the reaction to the right untilQ=K.

Note that the effect is to shift the reaction in the direction that contains fewer particles. If we add water,

decreasing the concentrations, then the reaction will shift in the direction that has more particles.

1

Consider this reaction

Co

2+(aq) + 4Cl-(aq)

CoCl2-4(aq)

Question 6.We can use color to study this reaction becauseCo2+is pink andCoCl2-4is blue. If we begin with equilibrium that favors the blue CoCl2-4and add H2O, why does the solution turn pink?

Answer.

From Question 5 we know that diluting a solution makesQ > K, forcing the reaction to shift to the left in the direction that has more particles.

Question 7.

If we start with the reaction from Question 6 at an equilibrium position where the concentrations of Co2+and of CoCl2-4are approximately equal, then the solution appears purple. Why?

Answer.

If the concentrations ofCo2+and ofCoCl2-4are equal, then the solution"s color is the mixture of pink from Co2+and blue from CoCl2-4; thus, it is purple.

Question 8.

If we place half of the solution from Question 7 in an ice bath and half on a hot plate, the

portion in the ice bath turns pink and the portion on the hotplate turns blue. What do the colors tell us

about how this reaction"s equilibrium constant,K, is affected by temperature,T?

Answer.

Based on the colors, decreasing the temperature shifts the reaction toward the reactants, increasing

the concentration ofCo2+and turning the solution pink. Increasing the temperature has the opposite effect,

increasing the concentration ofCoCl2-4and turning the solution blue. We can explain this as a need to

release heat when we cool the mixture and to absorb heat when we warm the mixture. This suggest that the

reaction is endothermic, absorbing heat from the environment whenCo2+formsCoCl2-4and relasing heat when CoCl2-4forms Co2+. 2quotesdbs_dbs46.pdfusesText_46
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