[PDF] 5-2 Study Guide and Intervention - Medians and Altitudes of Triangles





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5-2 - Study Guide and Intervention

Glencoe Algebra 2. Study Guide and Intervention. Dividing Polynomials. 5-2. Long Division To divide a polynomial by a monomial use the skills learned in.



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Study Guide and Intervention Workbook

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Lesson 5-2. PDF Pass. Chapter 5. 11. Glencoe Algebra 2. Study Guide and Intervention. Dividing Polynomials. 5-2. Long Division To divide a polynomial by a 



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5-2 Study Guide and Intervention - Medians and Altitudes of Triangles

5-2 Study Guide and Intervention 2. EU. 3. CU. 4. AD. 5. UF. 6. BE. In ?CDE U is the centroid



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4x³ + x² + 7x - 2) = (x - 2). 1. NAME. DATE. Study Guide and Intervention (continued). Dividing Polynomials. 6-3. Use Synthetic Division. Synthetic division.



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NAME DATE PERIOD 5-2 Study Guide and Intervention

Study Guide and Intervention (continued) Dividing Polynomials 5-2 Synthetic Division Use synthetic division to find (23x- 5x2 + 5x - 2) ÷ (x - 1) Thus (2x3 - 5x2 + 5x - 2) ÷ (x - 1) = 2x2 - 3x + 2 Exercises Simplify 1 (3x3 2- 7x + 9x - 14) ÷ (x - 2) 2 (5x3 + 7x2-x - 3) ÷ (x + 1) 2 3 (2x3 + 3x2 - 10x - 3) ÷ (x + 3) 4 (x3 - 8x2 + 19x



How to Divide Polynomials? - GeeksforGeeks

Study Guide and Intervention Dividing Polynomials Use Long Division To divide a polynomial by a monomial use the properties of powers from Lesson 5-1 To divide a polynomial by a polynomial use a long division pattern Remember that only like terms can be added or subtracted Example l 1 12p3t2r Simplify 12p3t2r 21p2qtr2 9p3tr 12p3t2r



Searches related to 6 2 study guide and intervention dividing polynomials

5-3 Study Guide and Intervention (continued) Dividing Polynomials Use Synthetic Division a procedure to divide a polynomial by a binomial using coefficients of the dividend and Synthetic division the value of rin the divisor x— r Use synthetic division to find (2 3 — 5x2 + 5x — 2) + (x — 1) Use Long Division To divide a polynomial by a

NAME _____________________________________________ DATE ____________________________ PERIOD _____________

Chapter 5 11 Glencoe Geometry

5-2 Study Guide and Intervention

Medians and Altitudes of Triangles

Medians A median is a line segment that connects a vertex of a triangle to the midpoint of the opposite side. The three

medians of a triangle intersect at the centroid of the triangle. The centroid is located two thirds of the distance from a

vertex to the midpoint of the side opposite the vertex on a median.

Example: In ᇞABC, U is the centroid and

BU = 16. Find UK and BK.

7BK 7BK

24 = BK

BU + UK = BK

16 + UK = 24

UK = 8

Exercises:

In ᇞABC, AU = 16, BU = 12, and CF = 18. Find each measure.

1. UD 2. EU

3. CU 4. AD

5. UF 6. BE

In ᇞCDE, U is the centroid, UK = 12, EM = 21, and UD = 9. Find each measure.

7. CU 8. MU

9. CK 10. JU

11. EU 12. JD

8 6 12 24 6 18 24 7

36 4.5

14 13.5

NAME _____________________________________________ DATE ____________________________ PERIOD _____________

Chapter 5 12 Glencoe Geometry

5-2 Study Guide and Intervention (continued)

Medians and Altitudes of Triangles

Altitudes An altitude of a triangle is a segment from a vertex to the line containing the opposite side meeting at a right

angle. Every triangle has three altitudes which meet at a point called the orthocenter.

Example: The vertices of ᇞABC are A(1, 3),

B(7, 7) and C(9, 3). Find the coordinates of the

orthocenter of ᇞABC. Find the point where two of the three altitudes intersect. has a slope of ଵ 6. y ݕଵ = m(x ݔଵ) Point-slope form y 3 = ଵ

6(x 1) m = ଵ

6, (ݔଵ, ݕଵ) = A(1, 3)

y 3 = ଵ

6x ଵ

6 Distributive Property

y = ଵ

6x + ହ

6 Simplify.

Find the equation of the altitude from

7, then the altitude has a slope

of ଷ 6. y ݕଵ = m(x ݔଵ) Point-slope form y 3 = ଷ

6(x 9) m = ଷ

6, (ݔଵ, ݕଵ) = C(9, 3)

y 3 = ଷ

6 Distributive Property

y = ଷ

6x + ଷଷ

6 Simplify.

Solve the system of equations and find where the altitudes meet. y = ଵ

6x + ହ

6 y = ଷ

6x + ଷଷ

6 Original equations

6x + ହ

6 = ଷ

6x + ଷଷ

6 Substitute ଵ

6x + ହ

6 for y.

6 x + ଷଷ

6 Subtract ଵ

6x from each side.

x Subtract ଷଷ

6 from each side.

7 = x Divide each side by 2.

y = ଵ

6x + ହ

6 = ଵ

6 (7) + ହ

6 = ଻

6 + ହ

6 = 6 The coordinates of the orthocenter of ᇞABC are (7, 6).

Exercises:

COORDINATE GEOMETRY Find the coordinates of the orthocenter of the triangle with the given vertices.

1. J(1, 0), H(6, 0), I(3, 6) 2. S(1, 0), T(4, 7), U

(3, 1) (1, 0)quotesdbs_dbs8.pdfusesText_14
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