CMS Math Camps Report Rapport des Camps mathématiques de la
Sujets: Jeux de maths la résolution de problèmes and les présentations sur différents sujets des mathématiques. « On a touché à beaucoup de domaines et
the french baccalauréat curriculum and us math equivalencies
Algebra Geometry
IMO 2020 Solution Notes
and k different finishing points and a cable car which starts higher has the property that the arithmetic mean of the numbers on each pair of cards is.
Course Objectives 1. To understand the basic concepts of
Apply the knowledge in mathematics (algebra matrices
COURSES SCHEME & SYLLABUS
Write compile and debug programs in C language
Mental Discipline Theory and Mathematics Education
Some mental disciplinarians used slightly different labels for the faculties but the discussion by Brooks is representa- tive of mental discipline theory.
Series Convergence Tests Math 122 Calculus III
Math 122 Calculus III. D Joyce Fall 2012. Some series converge
COUNTING LABELLED TREES
reunir les elements d'un sujet interessant et de lecture tres agreable. nn- 3 different trees with n unlabelled nodes and n - 1 edges labelled.
Proceedings of the 13th International Conference on Technology in
10-Nov-2017 for ICT to penetrate mathematics classrooms is not new explained in many research by the "teacher barrier". Will it be different this time?
IB COURSE DESCRIPTIONS 2022-2024
dont les différentes formes littéraires et conventions de genres explorent les les maths et qui désirent approfondir le sujet dans un contexte plus pur.
LABELLEDTREES
J.W.MOON
MadeandprintedinGreatBritainby
longueserie. avaientparusousformedelivre. inbookform. standardforotherstofollow. finitemathematicsorprobabilitytheory. encouragement.Edmonton,Alberta
February,1970
1.Introduction
1.1Definitions
1.2PropertiesofTrees
1.3Summary
AssociatingSequenceswithTrees
2.1PriiferSequences
2.2TreeFunctions
2.4SpecialCases
,3.InductiveArguments3.1SomeIdentities
3.2TreeswithaGivenDegreeSequence
3.4TheNumberofk-Trees
.3.5ForestsofTreeswithSpecifiedRoots3.6ConnectedGraphswithOneCycle
3.7TreeswithaGivenNumberofEndnodes
3.8RecurrenceRelationsforT(n)
4.ApplicationsofGeneratingFunctions
4.1CountingConnectedGraphs
4.2CountingRootedTreesandForests
4.3CountingUnrootedTreesandForests
4.4BipartiteTreesandForests
4.5CountingTreesbyNumberofInversions
4.6ConnectedGraphswithGivenBlocks
5.TheMatrixTreeTheorem
5.1Introduction
5.2TheIncidenceMatrixofaGraph
5.3TheMatrixTreeTheorem
5.4Applications
5.5TheMatrixTreeTheoremforDirectedGraphs
5.6TreesintheArc-GraphofaDirectedGraph
5.7ListingtheTreesinaGraph
6.TheMethodofInclusionandExclusion
6.1Introduction
6.2TheNumberofTreesSpannedbyaGivenForest
6.3TheNumberofSpanningTreesofaGraph
6.4Examples
6.6MiscellaneousResults
7.ProblemsonRandomTrees
7.1RandomMappingFunctions
7.2TheDegreesoftheNodesinRandomTrees
7.3TheDistancebetweenNodesinRandomTrees
7.4TreeswithGivenHeightandDiameter
7.6RemovingEdgesfromRandomTrees
7.7ClimbingRandomTrees
7.8CuttingDownRandomTrees
AuthorIndex
SubjectIndex30
3233
39
39
41
43
46
48
51
52
52
54
54
62
64
66
70
76
78
79
83
86
90
99
i109I112 1 "ii1 graphisanodeofdegreeone.
Figures1and2.
ofanyshortestpathjoiningthem. 1 2Introduction
1111
\23L23623..23. 1 131\23..2
1 13/.23.-\2FIGURE1
-UD~12]--
LLbJManvel(1968».
endnodes. longestpathsinthetree. example,Riordan(1958)andKnuth(1968a). S 732.VI12864
FIGURE4
correspondingsequences. canbeformedfromthenumbers1,2,...,n. sequencecorrespondstosometreeTn. T n betweenthesesequencesandthetreesTn. +6afJy1060 125a 4 4 labelledn.) multinomialcoefficient (n-2)d1-1,...,dn-1. theselatterqnodesequals2(q-I)+p.) root. problemsforadifferenttypeoftree. ofthetype7icalledloops. h). h-1 c(H)=L{rrIr(SI)181-1"lf(SI)I}, f1=1 form somespanningsubtreeofD. sequences. thereare ofnodes. graphs. x"SlS2)-1+(S2SS)-1+...+(ShS1)-1). spanningsubtreestoconsider. thenh c(H)=Il!r(Sj)!St-1stt-1.
COROLLARY2.2.4.
nC1>...,Cte1>...,et (s-l)(r-l)r1-1,...,rT-1.Sl-1,...,ss-1 endnodes. nL:(~)kn-k-1(n-k)k-1=2nn-2;
k=O wherethesumisoverallisuchthataj;::1.THEOREM3.1.Ifn;::3,then
that wherethesumisoverallisuchthatdj;::2. d whenn=3. relation. nAn(x,y;p,q)=L(~)(x+k)k+P(y+n-k)n-k+q.
k=O listedinthefollowingtable. -10x-1(x+y+n)n -1-1(x-1+y-l)(X+Y+n)n-l1-1y-l(x+y+n+f3(xW
2-1y-l{(X+Y+n+f3(x;2))n+(x+Y+n+a+y(x))n}
Theconventionisadoptedthat
a k==ak=k!,f3k(X)==f3ix)=k!(x+k), showthatthereare r"-l(r-1)(8_1)r-1Ck-1 followsfromformula(2.2». appealtoTheorem3.2,weobtaintheidentity n-2) (1965». obtainedfromdifferenttreesRninthisway. nlnodesintheithsubtree,thentherearen-k-lC(n,k)=(n~1)2:C(n-k,t)kt,
t=l (n-1-nl)+...+(n-1-nk)=k(n-1)-(n-1) equalsone. obtaintherecurrencerelation n-k-1C(n,k)=(n~1)L:(n~~~2)(n_k_l)n-k-t-1kt
t=1 =k(n~1)(n-l)n-k-2=(~=:D(n_l)n-k-1.Theorem3.2nowfollowsbyinductiononn.
ofkdisjointtrees). n-cl-kCk(n,d)=(n~k)LCk(n-d,t)(kd)t.
t=1n-kRk(n)=LCk(n,d)={k(n-k)+W-k-1
cl=1 (~)Rin)={k(n-k)+l}Bk(n).THEOREM3.3.If1~k~n,thenF(n,k)=knn-k-1.
Gobel(1963)provedthisbyfirstshowingthat
n-kF(n,k)=L(n~k)ktF(n-k,t);
t=1 (rl+sk-kl)r8-1-1sr-k-1 andinthegeneralcasebyMoon(1967b).Riordan(1964,1968b».
letv=nandu=n-k. whichthecyclehaslengthk,where1~k~n. thenodesatdifferentdistances,wefindthat (x)t=x(x-1)...(x-t+1)fort=1,2,....) inthegraphofjbelongtocycles,then "v"=2:F(t,u,v). theidentity ""knl-1n~2-1nf!.11-1_nn-k-1Itisnotdifficulttoseethat
F(t,u,v)=(~)t!F(O,u-t,v),
""=F(O,u,v)+2:(u)tV"-t-2:(U)t+1V"-T(n)=LR(n,k)=L~iS(n-2,n-k)
1<=21<=2
n-2 =LS(n-2,k)(n)1<=nn-2, 1<=0D(n,k)=(k-I)!(~)F(n,k)=(n)~n-1<-l.
functionsflater.by(3.7).. identityn (2x+l)n=LM(n,k)(x)1<" 1<=0 n x n=LS(n,k)(x)1<" thatthereare n-l x·x n1=L(k+x-k)S(n-1,k)(x)1<
1<=0 n-ln-l =LkS(n-1,k)(x)1<+LS(n-1,k)(x)1<+1>1<=01<=0~:.J{S(s-1,r-k)S(r-1,s-I)
(3.8)S(n,k)=kS(n-1,k)+S(n-1,k-1) thenumberoftreesTnwithexactlykendnodes. kn- 1 consequently, n-l2(n-I)T(n)=L(~)T(OT(n-Oi(n-i).
1=1 moregeneralsetting.)L(-I)f(~)(n-j)k=0
1=0] empty;italsoisequaltoanQk=n!S(k,n). nodes,then n-l2(n-I)nn-2=L(7)il-1(n-on-I-I.
1=1H(n,m,I)=L(-I)1-l(1)(~)C(n-j,m-j)(n-j)f,
1=1] byLemma1.1.Therefore, n-lL(-I)i(~)T(n-j)(n-j)f=0
1=0] yieldsanotherproofofTheorem3.5,since n-lR(n,k)=H(n,n-1,k)=L(-I)f-k(i)(~)(n-j)n-2
1=k] obtaintherelation n2+C.L.T.
equaltothecoefficientofxkin (x+x2+...)1(1+X+x2+..-)n-I=xl(1_x)-n, (-I)k-l(-n)=(k+n-1-I).k-In-lTherefore,
E(n+k,m+k,k)
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