[PDF] Piézoélectricité et application à loptique adaptative Proposition de

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mx+_x+ (kC2)x=Cu mv+_v+ (kC2)v=Cdudt(E) C =24m(kC2) ?????r1+r2==m? v+!0Q _v+!20v=Cm dudt(E) ????t >0? ?? ?u(t) = Cte = E????du=dt= 0????v(0+) = 0? 24
? ?? ?<0????Q >1=2? ??? X =!02Q

1jp4Q21

1 v(t) =Aet=sin(!00t) v

0(t)<0;05v0(0)

t > q=ln(1=0;05) =ln203 ?? ? ????q=2Qln20! 06Q! 0? =qT

0=!00!

0Qln20

!00! 03Q !00! 0Q ????? ??Q1? ?????!00!0? ?? ????? ??? ? Q qC +x=umx+_x+kx+q= 0 (EC) Z= ui= 1j! 1C

2k+j!m!2

Z= kC2j!Ck

1 +j!kC2mkC2!21 +j!k

mk !2 1Ze =jCp!+1R s+1jC s!+jLs! Ze =1j!(Cs+Cp)1 +jRsCs!LsCs!21 +jRsCsCpC s+Cp!LsCsCpC s+Cp!2

8>>>>>><

>>>>>:C p=C C s=2C2kC2 R s= 2C2 L s=m 2C2 ?R Ze =Z=

1j!(Cs+Cp)1LsCs!21LsCsCpC

s+Cp!2 8>>>< s=1pL sCs p=sC p+CsL sCsCp=s1 L s 1C p+1C s

2p!2s!

2s=!p!

s 2

1 =CsC

p1021

2p!2s!

2s= (!p!s)!p+!s!

2s

2(!p!s)!

s =!sQ s=1Q

1051022

!p!s! s ?? ??? ?? ?? ????? ??1=Q= 102? ?!=!s= 1=pL Zs (!s) =1jC s!s+jLs!s= 0 ???? ?? ????P? ZZ

S~Ed~S=Qint"

0 ~E(M) =2"0~n P!M ~E=~0? ??????Q="0Se

Q=C0U??C0="0Se

???????A?? ????? ??????? ?? ??????q??B?? ????? ??????? ?? ??????+q? ??????OB=OA=a=2 ??~p=q!AB? V ~p(M) =q4"0BMq4"0AM=q4"0OM OMBM OMAM

BM=jj!BMjj=q(

!BO+!OM)2=q(a=2)2+OM2+ 2!BO!OM OMBM 112

2!BO!OMOM

2 OMBM OMAM =(!AO!BO)!OMOM

2=~p!OMqOM

2 V ~p(M) =14"0~p!OMOM 3 ~P=d~pd ~p~

P++++++++~p~

P++++++++++polarisation uniformepolarisation non uniforme dV(M) =14"0~

P(A)d!AMAM

3=14"0~P(A)!????A1AM

d 14"0" A ~P(A)AM 1AM ???A~P(A)# d

V(M) =14"0ZZZ

V ??? ~Pr d14"0ZZZ V1r ???~Pd

14"0ZZ

S~ Pr d~S+14"0ZZZ ???~Pr d ~E?

P="0~E

~E=tot"

0=libre+p"

0=libre???~P"

0 ???("0"r~E) =libre

C="0"rSe

= 3;011012F ~Pp=Pp~ux? ??~n= +~ux??? ?? ???? ?? ???? ??~n=~ux??? ?? ???? ?? ???? ?? ? ? ~D???? ????? ??? D=~n ????? ?????? ???? ?? ??????? ?????~ux? ???? ?? ?? ?? ?? ???? ????~D? ?????? ?? ?????? ??~D??? ?????

D=haut~ux=bas~ux=qS

~ux ~D="0~E+~P="0(1 +)~E+"xe ~ux="~E+"xe ~ux qS ="E+"xe ="ue +"xe u=qC +x FS =Exe =)F=SEe x=kx q?? ???? ? u=qC 2k q=qC

0??C0=C1C2=k

C ui=q_qC +x_q

0 =mx_x+_x2+kx_x+q_x

ui=_x2+ddt 12 m_x2+12 kx2+12 q 2C +qx P +v v s"1i i i +=i= 0 ;jvsj Vsat;vs=G"??G! 1 vsv +=R2+R3R v e=R3R1R 2i e

R0=R3R1R

L d2idt2+ (RR0)didt+iC = 0 (RR0)p 1?

Z=jL!+R+1jC!

jZj=sR 2+ L!1C! 2 L!1C! = 0? ???? ??????!=!0=1pLC ????R3> R3c? = 0?? sCs??Q=1R srL sC

2? ?? ??? ??? ?? ?????R1= 3;9k

?R2= 560 ??R3= 1k R s= 7;0k ? ?????Cs=12RsQf0= 3;21014F??Ls=RsQ2f0= 750H?

1 = 0?? ????? ??0???0 = 1?

1PL

2EPElaser(a)(b)

????? ??????? ???1;22D

1;22f=D? ?? ??? ?? ??????

?????? ???? ?????? ?????? ??????? ??? ????R= 1;22D (X;Y) (X;Y) i(X;Y); (X;Y) =(X;Y) 0: h(x;y) =C 0f Z 1 1Z 1 1 (X;Y)e2j(xXf +yYf )dXdY: ???? ????u X=f??v Y=f? ?? ? ????? ? h(x;y) = (fC 0)Z 1 1Z 1 1 (fu;fv)e+2j(xu+yv)dudv: h(x;y) = (fC 0)F1[(fu;fv)](x;y) = (fC 0)F1[(fu;fv)](x;y);

H(u;v) =F[jh(x;y)j2](u;v) =F[hh](u;v) =F[h] F[h];

F[h](u;v) = (fC 0)FF1[(fu;fv)] = (fC 0)(fu;fv):

F[h](u;v) =h

F[h](u;v)i

= (fC 0)h FF

1[(fu;fv)]i

= (fC 0)(fu;fv): ^H(u;v) = (f 0)2jCj2h (fu;fv)(fu;fv)i fjuj> D? ???? ????juj> uc????uc=D=f? PP +TT = 0: (n1)n1= =TT ????n=(n1)T=T:?? ?? ?????? ?

L= ne=(n1)eTT

?????? ? ????n= 1:0002678?e= 0;3??T=1? ??T= 300?? ?? ?????? ?L=

0;27106??

??????Am(X;Y;t) = 18t? ?? ??????? ?

H(u;v;t) =KZ

1 1Z 1 1 ??r n1sini1=n2sini2 i01=i1 1i 2i

01normalerayon

incidentrayon re echirayon 0A 0FLF

0 A1(c)(a)AFLF

0A 0(b) incidentrayon re echimiroirfront d'onde incidentfront d'onde re echi=2normale au miroir(a)miroirfront d'onde incidentfront d'onde re echi(b) ?? ???????f 0f 0h front de l'onde r

0= 2=p200 = 0;14??

quotesdbs_dbs20.pdfusesText_26

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