Worksheet: Logarithmic Function
Write the following equalities in exponential form. (1) log3 81 = 4. (2) log7 7 = 1. (3) log1. 2.
Logarithmic Equations.pdf
Worksheet by Kuta Software LLC. Kuta Software - Infinite Algebra 2. Name___________________________________. Period____. Date________________. Logarithmic
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In this section we explore integration involving exponential and logarithmic functions. Integrals of Exponential Functions. The exponential function is perhaps
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Worksheet by Kuta Software LLC. Rewrite each equation in logarithmic form. 16) 4. 2. = 16. 17) x. −4. = y. 18) m. 3. = n. 19) 12 x. = y. 20) a. −7. = b. Find
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Unit 8: Exponential & Logarithmic Functions
Worksheet. 13. Review. 14. Test. Date ______. Period_________. Unit 8: Exponential & Logarithmic Functions. Page 2. Objective: To model exponential growth.
Worksheet: Logarithmic Function
Write the following equalities in exponential form. (1) log3 81 = 4. (2) log7 7 = 1. (3) log1. 2.
derivative-of-exponential-and-logarithmic-functions.pdf
If you are not familiar with exponential and logarithmic functions you may wish to consult the booklet Exponents and Logarithms which is available from the
Worksheet 2.7 Logarithms and Exponentials
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Mathematics Learning Centre
Derivatives of exponential and
logarithmic functionsChristopher Thomas
c?1997 University of Sydney Mathematics Learning Centre, University of Sydney11Derivatives of exponential and logarithmic func-
tions If you are not familiar with exponential and logarithmic functions you may wish to consult the bookletExponents and Logarithmswhich is available from the Mathematics LearningCentre.
Youmayhave seen that there are two notations popularly used for natural logarithms, log e and ln. These are just two different ways of writing exactly the same thing, so that log e x≡lnx.Inthis booklet we will use both these notations.The basic results are:
d dxe x =e x d dx(log e x)=1 x. Wecan use these results and the rules that we have learnt already to differentiate functions which involve exponentials or logarithms.Example
Differentiate log
e (x 2 +3x+1).Solution
Wesolve this by using the chain rule and our knowledge of the derivative of log e x. d dxlog e (x 2 +3x+1) =d dx(log e u)(whereu=x 2 +3x+1) d du(log e u)×du dx(by the chain rule) 1 u×dudx 1 x 2 +3x+1×ddx(x 2 +3x+1) 1 x 2 +3x+1×(2x+3) 2x+3 x 2 +3x+1.Example
Find d dx (e 3x 2 Mathematics Learning Centre, University of Sydney2Solution
This is an application of the chain rule together with our knowledge of the derivative of e x d dx(e 3x 2 )=de u dxwhereu=3x 2 =de u du×dudxbythe chain rule =e u×du
dx =e 3x 2 ×d dx(3x 2 =6xe 3x 2Example
Find d dx (e x 3 +2xSolution
Again, we use our knowledge of the derivative ofe
x together with the chain rule. d dx(e x 3 +2x )=de u dx(whereu=x 3 +2x) =e u×du
dx(by the chain rule) =e x 3 +2x ×d dx(x 3 +2x) =(3x 2 +2)×e x 3 +2xExample
Differentiate ln(2x
3 +5x 2 -3).Solution
Wesolve this by using the chain rule and our knowledge of the derivative of lnx. d dxln(2x 3 +5x 2 -3) =dlnu dx(whereu=(2x 3 +5x 2 -3) dlnu du×dudx(by the chain rule) 1 u×dudx 1 2x 3 +5x 2 -3×ddx(2x 3 +5x 2 -3) 1 2x 3 +5x 2 -3×(6x 2 +10x) 6x 2 +10x 2x 3 +5x 2 -3. Mathematics Learning Centre, University of Sydney3 There are two shortcuts to differentiating functions involving exponents and logarithms.The four examples above gave
d dx(log e (x 2 +3x+1)) =2x+3 x 2 +3x+1 d dx(e 3x 2 )=6xe 3x 2 d dx(e x 3 +2x )=(3x 2 +2)e 3x 2 d dx(log e (2x 3 +5x 2 -3)) =6x 2 +10x 2x 3 +5x 2 -3.These examples suggest the general rules
d dx(e f(x) )=f (x)e f(x) d dx(lnf(x)) =f (x) f(x). These rules arise from the chain rule and the fact that de x dx =e x and dlnx dx 1 x .They can speed up the process of differentiation but it is not necessary that you remember them. If you forget, just use the chain rule as in the examples above.Exercise 1
Differentiate the following functions.
a.f(x)=ln(2x 3 )b.f(x)=e x 7 c.f(x)=ln(11x 7 d.f(x)=e x 2 +x 3 e.f(x)=log e (7x -2 )f.f(x)=e -x g.f(x)=ln(e x +x 3 )h.f(x)=ln(e x x 3 )i.f(x)=ln x 2 +1 x 3 -x Mathematics Learning Centre, University of Sydney4Solutions to Exercise 1
a.f (x)=6x 2 2x 3 =3 xAlternatively writef(x)=ln2+3lnxso thatf
(x)=31 x. b.f (x)=7x 6 e x 7 c.f (x)= 7 x d.f (x)=(2x+3x 2 )e x 2 +x 3 e.Writef(x)=log e7-2log
e xso thatf (x)=- 2 x f.f (x)=-e -x g.f (x)=e x +3x 2 e x +x 3 h.Writef(x)=lne x 3 lnx so thatf (x)=1+3 x. i.Writef(x)=ln(x 2 +1)-ln(x 3 -x)sothatf (x)=2x x 2 +1-3x 2 -1 x 3 -x.quotesdbs_dbs12.pdfusesText_18[PDF] exponential fourier series for signal
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