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Lesson 8-6 Chapter 8 39 Glencoe Algebra 1 Skills Practice Solving x2 + bx + c = 0 Factor each polynomial 1 t2 + 8t + 12 2 n2 + 7n + 12

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Solve Equations by Factoring Factoring and the Zero Product Property can be used to solve many equations of the form x² + bx + c = 0 0=-16t² +22881 – 6720 0=-

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Chapter 8 40 Glencoe Algebra 1 Practice Solving x2 + bx + c = 0 Factor each polynomial 3 x2 + 14x + 33 (a + 4)(a + 6) (h + 3)(h + 9)

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8-6 Skills Practice Factoring Quadratic Trinomials Factor each polynomial 6 2 + 2x – 8 7 2 + 4r – 12 8 2 – x – 12 9 2 – w – 6

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Lesson 8-7 Chapter 8 45 Glencoe Algebra 1 Skills Practice Solving ax2 + bx + c = 0 Factor each polynomial if possible If the polynomial cannot be

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Lesson 8-6 PDF Pass Chapter 8 39 Glencoe Algebra 1 Skills Practice Solving x2 + bx + c = 0 Factor each polynomial 1 t2 + 8t + 12 2 n2 + 7n + 12

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NAME DATE PERIOD ______ Chapter 8 39 Glencoe Algebra 1 8-6 Skills Practice Solving + bx + c = 0 Factor each polynomial 1 2 + 8t + 12

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Glencoe Algebra 1 8-7 Skills Practice Solving a + bx + c = 0 + 3x – 6 7 2 2 + y – 1 8 4? 2 + 8h – 5 9 4 Solve each equation

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n²-36 = 5n Chapter 8 ACHT 63 CHE Glencoe Algebra 1 Page 6 DATE PERIOD 8-3 Practice Quadratic Equations: x² + bx + c = 0 Factor each polynomial 1

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LESSON Practice B 9 6 Solving Quadratic Equations by Factoring Use the Zero PracticeChapter 8 40 Glencoe Algebra 1 Practice Solving x2 + bx + c = 0

NAME DATE PERIOD 8-6 Skills Practice

8-6 Skills Practice Solving x2 + bx + c = 0 Factor each polynomial 1 t2 + 8t + 12 (t + 2)(t + 6) 3 p2 + 9p + 20 (p + 5)(p + 4) 5 n2 + 3n - 18 (n + 6)(n - 3) 7 y2 - 5y - 6 (y + 1)(y - 6) 9 r2 + 4r - 12 (r - 2)(r + 6) 11 w2 - w - 6 (w - 3)(w + 2) 13 x2 - 8x + 15 (x - 5)(x - 3) 15 t2 - 15t + 56 (t - 7)(t - 8) 2 n2 + 7n + 12

8-6 Solving x2 + bx + c = 0 Review — Multiply using FOIL

Chapter 8 40 Glencoe Algebra 1 Practice Solving x2 + bx + c = 0 Factor each polynomial 1 a 2 + 10a + 24 2 h + 12h + 27 3 x2 + 14x + 33 (a + 4)(a + 6) (h + 3)(h + 9) (x + 11)(x + 3) 4 g2 - 2g - 63 5 w2 + w - 56 6 y2 + 4y - 60 (g + 7)(g - 9) (w + 8)(w - 7) (y + 10)(y - 6) 7 b2 + 4b 2- 32 8 n - 3n - 28 9 t2 + 4t - 45 (b - 4)(b + 8) (n

8-6 Study Guide and Intervention - The Masters Program

8-6 Study Guide and Intervention Solving x2 + bx + c = 0 Factor Û + bx + c To factor a trinomial of the form T2 + bx c find two integers m and p whose sum is equal to b and whose product is equal to c Factoring Û + + bx + c T2 bx + c = (x m)(p) where m p = b and mp c Example 1: Factor each polynomial a Û + 7x + 10 In this trinomial b

8-6 Word Problem Practice - East Brunswick Public Schools

8-6 Word Problem Practice Solving + bx + c = 0 1 COMPACT DISCS A compact disc jewel case has a width 2 centimeters greater than its length The area for the front cover is 168 square centimeters The first two steps to finding the value of x are shown below Solve the equation and find the length of the case Length × width = area 4

Chapter 8 Resource Masters - Commack Schools

Look at the factors of 12 -12 or -144 for a pair whose sum is -7 Enter an equation to determine the factors in Y1and an equation to find the sum of factors in Y2 Examine the table to find a sum of -7 12x2- 7x- 12 = 12x2+ 9x+ (-16x) - 12 = 3x(4x+ 3) - 4(4x+ 3) = (4x+ 3)(3x- 4) Thus 12x2- 7x- 12 = (4x+ 3)(3x- 4)

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