Frequency Response of FIR Filters
A simple FIR filter: y[n]=x[n-n. 0. ] • Therefore from the difference equation
Frequency Response of FIR Filters
For example a low-pass filter might allow low-frequency components of a signal through relatively unchanged
Frequency Response of FIR Filters
Frequency Response of a FIR. 1. When the input is a discrete-time complex exponential signal the output of an FIR filter is also a discrete-time complex
Lecture 13 Frequency Response of FIR Filters
Lecture 13 Frequency Response of FIR. Filters. Fundamentals of Digital Signal Processing. Spring 2012. Wei-Ta Chu. 2012/4/17. 1. DSP
Design of FIR Filters
A general FIR filter does not have a linear phase response but this property is satisfied when Magnitude of Rectangular Window Frequency Response ...
Lecture 14 Frequency Response of FIR Filters 2
19 avr. 2012 ó For the FIR filter with coefficients {b k. }={12
Frequency Response of FIR Filters
DETERMINE the FIR FILTER OUTPUT. • FREQUENCY RESPONSE of FIR. – PLOTTING vs. Frequency. – MAGNITUDE vs. Freq. – PHASE vs. Freq.
UNIT - 7: FIR Filter Design
25 oct. 2016 For a desired frequency response with tight constraints on the passband
Response Maskingfor Efficient Narrow Transition Band FIR Filters
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Low Pass filter. Frequency. Response in dB for 11 and 21 coefficients. Low pass filter phase response for 21-coefficient design
Prof. Nizamettin AYDIN
naydin@yildiz.edu.tr http://www.yildiz.edu.tr/~naydinDigital Signal Processing
2Lecture 12
Frequency Response Frequency Response
of FIR Filtersof FIR FiltersDigital Signal Processing
3License Info for SPFirst Slides
• This work released under a Creative Commons Licensewith the following terms: • Attribution • The licensor permits others to copy, distribute, display, and perform the work. In return, licensees must give the original authors credit. • Non-Commercial • The licensor permits others to copy, distribute, display, and perform the work. In return, licensees may not use the work for commercial purposes-unless they get the licensor"s permission. • Share Alike • The licensor permits others to distribute derivative works only under a license identical to the one that governs the licensor"s work. •Full Text of the License •This (hidden) page should be kept with the presentation 4READING ASSIGNMENTS
• This Lecture: - Chapter 6, Sections 6-1, 6-2, 6-3, 6-4, & 6-5 • Other Reading: - Recitation: Chapter 6 • FREQUENCY RESPONSE EXAMPLES - Next Lecture: Chap. 6, Sects. 6-6, 6-7 & 6-8 5LECTURE OBJECTIVES
• SINUSOIDALINPUT SIGNAL - DETERMINE the FIR FILTER OUTPUT • FREQUENCY RESPONSE of FIR - PLOTTING vs. Frequency - MAGNITUDE vs. Freq - PHASE vs. Freq wwwjeHjjjeeHeHÐ= MAG PHASE 6DOMAINS: Time & Frequency
•Time-Domain: "n" = time -x[n] discrete-time signal -x(t) continuous-time signal •Frequency Domain (sum of sinusoids) - Spectrum vs. f (Hz) - ANALOG vs. DIGITAL - Spectrum vs. omega-hat • Move back and forth QUICKLY 2 7LTI SYSTEMS
• LTI:Linear & Time-Invariant
• COMPLETELY CHARACTERIZED by: -IMPULSE RESPONSEh[n] -CONVOLUTION : y[n] = x[n]*h[n] • The "rule"defining the system can ALWAYS be re- written as convolution • FIR Example: h[n] is same as bk 8POP QUIZ
• FIR Filter is "FIRST DIFFERENCE" -y[n] = x[n] -x[n-1] • Write output as a convolution - Need impulse response - Then, another way to compute the output: ]1[][][--=nnnhdd ()][]1[][][nxnnny*--=dd 9DIGITAL "FILTERING"
• CONCENTRATE on theSPECTRUMSPECTRUM
• SINUSOIDAL INPUT - INPUT x[n] = SUM of SINUSOIDS - Then, OUTPUT y[n] = SUM of SINUSOIDSFILTERD-to-AA-to-Dx(t)y(t)y[n]x[n]
wˆwˆ 10FILTERING EXAMPLE
• 7-point AVERAGER - Removes cosine • By making its amplitude (A) smaller • 3-point AVERAGER - Changes A slightly 6 0 717k knxny 2 0 313
k knxny 11
3-pt AVG EXAMPLE
USE PAST VALUES
400for)4/8/2cos()02.1(][ :Input££++=nnnxnpp
127-pt FIR EXAMPLE (AVG)
CAUSAL: Use Previous
LONGER OUTPUT
400for)4/8/2cos()02.1(][ :Input££++=nnnxnpp
3 13SINUSOIDAL RESPONSE
• INPUT: x[n] = SINUSOID • OUTPUT: y[n] will also be a SINUSOID - Different Amplitude and Phase -SAMEFrequency • AMPLITUDE & PHASE CHANGE - Called the FREQUENCY RESPONSEFREQUENCY RESPONSE 14DCONVDEMO: MATLAB GUI
15COMPLEX EXPONENTIAL
M kM k k knxkhknxbny 00FIR DIFFERENCE EQUATION
¥<<¥-=neAenxnjjwjˆ][
x[n] is the input signal-a complex exponential 16COMPLEX EXP OUTPUT
• Use the FIR "Difference Equation" njjeAeHwjwˆ)ˆ(= M kknjj kM k k eAebknxbny0)(ˆ
0 ][][wj njjM kkj keAeebwjwˆ 0)( 17FREQUENCY RESPONSE
• Complex-valued formula - Has MAGNITUDE vs. frequency - And PHASE vs. frequency • Notation:FREQUENCY
RESPONSE
• At each frequency, we can DEFINE )ˆ(of place in )(ˆwwHeHj kjM k kebHwwˆ0)ˆ(-
=∑=kjM k kjebeHwwˆ0ˆ)(-
18EXAMPLE 6.1
EXPLOIT
SYMMETRY
}1,2,1{}{=kb )ˆcos22()2(21)(ˆˆˆˆˆ2ˆˆwwwwwwww+=++=++=-----
j jjjjjjeeeeeeeH ww w wwˆ)( is Phaseand)ˆcos22()( is Magnitude0)
ˆcos22( Sinceˆˆ-=Ð+=
jjeHeH 4 19PLOT of FREQ RESPONSE
wwwˆˆ)ˆcos22()(jjeeH-+=RESPONSE at pppp/3 }1,2,1{}{=kb (radians)ˆwp-p wˆ 20EXAMPLE 6.2
y[n]x[n])(ˆwjeH wwwˆˆ)ˆcos22()(jjeeH-+= njjjeenxeHny)3/(4/ˆ2][ andknown is )( when][ Findppw= 21njjeenxny)3/(4/2][ when][ Findpp=
EXAMPLE 6.2 (answer)
3/ˆat )( evaluate-Step One ˆpww=jeH
wwwˆˆ)ˆcos22()(jjeeH-+=3/ˆ@3)(3/ˆpwpw==-jjeeH
22EXAMPLE: COSINE INPUT
)cos(2][ andknown is )( when][ Find43ˆppw+=nnxeHny j wwwˆˆ)ˆcos22()(jjeeH-+= y[n]x[n])(ˆwjeH wˆwˆ 23EX: COSINE INPUT
)cos(2][ when][ Find43pp+=nnxny ][][][)cos(221)4/3/()4/3/(43nxnxnxeen
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