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Exercise 11

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  • Comment faire l'analyse d'un croisement ?

    1ère étape : nommer les gènes, allèles et phénotypes en utilisant des lettres. 2ème étape : repérer si les parents P1 et P2 sont - de lignée pure, donc s'ils sont homozygotes - ou s'ils sont hétérozygotes. - Repérer si l'énoncé indique quels sont les caractères dominants.
  • Comment savoir si la maladie est récessive ou dominante ?

    Si la maladie survient quand un seul gène est muté, elle est dominante, • Si la maladie survient seulement quand les deux exemplaires sont mutés, elle est récessive.
  • Les caractéristiques d'une maladie génétique
    S'il est situé sur la paire de chromosomes sexuels, la maladie est dite gonosomale, s'il est localisé sur une paire de chromosomes homologues, la maladie est dite autosomale.
Exercise 11

Aim: Preparation and analysis of Pedigree Charts

Principle: The Mendelian concept of dominance and segregation can also be studied in humans by preparing and then analysing the pedigree charts. The internationally approved symbols for indicating males and females, marriages, various generations (I, II, II

I), etc., are given below.Exercise 11

Requirement: Information about characters/traits in a family for more than one gene ration

Procedure

Select a family in which any one of the monogenic traits such as tongue rolling, widow's peak, blood groups', red-green colour blindness, dim ple in

40LABORATORY MANUAL: BIOLOGY

the cheek, hypertrichosis of ear, hitch-hiker's thumb, etc., is found. Ask the person exhibiting the trait to tell in which of his/her parents, grand p arents (both maternal and paternal), their children and grand children the tr ait in question is present. Among surviving individuals the trait may also be examined. The information made available is the basis for the preparatio n of pedigree chart using the appropriate symbols. A careful examination of t he pedigree chart would suggest whether the gene for the character is autos ome- linked dominant or recessive, X - chromosome linked dominant or recessiv e,

Y- chromosome linked or not.

Explanation

1.Autosome Linked Dominant traits: These are the traits whose

encoding gene is present on any one of the autosomes, and the wild- type allele is recessive to its mutant allele, i.e., the mutant allele i s dominant. The pedigree-chart can be of the undernoted pattern (Fig. 11.2), where the female being interviewed is exhibiting the trait, and is indicated b y an arrow-mark in the chart. The characteristic features of inheritance of such type of traits are: (a)Transmission of traits occurs from parents of either sex. (b)Males and females are equally affected. (c)The pedigree is vertical, i.e., the trait is marked to be present in eac h ofthe generations. (d)Multiple generations are characteristically affected. Brachydactyly, polydactyly, dimple in the cheek are some of the common traits of this type.

41EXERCISE 11

2.Autosomal Recessive trait: These are the traits whose mutant allele is

recessive to its wild type allele. The pedigree chart can be more or less of the pattern given below (Fig.

11.3), where the lady (marked by the arrow) is showing the trait. The

bar in the example represents the presence of corresponding dominant or recessive allele for the specific trait. Suppose the given trait is albinism. Denote its dominant allele as 'A' that produces pigments, and the recessive allele as 'a' that fails to synthesise the pigment, melanin. The female (our subject in generation III) is th erefore of genotype aa. She must have received each of her 'a' allele from both the parents (generation-II), who are therefore themselves normal but are d efinitely of genotype Aa, and are carriers of the trait. The allele a must also ha ve been present in her grand parents too, of course in heterozygous condition al so to make them carriers (generation-I) Albinism in the subject's children (generation-IV) suggests her hus band too to be of genotype Aa, a carrier. Marriage of her albino daughter to an albino man is bound to produce all her grand-children albino (gen-V). The following are the salient features of the inheritance of such type o f traits. (a)Occur in equal proportions in multiple male and female siblings, whose parents are normal but carriers; (b)The siblings are homozygous for the defective allele, but their parents, though some may appear normal, are obviously heterozygous, i.e., are merely carriers of the trait. (c)Consanguinity (marriage between man and woman genetically related to each other, such as cousins) occasionally results in the appearance of such traits.

43EXERCISE 11

Here, the dominant mutant allele is denoted by 'D', and its recess ive wild type allele is denoted by 'd'. Remember that human females have tw o X-chromosomes (XX), and the males have only one X and one Y chromosome Males receive their lone X-chromosome from their mother, and the Y-chromosomes from their father, whereas females receives one of her X-chromosome from her mother, and the other X from her father.

The characteristics of such inheritance are:

(a)The trait appears in almost all the generations, and the inheritance is vertical. (b)If the female is affected, then about half of her sons are affected. (c)If the male is affected then all of his daughters would be affected, but none of his sons are affected. (d)In short, the pedigree resembles the pattern of inheritance of autosomal dominants, except that there is no male-to-male transmission.

4.X-linked Recessive traits: These are the traits whose encoding gene is

present on the X-chromosome and its mutant allele is recessive to its wild-type allele. Red-green colour blindness and hemophilia, are some of its well known examples. The characteristic features of such inheritance are: (a)Females express the trait only when they are homozygous for the mutant allele, whereas the males do so even when they are hemizygous for it. The pedigree chart would appear as the following one (Fig. 11.6):

44LABORATORY MANUAL: BIOLOGY

(b)About half of the sons of the carrier (heterozygous for the trait) fem ales are affected. In case of homozygous females showing the trait, fifty percent of her daughters and all of her sons are likely to be affected. Therefore, the males are most affected in the population. (c)Affected persons are related to one another through the maternal side of their family. (d)Any evidence of male-to-male transmission of the trait rules out the

X- linked inheritance.

5.Y-chromosome linked traits: These are the traits whose gene is present

on the Y-chromosome. The females do not have any Y-chromosome, whereas all the males must have a Y-chromosome to be a male, and this Y-chromosome they get from their father. Therefore, any trait linked to the Y- chromosome must be present only in males, and certainly not in any of the females. This is why these traits are also called male-sex li mited traits. All the sons of the affected male would express the trait wherea s none of his daughters would do so. The pattern of the pedigree chart would be as follows (Fig 11.7): Hypertrichosis of the ear (presence of hairs on pinna) is one most com mon example of such traits.

Questions

1.How will you differentiate between autosome linked dominant and sex chro

mosome linked dominant pedigree chart? Explain.

2.Discuss the differences in the patterns of autosome linked recessive and

sex- chromosome linked pedigree. Note:Students may be asked to prepare the pedigree-chart from given data and analyse the pattern of inheritance. The work may be done as a project.quotesdbs_dbs29.pdfusesText_35
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