[PDF] HOW TO SOLVE PRACTICAL ASPECTS OF MICROBIOLOGY - OCW





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RÉSUMÉ

Dilution 1 : diluer les échantillons de plasma ou de sérum de 1:100 avec le diluant pour échantillon de complément (échantillon de 10 µl + 990 µl de.



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HOW TO SOLVE PRACTICAL ASPECTS OF MICROBIOLOGY - OCW

1:10 dilution = 10 ml of 1:10 dilution (or 10-1 dilution) 1 ml of sample + 9 ml of diluent If a higher dilution of the sample is required successive dilutions can be prepared For example if the 1:100 dilution is needed (or the 10-2 dilution) it can be prepared adding 1 ml of 1:10 dilution to 9 ml of diluent according to the following



Dilution factor: 10X

Final volume = 1000 mL (1 L) Dilution factor: 10X Stock volume: 1000 mL/10 = 100 mL Now you need to calculate the amount of water you will add the 100 mL stock solution to Do this by subtracting 100 mL from the final volume: Final volume: 1000 mL Volume of water to add: 1000 mL – 100 mL = 900 mL

What is a 1 1000 dilution?

What is the dilution factor of 1 1000? You could make 1/1,000 by adding 1 microliter of sample to 0.999 ml diluent. Why is that a poor choice? Because you can’t measure 1 microliter (or even 10 microliters) accurately with ordinary pipeters. So, make three serial 1/10 dilutions (0.1 ml [100 microliters] into 0.9 ml): 1/10 x 1/10 x 1/10 = 1/1,000.

How do you do a 100 fold dilution?

How do you do a 100 fold dilution? For a 1:100 dilution, one part of the solution is mixed with 99 parts new solvent. Mixing 100 µL of a stock solution with 900 µL of water makes a 1:10 dilution. The final volume of the diluted sample is 1000 µL (1 mL), and the concentration is 1/10 that of the original solution. How do you fold a dilution?

What are examples of dilution in chemistry?

What are examples of dilution in chemistry? A dilution is a solution made by adding more solvent to a more concentrated solution (stock solution), which reduces the concentration of the solute. An example of a dilute solution is tap water , which is mostly water (solvent), with a small amount of dissolved minerals and gasses (solutes) .

HOW TO SOLVE PRACTICAL

ASPECTS OF MICROBIOLOGY

1. DILUTIONS AND CONCENTRATIONS. LIQUID AND SOLID SAMPLES

Inés Arana, Maite Orruño & Isabel Barcina

Department of Immunology, Microbiology and Parasitology

University of the Basque Country

Universidad del País Vasco (UPV/EHU)

OCW 2013

1. DILUTIONS AND CONCENTRATIONS. LIQUID AND SOLID

SAMPLES

In most environments, the microbial density is usually too high or too low to obtain good results in the enumeration of microorganisms by a direct culture of the sample. This situation requires the dilution or concentration of the sample prior to carry out any study. Additionally, solid samples must be diluted for an easier handling, in this way; they can be treated as liquid samples. In most cases, we work with decimal dilutions. The simplest case is the preparation of 10 ml of the

1:10 dilution of the sample. For this, 1 ml of sample is added to 9 ml of diluent; consequently, in 10 ml

of this 1:10 dilution, 1 ml corresponds to the sample. Expressing by an equation:

1 ml of sample

1:10 dilution = 10 ml of 1:10 dilution (or 10

-1 dilution)

1 ml of sample + 9 ml of diluent

If a higher dilution of the sample is required, successive dilutions can be prepared. For example, if the

1:100 dilution is needed (or the 10

-2 dilution), it can be prepared adding 1 ml of 1:10 dilution to 9 ml of diluent, according to the following equation:

1 ml of 10

-1 dilution

1:100 dilution = 10 ml of 1:100 dilution (10

-2)

1 ml of 10

-1 dilution + 9 ml of diluent Or directly, adding 1 ml of sample to 99 ml of diluent:

1 ml of sample

1:100 dilution = 100 ml of 1:100 dilution (10

-2)

1 ml of sample + 99 ml of diluent

Or adding 0.1 ml of sample to 9.9 ml of diluent:

0.1 ml of sample

1:100 dilution = 10 ml of 1:100 dilution (10

-2)

0.1 ml of sample + 9.9 ml of diluent

Note: The final volume obtained is given by the denominator of the equation. With these notions, you must propose solutions to the following problems:

1.1. How would you prepare 250 ml of a 10

-1 dilution from a water sample?

1.2. How would you prepare 10 ml of a 10

-5 dilution in 3 steps?

What if the sample is not liquid, for example, a food sample? In this case, we can consider that 1 gram

of sample is equal to 1 ml:

1 g of sample

1:10 dilution = 10 ml of 1:10 dilution (10

-1)

1 g of sample + 9 ml of diluent

1.3. 1.5 grams of food were added to 13.5 ml of Ringer Solution (diluent) and homogenized. What is

the resultant dilution? As previously indicated, sometimes, due to the low density of microorganisms, it is necessary to

concentrate the sample by filtration or centrifugation. This fact requires for subsequent handling, the

resuspension of the microbes retained in the filters or accumulated in the pellets in a given volume of

diluent. In this case, it is necessary to determine the concentration factor. For example:

10 ml of filtered sample

Concentration factor = 1 ml 10X concentrate

1 ml of diluent

1.4. 100 ml of a water sample were filtered, and then the filter was suspended in 10 ml of saline

solution and shaked vigorously. What is the concentration factor?

1.5. 100 ml of a dense microbial suspension were centrifuged at 5,000 rpm. The supernatant was

removed and the pellet was resuspended after adding 2.5 ml of diluent. What is the concentration factor? We must know not only how to dilute or concentrate a sample; we must also understand how to properly apply the dilution or concentration factors to determine the microbial density of a sample. Here are some problems based on the enumeration of microorganisms by the method of counting colony forming units (CFU).

A colonies

CFU/ml = X Dilution Factor

B volume plated (ml)

A colonies 1 CFU/ml = X B volume plated (ml) Concentration Factor

1.6. We have prepared the followings dilutions from different sample: 1:10, 1:5, 1:4 and 1:2. Then,

0.1 ml of each dilution is plated. After incubation, in all cases 27 colonies grew in the plates,

which are the microbial densities of the samples?

1.7. A food sample was processed following this protocol:

· 15 g of food were added to 135 ml of Ringer solution and homogenized. · 2 ml of the suspension were mixed with 18 ml of diluent and homogenized. · 0.2 ml were plated on nutrient agar and incubated.

· 100 colonies were counted in the plate.

From this information, how many microorganisms were present per gram of food?

SOLUTIONS

225 ml

SAMPLE

1.1. 250 ml of a 10-1 dilution

25 ml sample/(25 ml sample + 225 ml diluent)

1.2. 10 ml of a 10-5 dilution in 3 steps

There are other options, for example:

25 ml

1 ml 0,1 ml 0,1 ml

SAMPLE

9 ml 9,9 ml 9,9 ml

10-1 10-3 10-5

1:10 1:10 x 1:100 1:1,000 x 1:100

1:1,000 1:100,000

0,1 ml 0,1 ml 1 ml

SAMPLE

9.9 ml 9.9 ml 9 ml

10-2 10-4 10-5

1:100 1:100 x 1:100 1:10,000 x 1:10

1:10,000 1:100,000

27 colonies x 101

1:10 dilution: = 2.7 10

3 CFU/ml

0.1 ml plated

27 colonies x 5

1:5 dilution: = 1.35 10

3 CFU/ml

0.1 ml plated

27 colonies x 4

1:4 dilution: = 1.08 10

3 CFU/ml

0.1 ml plated

27 colonies x 2

1:2 dilution: = 5.4 10

2 CFU/ml

0.1 ml plated

100 colonies x 10 x 10

= 5 10

4 CFU/g

0.2 ml plated

1.3. 1.5 g food + 13.5 ml diluent. Dilution?

1.5 g sample/(1.5 g sample + 13.5 ml diluent) = 1,5/15 = 1/10

1.4. 100 ml filtered and resuspended in 10 ml of diluent. What is the concentration factor?

100 ml sample/10 ml diluent = 10101010

1.5. 100 ml centrifugated and resuspended in 2.5 ml of diluent. Concentration factor?

100 ml sample/2.5 ml diluent = 44440000

1.6..1:10, 1:5, 1:4 and 1:2 dilutions. 1 plate/dilution. 0.1 ml/plate. 27 colonies/plate. CFU/ml?

1.7. 15 g sample + 135 ml diluent = 15:150 dilution = 1:10

2 ml 1:10 dilution + 18 ml diluent = 2 :20 dilution = 1 :10

Volume spread = 0.2 ml. Colonies/plate = 100 colonies. Microorganisms/g food?quotesdbs_dbs35.pdfusesText_40
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