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Is a function injective or surjective?

    A function is injective (an injection or one-to-one) if every element of the codomain is the image of at most one element from the domain. A function is surjective (a surjection or onto) if every element of the codomain is the image of at least one element from the domain. A bijection is a function which is both an injection and surjection.

What is the difference between surjective and injective?

    Surjective: If f: P ? Q is a surjective function, for every element in Q, there is at least one element in P, that is, f (p) = q. Injective: If f: P ? Q is an injective function, then distinct elements of P will be mapped to distinct elements of Q, such that p=q whenever f (p) = f (q).

What is injective function f x y?

    A function f : X ? Y is defined to be one-one (or injective), if the images of distinct elements of X under f are distinct, i.e., for every x1, x2 ? X, there exists distinct y1, y2 ? Y, such that f (x1) = y1, and f (x2) = y2. The injective function can be represented in the form of an equation or a set of elements.

What is injectivity in math?

    Recap: Injectivity ?A function is injective(one-to-one) if every element in the domain has a unique image in the codomain –That is, f(x) = f(y) implies x= y NY MA CA Albany Sacramento Boston ...
Functions Surjective/Injective/Bijective - University of Limerick

Functions

Surjective/Injective/Bijective

Aim To introduce and explain the following properties of functions: \surjective", \injective" and \bijective".

Learning Outcomes

At the end of this section you will be able to:

²Understand what is meant by surjective, injective and bijective,

²Check if a function has the above properties.

Surjective Functions

Letf:A!Bbe an arbitrary function with domainAand codomainB. Part of the de¯nition of a function is that every member ofAhas an image underfand that all the images are members ofB; the setRof all such images is called the range of the function f. ThusR=f(A) and clearlyRµB. If it should happen thatR=B, that is, that the range coincides with the codomain, then the function is called asurjectivefunction. De¯nition :A functionf:A!Bis ansurjective, oronto, function if the range of fequals the codomain off. In every function with rangeRand codomainB,RµB. To prove that a given function is surjective, we must show thatBµR; then it will be true thatR=B. We must therefore show that an arbitrary member of the codomain is a member of the range, that is, that it is the image of some member of the domain. On the other hand, if we can produce one member of the codomain that is not the image of any member of the domain, then we have proved that the function is not surjective. To show that a function is surjective pick an arbitrary element in the codomain and show that it has a preimage in the domain. Graph the following function and check is it surjective? f:R! fxjx >0g; f(x) =ex

Functions

The codomain isx >0. By looking at the graph of the functionf(x) =exwe can see thatf(x) exists for all non-negative values, i.e. for all values ofx >0. Hence the range of the function isx >0. This means that the codomain and the range are identical and so the function is surjective. Graphically speaking, if it is possible to draw a horizontal line across the graph of a function without making contact with the curve representing the function then the function is not surjective.

Graph the following two functions

f:R!R; f(x) =x3; f:R!R; f(x) =x2: and check to see if they are surjective. The answers are (1) yes, (2) no. Can you see why?

Injective Functions

The de¯nition of a function guarantees a unique image of every member of the domain. A given member of the range may have more that one preimage, however. If this is the case then the function is notinjective. De¯nition :A functionf:A!Bisinjective, orone-to-one, if no member ofBis the image underfof two distinct elements ofA. To show that a function is injective, we assume that there are elementsa1anda2of

Awithf(a1) =f(a2) and then show thata1=a2.

Graphically speaking, if a horizontal line cuts the curve representing the function at most once then the function is injective. Test the following functions to see if they are injective. f:R!R; f(x) =x3; f:R!R; f(x) =x2; f: [0;1)!R; f(x) =x2;

Functions

Solutions:

Injective

Not Injective

Injective

Bijective Function

De¯nition :A functionf:A!Bisbijective(abijection) if it is bothsurjective andinjective. Iff:A!Bis injective and surjective, thenfis called aone-to-one correspondence betweenAandB. This terminology comes from the fact that each element ofAwill then correspond to a unique element ofBand visa versa. Which of the following functions are surjective, injective and bijective ? f:R!R; f(x) =x3; f:R!R; f(x) = 2x; f:R!R; f(x) =x3¡2x2¡5x+ 6;

Plotting the above functions with Maple may help.

Related Reading

Gersting, J.L. 2007.Mathematical Structures for Computer Science. 6thEdition. Free- man & Company.quotesdbs_dbs7.pdfusesText_5
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