[PDF] [PDF] PHYS 445 Lecture 18 - Maxwell-Boltzmann distribution 18





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PHYS 445 Lecture 18 - Maxwell-Boltzmann distribution18 - 1

© 2001 by David Boal, Simon Fraser University. All rights reserved; further resale or copying is strictly prohibited.

Lecture 18 - Maxwell-Boltzmann distribution

What's Important:

· mean speeds

· molecular flux

Text: Reif

Mean speeds

The Maxwell-Boltzmann speed distribution that was derived in the previous lecture has the appearance where F(v) dv is the number of particles per unit volume with a speed between v and v+dv. Now, there are three common measures of the velocity distributionv 21/2

ºvrms(rootmeansquarespeed)v º(meanspeed)

˜ v º(mostlikelyspeed).

These quantities are straightforward to calculate, and the details can be found in Reif. Root mean squareOne can work through the integral of F(v) to obtain vrms, or just invoke the equipartition theorem in three dimensions:3 2k

BT=[meankineticenergy]=1

2mv 2or v rms=3kBT m.(18.1)

MeanEvaluate the integralv =1

nvF(v)dv=8 pk BT m0

ò(18.2)

Most likelyDetermine the derivativedF(v)

dv=0Þ˜ v =2kBT m(18.3)0 vF(v) PHYS 445 Lecture 18 - Maxwell-Boltzmann distribution18 - 2

© 2001 by David Boal, Simon Fraser University. All rights reserved; further resale or copying is strictly prohibited.

From these results, one can see that all the factors outside (kBT /m)1/2 have similar values

Ö3 = 1.73

(8/p)1/2 = 1.60

Ö2 = 1.41,

so that an order-of-magnitude estimate for the mean speed is (kBT /m)1/2, just as the kinetic energy is ~ kBT. ExampleFind the rms velocity of a gas of neon atoms at T = 300 K (near room temperature); mNe ~ 20mp = 20 • 1.67 ´ 10-27 kg.v rms=3•1.38´10-23•300

20•1.67´10-27ae

ø 1/2

=610m/s.

Molecular flux

Among the quantities that we wish to measure are the pressure and effusion rate, both of which require a knowledge of the molecular flux, the number of particles passing through a unit area in unit time. We start with a simple calculation in one dimension, before treating the general problem in three dimensions.

One dimension

Let the system have a linear density of n particles per unit length (linear, since the system is confined to one dimension). At any given time, n /2 of them are moving to the left, and n /2 to the right. For a specific speed v the particles capable of striking the wall in time t lie within a distance vt of it.

Allowing for a distribution of speeds, the number of particles hitting the wall isnumber=v t•n2=v n

2t Dividing by t gives the number of particles hitting per unit timenumberperunittime=v n

2(18.4)n /2 to the right

vt PHYS 445 Lecture 18 - Maxwell-Boltzmann distribution18 - 3

© 2001 by David Boal, Simon Fraser University. All rights reserved; further resale or copying is strictly prohibited.

Three dimensions

This calculation can be easily extended to include the number hitting a unit area on a wall. [number hitting wall area A in time t with velocity v] = f(v) d 3v • A vt cos.(18.5) number pervolume of unit volumecalpture cylinder

The volume of the capture cylinder arises from

Dividing Eq. (18.5) by the area A and time t gives [number hitting wall per area A per unit time t with velocity v] = f(v) v cos d 3v.(18.6) The flux is obtained by integrating Eq. (18.6) over all velocities v: = ò f(v) v cos d 3v.(18.7)

Details:

d

3v = sin d d v 2dvso = ò f(v) v cos sin d d v 2dv.

Because only right-moving particles will hit A, the integral runs only over 0 to p/2:sincosd= 0p/2 cosdcos0 1 =1 2cos 20 1=1

2òd = 2parea = Awall

A vt[volume] = Avt cos PHYS 445 Lecture 18 - Maxwell-Boltzmann distribution18 - 4

© 2001 by David Boal, Simon Fraser University. All rights reserved; further resale or copying is strictly prohibited.

leaving = 2p • (1/2) ò f(v) v 3dv = p ò f(v) v 3dv.

But the mean speed isv =4p

nv

3f(v)dvòso

14nv (18.8)

Comparing with Eq. (18.4), the flux is less in 3D than in 1D because the velocities are averaged over directions, and vz is less than v. This equation can be massaged in a variety of ways once the ideal gas law has been established.

Effusion

The Maxwell-Boltzmann predictions for the velocity distributions has been tested experimentally through a process known as effusion. A tiny hole is drilled in a container, and the velocities of the escaping molecules are measured by means of two co- rotating disks, acting as choppers to select the molecular velocities: Because it is sensitive to the escape rate of molecules through the hole, this technique measures the flux [ ~ f(v)v 3], not f(v) itself.axis of rotationquotesdbs_dbs21.pdfusesText_27
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