Engineering Formula Sheet
Engineering Formulas. Engineering Formula Sheet. Probability. Pk = n!(pk)(qn-k) k!(n-k)! AMA = Actual Mechanical Advantage. DE = Effort Distance.
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An understanding of what Mechanical Engineering is and to a lesser extent what professional society for mechanical engineers) the Formula SAE racecar.
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Hun 15 2022 introduce his experience how to teach the courses in mechanical engineering technology at RIT using Excel spreadsheets. The case study in ...
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Engineering Formula Sheet Probability Pk = n!(pk)(qn-k) Pk = binomial probability of k successes in n trials AMA = Actual Mechanical Advantage
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What formulas do mechanical engineers use?
There are thousands of Mechanical Engineering formulas. These formulas are used in the design of various Mechanical equipment.22 jan. 2023How many formulas are there in mechanical engineering?
The distance formula is used for finding the distance between two points. In two dimensions it is simply an application of the Pythagorean theorem. Given two points (x1,y1) and (x2,y2) the distance between them is: d=?(x2?x1)2+(y2?y1)2.What is distance formula in mechanical engineering?
The unit of stress is N/mm2 or N/m2 When an external force acts on a body, the body tends to undergo deformation. Due to cohesion between molecules the body resist the force. This resistance offered by the body is known as strength of material. 1 N/mm2 =106N/m2 1 bar = 1x105N/m2 2.
FUNDAMENTALS OF ENGINEERING
SUPPLIED-REFERENCE HANDBOOK
FIFTH EDITION
NATIONAL COUNCIL OF EXAMINERS
FOR ENGINEERING AND SURVEYING
???? 2001 by the National Council of Examiners for Engineering and Surveying®.N C E E S
FUNDAMENTALS OF ENGINEERING
SUPPLIED-REFERENCE HANDBOOK
FIFTH EDITION
Prepared by
National Council of Examiners for Engineering and Surveying (NCEES280 Seneca Creek Road
P.O. Box 1686
Clemson, SC 29633-1686
Telephone: (800) 250-3196
Fax: (864) 654-6033
www.ncees.org ? 2001 by the National Council of Examiners for Engineering and SurveyingAll rights reserved. First edition 1996
Fifth edition 2001
iiiFOREWORD
During its August 1991 Annual Business Meeting, the National Council of Examiners for Engineering and Surveying (NCEES)
voted to make the Fundamentals of Engineering (FE) examination an NCEES supplied-reference examination. Then during its
August 1994 Annual Business Meeting, the NCEES voted to make the FE examination a discipline-specific examination. As a
result of the 1994 vote, the FE examination was developed to test the lower-division subjects of a typical bachelor engineering
degree program during the morning portion of the examination, and to test the upper-division subjects of a typical bachelor
engineering degree program during the afternoon. The lower-division subjects refer to the first 90 semester credit hours (five
semesters at 18 credit hours per semester) of engineering coursework. The upper-division subjects refer to the remainder of the
engineering coursework.Since engineers rely heavily on reference materials, the FE Supplied-Reference Handbook will be made available prior to the
examination. The examinee may use this handbook while preparing for the examination. The handbook contains only reference
formulas and tables; no example questions are included. Many commercially available books contain worked examples and
sample questions. An examinee can also perform a self-test using one of the NCEES FE Sample Questions and Solutions books
(a partial examination), which may be purchased by calling (800) 250-3196.The examinee is not allowed to bring reference material into the examination room. Another copy of the FE Supplied-Reference
Handbook will be made available to each examinee in the room. When the examinee departs the examination room, the FE
Supplied-Reference Handbook supplied in the room shall be returned to the examination proctors.The FE Supplied-Reference Handbook has been prepared to support the FE examination process. The FE Supplied-Reference
Handbook is not designed to assist in all parts of the FE examination. For example, some of the basic theories, conversions,
formulas, and definitions that examinees are expected to know have not been included. The FE Supplied-Reference Handbook
may not include some special material required for the solution of a particular question. In such a situation, the required special
information will be included in the question statement.DISCLAIMER: The NCEES in no event shall be liable for not providing reference material to support all the
questions in the FE examination. In the interest of constant improvement, the NCEES reserves the right to
revise and update the FE Supplied-Reference Handbook as it deems appropriate without informing interested
parties. Each NCEES FE examination will be administered using the latest version of the FE Supplied-Reference Handbook.
So that this handbook can be reused, PLEASE, at the examination site,DO NOT WRITE IN THIS HANDBOOK.
vTABLE OF CONTENTS
CONVERSION FACTORS............................................................................................................2
S D MECHANICS OF MATERIALS.....................................................................................................33
FLUID MECHANICS...................................................................................................................38
T HEAT TRANSFER......................................................................................................................58
TRANSPORT PHENOMENA.........................................................................................................63
C MATERIALS SCIENCE/STRUCTURE OF MATTER........................................................................68
ELECTRIC CIRCUITS.................................................................................................................72
COMPUTERS, MEASUREMENT, AND CONTROLS........................................................................76
ENGINEERING ECONOMICS.......................................................................................................79
E CHEMICAL ENGINEERING.........................................................................................................88
CIVIL ENGINEERING.................................................................................................................92
ENVIRONMENTAL ENGINEERING............................................................................................117
ELECTRICAL AND COMPUTER ENGINEERING..........................................................................134
INDUSTRIAL ENGINEERING.....................................................................................................143
MECHANICAL ENGINEERING..................................................................................................155
I 1 UNITSThis handbook uses the metric system of units. Ultimately, the FE examination will be entirely metric. However, currently some
of the problems use both metric and U.S. Customary System (USCS). In the USCS system of units, both force and mass are
called pounds. Therefore, one must distinguish the pound-force (lbf) from the pound-mass (lbm). The pound-force is that force which accelerates one pound-mass at 32.174 ft/s 2 . Thus, 1 lbf = 32.174 lbm-ft/s 2 . The expression32.174 lbm-ft/(lbf-s
2 ) is designated as g c and is used to resolve expressions involving both mass and force expressed as pounds. For instance, in writing Newton's second law, the equation would be written as F = ma/g c , where F is in lbf, m in lbm, and a is in ft/s 2 Similar expressions exist for other quantities. Kinetic Energy: KE = mv 2 /2g c , with KE in (ft-lbf); Potential Energy: PE = mgh/g c with PE in (ft-lbf); Fluid Pressure: p = ρgh/g c , with p in (lbf/ft 2 ); Specific Weight: SW = ρg/g c , in (lbf/ft 3 ); Shear Stress: τ = (μ/g c )(dv/dy), with shear stress in (lbf/ft 2 ). In all these examples, g c should be regarded as a unit conversion factor. It isfrequently not written explicitly in engineering equations. However, its use is required to produce a consistent set of units.
Note that the conversion factor g
c [lbm-ft/(lbf-s 2 )] should not be confused with the local acceleration of gravity g, which has different units (m/s 2 ) and may be either its standard value (9.807 m/s 2 ) or some other local value. If the problem is presented in USCS units, it may be necessary to use the constant g c in the equation to have a consistent set of units.METRIC PREFIXES
Multiple Prefix Symbol
COMMONLY USED EQUIVALENTS
1 gallon of water weighs 8.34 lbf
1 cubic foot of water weighs 62.4 lbf
1 cubic inch of mercury weighs 0.491 lbf
The mass of one cubic meter of water is 1,000 kilogramsTEMPERATURE CONVERSIONS
10 -18 10 -15 10 -12 10 -9 10 -6 10 -3 10 -2 10 -1 10 1 10 2 10 3 10 6 10 9 10 12 10 15 10 18 atto femto pico nano micro milli centi deci deka hecto kilo mega giga tera peta exa a f p n m c d da h k M G T PE ºF = 1.8 (ºC) + 32
ºC = (ºF - 32)/1.8
ºR = ºF + 459.69
K = ºC + 273.15
FUNDAMENTAL CONSTANTS
Quantity Symbol Value Units
electron charge e 1.6022 × 10 -19C (coulombs)
Faraday constant
96,485 coulombs/(mol)
gas constant metricR 8,314 J/(kmol·K)
gas constant metricR 8.314 kPa·m
3 /(kmol·K) gas constant USCSR 1,545 ft-lbf/(lb mole-ºR)
R 0.08206 L-atm/mole-K
gravitation - newtonian constant G 6.673 × 10 -11 m 3 /(kg·s 2 gravitation - newtonian constant G 6.673 × 10 -11N·m
2 /kg 2 gravity acceleration (standard) metric g 9.807 m/s 2 gravity acceleration (standard) USCS g 32.174 ft/s 2 molar volume (ideal gas), T = 273.15K, p = 101.3 kPa V m22,414 L/kmol
speed of light in vacuum c 299,792,000 m/s 2CONVERSION FACTORS
Multiply By To Obtain Multiply By To Obtain
acre 43,560 square feet (ft 2 ) joule (J) 9.478×10 -4 Btu ampere-hr (A-hr) 3,600 coulomb (C) J 0.7376 ft-lbf -10 meter (m) J 1 newton·m (N·m) atmosphere (atm) 76.0 cm, mercury (Hg) J/s 1 watt (W) atm, std 29.92 in, mercury (Hg) atm, std 14.70 lbf/in 2 abs (psia) kilogram (kg) 2.205 pound (lbm) atm, std 33.90 ft, water kgf 9.8066 newton (N) atm, std 1.013×10 5 pascal (Pa) kilometer (km) 3,281 feet (ft) km/hr 0.621 mph bar 1×10 5Pa kilopascal (kPa) 0.145 lbf/in
2 (psi) barrels-oil 42 gallons-oil kilowatt (kW) 1.341 horsepower (hp)Btu 1,055 joule (J) kW 3,413 Btu/hr
Btu 2.928×10
-4 kilowatt-hr (kWh) kW 737.6 (ft-lbf )/secBtu 778 ft-lbf kW-hour (kWh) 3,413 Btu
Btu/hr 3.930×10
-4 horsepower (hp) kWh 1.341 hp-hrBtu/hr 0.293 watt (W) kWh 3.6×10
6 joule (J)Btu/hr 0.216 ft-lbf/sec kip (K) 1,000 lbf
K 4,448 newton (N)
calorie (g-cal) 3.968×10 -3 Btu cal 1.560×10 -6 hp-hr liter (L) 61.02 in 3 cal 4.186 joule (J) L 0.264 gal (US Liq) cal/sec 4.186 watt (W) L 10 -3 m 3 centimeter (cm) 3.281×10 -2 foot (ft) L/second (L/s) 2.119 ft 3 /min (cfm) cm 0.394 inch (in) L/s 15.85 gal (US)/min (gpm) centipoise (cP) 0.001 pascal·sec (Pa·s) centistokes (cSt) 1×10 -6 m 2 /sec (mquotesdbs_dbs10.pdfusesText_16[PDF] mechanical engineering handbook pdf
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