[PDF] Shift (Caesar) Ciphers If you have a message you want to transmit





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Shift (Caesar) Ciphers If you have a message you want to transmit

A shift cipher involves replacing each letter in the message by a letter that is some fixed number of positions further along in the alphabet.



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9 févr. 2011 Caesar Cipher: Pick a number between 1 and 25. We are now going to shift the whole alphabet to the right so that each letter is replaced by ...



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Because Friedman denoted this number by the Greek letter kappa ? it is sometimes called the Kappa Test. Page 3. English plaintext. The frequencies of the 



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convenient to assign numbers to these letters and the most natural numbering changing ciphertext back into plaintext is called decoding or decryption.



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Now we will generalize this cipher to mx + y (mod 26) where m stands for a letter in the alphabet (counting from A = 0 to Z= 25) and x



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to using the letter with which the cipher alphabet starts. We can then define our encryption function En(x) that takes in the plaintext number x and returns 



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plaintext letters were replaced by other letters or numbers or symbols. Another type of cipher is the transposition cipher. Transposition ciphers use.



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• Choose a key t which is a number between 0 and 25 (for Cæsar t was always 3) • For each letter P E is de?ned by E(P) = P + t i e add t to the code for each letter to get a new letter code If you wind up with a number over 25 loop around to the beginning (like on a clock going past midnight) So e g 25+3 = 2 4



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Fill in the middle line with the message you'd like to encrypt: Pick your code word and write it on top (including the shifts these letters correspondto) Also convert your message letters to the corresponding numbers they represent: Repeat the code across the top then add down the numbers (mod 26) and convertthose number back into letters:



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Thus the correct encryption formula is c p+2mod26 (3) The congruence (3) can be solved forp: p c?2mod26 (4) One of the necessary components of an encryption method is that a ciphertext should be easily coded and decoded by anyone who knows the method and very di cult by someone doesn’t



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alphabetic characters are removed So the number of the possible keys is equal to 26! =4 ×1026 Table 2 illustrates an encryption and decryption example of a simple substitu-tion cipher For the encryption all ‘A’s in the plain text are replaced by letter ‘X’ ‘B’s replaced by ‘E’ etc For the de-



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A Caesar cipher wheel Your secret key is a number ƒ between 1 and 25 To encrypt a letter start at that letter and then count ƒ



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Putting these together we see that the code number used to encrypt column 9 is between 79 and 89 which correspond to the letters o – y If you repeat this 



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For example to decode the first letter Y we first find its cipher number c = 25 ? ?1 Therefore p ? ?5c+9=(?5)(?1) + 9 = 14 So the plaintext letter is 



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It is a type of substitution cipher in which each letter in the plain text is replaced by a letter some fixed number of positions down the alphabet For example 



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First let's learn a few terms together CODE A code is a set of letters numbers symbols etc that is used to secretly send messages to someone CIPHER

How do I encrypt a message?

    Fill in the middle line with the message you'd like to encrypt: Pick your code word and write it on top (including the shifts these letters correspondto). Also convert your message letters to the corresponding numbers they represent: Repeat the code across the top, then add down the numbers (mod 26) and convertthose number back into letters:

How do you decrypt a cipher?

    • Attack the selected cipher text with the bi-gram score function, using block slide proposal moves and parame- ter value 1, for 10,000 iterations. • Apply the decryption key to the full cipher text and cal- culate the log score for full decrypted text.

How many keys are in a cipher?

    Usually a cipher contains one or two keys. In a symmetric key algorithm (e.g. DES), the decryption key is the same as the encryption key (or just the inverse function of it). In an asymmetric key algorithm (e.g. RSA), two different keys are used. The public key is used for encryption and a private key is for the decryption.

How many shifts can you use to encrypt a message?

    As we've discovered, there are only 25 dierent shifts we can use to encrypt a messagewith a Caesar cipher. Because of this, the Caesar cipher is considered to be a very weak typeof cryptography. We call the act of testing all 25 options until nding the key, the methodof brute force.

Shift (Caesar) Ciphers

If you have a message you want to transmit securely, you can encrypt it (translate it into a secret code). One of the simplest ways to do this is with ashift cipher. Famously, Julius Caesar used this type of cipher when sending messages to his military commanders. A shift cipher involves replacing each letter in the message by a letter that is some fixed number of positions further along in the alphabet. We"ll call this number theencryption key. It is just the length of the shift we are using. For example, upon encrypting the message "cookie" using a shift cipher with encryption key 3, we obtain the encoded message (orciphertext): FRRNLH. To make all of this more mathematical, consider the following conversion table for the English alphabet:

0 1 2 3 4 5 6 7 8 9 10 11 12

A B C D E F G H I J K L M

13 14 15 16 17 18 19 20 21 22 23 24 25

N O P Q R S T U V W X Y Z

i.Using the table, we can represent the letters in our message "cookie" with their corresponding numbers: 2 14 14 10 8 4. ii.Now add 3 (the encryption key) to each number to get: 5 17 17 13 11 7. iii.Now use the table to replace these numbers with their corresponding letters: FRRNLH. There is a small complication when we want to encrypt a message that contains a letter near the end of the alphabet. For example, if we consider the new message "pizza," then what letter should we use to replace the "z" when we encrypt? After performing a shift cipher encryption with encryption key 3, the message "pizza" becomes SLCCD. The letter "z" was replaced with the letter "C," which we can view as being 3 places further along than "z" if, after we reach "z," we cycle the alphabet around to the beginning again.

In terms of the numerical representations of our letters, the encryption of the message "pizza" looks

this way:

15 8 25 25 0-→18 11 2 2 3.

What have we done mathematically? There is a handy mathematical concept that describes this very nicely. Define the following notation for integersaandband integerm >1: a≡b(modm) meansmis a divisor ofa-b. In our situation, we take the numberm(themodulus), to be equal to the size of our character set, so m= 26. Now take each numberxfrom the representation of the message and perform the following arithmetic: add 3 tox, and if the result is between 0 and 25, stop; otherwise, replacex+3 with the integerybetween 0 and 25 that satisfiesy≡x+ 3 (mod 26). In summary, our encryption of the message "pizza" using a shift cipher with encryption key 3 looks like this: p-→15-→15 + 3≡18 (mod 26)-→S i-→8-→8 + 3≡11 (mod 26)-→L z-→25-→25 + 3≡2 (mod 26)-→C z-→25-→25 + 3≡2 (mod 26)-→C a-→0-→0 + 3≡3 (mod 26)-→D

How is the original (plaintext) message recovered from the ciphertext if the encryption key is known?

The following ciphertext was produced using a shift cipher with encryption key 9: LQXLXUJCN. To decrypt it (i.e., to recover the plaintext message), we need to add 17 (...or subtract 9... why is that the same?) to each of the numbers representing the ciphertext letters. Here 17 is the decryption keyfor the shift cipher with encryption key 9. Again, we must sometimes replace the result of this addition with the appropriate number between 0 and 25:

L-→11-→11 + 17≡2 (mod 26)-→c

Q-→16-→16 + 17≡7 (mod 26)-→h

X-→23-→23 + 17≡14 (mod 26)-→o

L-→11-→11 + 17≡2 (mod 26)-→c

X-→23-→23 + 17≡14 (mod 26)-→o

U-→20-→20 + 17≡11 (mod 26)-→l

J-→9-→9 + 17≡0 (mod 26)-→a

C-→2-→2 + 17≡19 (mod 26)-→t

N-→13-→13 + 17≡4 (mod 26)-→e

Let"s think about security now. Suppose you intercept a transmission of an encrypted message, and you know that the sender has used a shift cipher on the English alphabet, but you do not know the encryption key. How difficult would it be for you to break the code? If we exclude the encryption key 0, there are only 25 distinct shifts that might have been used. It

probably wouldn"t take very long (especially with computer help) to test each of these shifts in turn

(anexhaustive search). An incorrect shift length is likely to produce gibberish, while the correct shift length will produce a sensible message. Note however, that spaces between words, punctuation,

etc., will not be included in the plaintext that is recovered. For example, the message "fish "n" chips"

would appear as "fishnchips" in its plaintext form. Can you find the plaintext that produced the ciphertext below? A shift cipher with undisclosed encryption key was used.

UEUFXGZOTFUYQKQF

Probably you answered the above question by performing an exhaustive search. However, if the message had been longer, possibly you could have taken a shortcut. Suppose you have a somewhat lengthy passage of ciphertext that you want to decrypt, but you do not have the key. If you know that a shift cipher was used on a plaintext message written in standard English, then you can employ

frequency analysis: determine which letter occurs most often in the ciphertext. It is very likely that

this letter represents the plaintext letter "e." Assuming that it does, the decryption key can now be

calculated. Then try decrypting the entire message using this probable key.

Chances are good that the above procedure will find the correct plaintext on the first try. If it doesn"t,

i.e., if the outcome is gibberish, then find the next most likely representative of the plaintext letter

"e" and try again. Below is ciphertext produced by a shift cipher with undisclosed encryption key. Decrypt it using frequency analysis. (Note that the line breaks do not necessarily occur between words!)

VRIYVIVZEKYVEVOKWVNDFEKYJ

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