[PDF] ORGANIC CHEMISTRY I – PRACTICE EXERCISE Alkene reactions





Previous PDF Next PDF





Practice Tests Answer Keys Organic Chemistry I

Online Organic Chemistry I Chem 350



Organic Chemistry WORKSHEETS Organic Chemistry WORKSHEETS

Answer in the spaces provided. (on reverse if insufficient room). Fill in the blanks keep it simple science.



Naming Organic Compounds Practice Naming Organic Compounds Practice

Chemistry 0871. Learning Centre. Naming Organic Compounds Practice. EXERCISES. A. Identify the class of the following compounds. For any alkanes alkenes 



Organic Compound Naming Worksheet Organic Compound Naming Worksheet

Name the following compounds: Answers. 1) propoxypentane (pentoxypropane is OK but it's better to name the smaller R group first). 2) 3-bromobutanoic acid. 3 



ORGANIC CHEMISTRY I – PRACTICE EXERCISE Elimination

Explain your answer. 5) Provide the structure of the major organic product from the following reaction. Br. H3C. Br. KI. 6) When 1-iodo-1-methylcyclohexane is 



PRACTICE EXERCISE – ORGANIC CHEMISTRY I Alkynes

41) Provide the major organic product of the reaction shown below. C CH. NaNH2. Ph. H. O. H3O. +. Page 4. ANSWERS. 1). 25



Organic Chemistry 32-235 Practice Questions for Exam #2 Part 1

The answer here is 1S. 2S. 2. Consider the SN1 reaction of tert-butyl chloride with iodide ion: (CH3)3C Cl + I.



Naming and Creating Hydrocarbons Hydrocarbons are the simplest

Fossil fuels are made up of complex chemical compounds called hydrocarbons. Hydrocarbons are the simplest organic compounds and contain only hydrogen and 



Practice Set Answer Keys Organic Chemistry I Table of Contents

Practice Set Answer Keys Organic Chemistry I. Table of Contents. • Online Organic Chemistry I



Practice Tests Answer Keys Organic Chemistry I

f. 15. Answers Test 1 Version 3. 1. Resonance: No atoms can move!



ORGANIC CHEMISTRY I – PRACTICE EXERCISE Alkene reactions

FOR QUESTIONS 1-24 GIVE THE MAJOR ORGANIC PRODUCT OF THE REACTION



Organic Chemistry 32-235 Practice Questions for Exam #2 Part 1

The answer here is 1S. 2S. 2. Consider the SN1 reaction of tert-butyl chloride with iodide ion: (CH3)3C Cl + I.



Practice Tests Answer Keys Organic Chemistry 2

Online Organic Chemistry 2 Chem 360



PRACTICE EXERCISE – ORGANIC CHEMISTRY I Alkynes

22) To a solution of propyne in diethyl ether one molar equivalent of CH3Li was added and the resulting mixture was stirred for 0.5 hour.



ORGANIC CHEMISTRY I – PRACTICE EXERCISE Elimination

Explain your answer. 5) Provide the structure of the major organic product from the following reaction. Br. H3C. Br.



General Organic Chemistry Questions

Arrange the following compounds in order of decreasing chemical shift for the underlined hydrogens (largest ? value first smallest value last). CH3CH2CH3 



Organic chemistry

to the rigor with which the subject of organic chemistry was presented. In the electric field of all the other ions in the solution.



GRE Chemistry Test Practice Book

necessary to answer some questions classified as testing organic chemistry ... The worksheet on page 51 lists the correct answers to the questions.



Organic Chemistry Practice Problems

Organic Chemistry I Practice Set #1 (Chapter 1 – Carey) Consider the following acid-base reaction: H To decide on which side the equilibrium lies: 1) Identify conjugate acid-base pairs (connect above with lines); 2) If you know the pK avalues (or they are given) the equilibrium lies AWAY FROM THE STRONGER ACID



Naming Of Organic Compounds Worksheets - K12 Workbook

SOLUTIONS (1) aromatic compound: iodobenzene (2) alkane: 3-methylhexane (3) ketone (4) alkane/alkyl halide: 3-chloro-4-ethyl-24-dimethyloctane (5) aromatic compound: o-diethylbenzene or ortho-diethylbenzene (6) alkene: 3-methylpentene (7) ester (8) aromatic compound: p-bromotoluene or para-bromotoluene (9) alkyne:



The Complete Organic Chemistry Worksheet

The Complete Organic Chemistry Worksheet The Complete Organic Chemistry Worksheet doc Name the following hydrocarbons CH3 CH3CH2CH CH CH2 CH3 CH3 CH3 b CH3 CH3CH2 CH CH3 CH3 c CH3 CH3 CH3 CH2 CH3 d CH3CH2 CH2CH2CH3 CH2CH3CH2CH3 Name the following hydrocarbons CH3 CH3CH2CH2CHCH3 CH3 CH3CHCH2CH3 CH3 CH3CHCHCH3 CH2CH3 g CH3CHCH2CH3 CH2 CH3



Worksheets for Organic Chemistry - van Maarseveen

Chemistry of Natural Substances – Organic Chemistry Worksheets 14 a) 5-methyl-2-hexanol b) 22-dimethyl-1-propanol c) 2-propyn-1-ol d) 3-heptanone e) 3-chloro-1-butanal f) 3-penten-2-one g) 2-methyl-3-hexen-1-al h) 3-ethyl-3-methyl-1-pentanol i) 24-dimethyl-24-hexandiol j) tetrachloroethene Question 3



PRACTICE PROBLEMS FOR BRONSTED-LOWRY ACID-BASE CHEMISTRY

ORGANIC CHEMISTRY I PRACTICE PROBLEMS FOR BRONSTED-LOWRY ACID-BASE CHEMISTRY 1 For each of the species below identify the most acidic proton and provide the structure of the corresponding conjugate base You might want to draw detailed Lewis formulas in some cases HF CH3CH2OH H3O H2O CH3CH3 CH3CN HCCH H2 RNH3 CH3OH2 2

What are worksheets in organic chemistry?

    Worksheets are Organic naming practice work, Naming compounds practice work, Chemistry 104 practice 1 organic identifying, C hem gu id e q u e s tio n s naming organic compounds 1, Short summary of iupac nomenclature of organic compounds, Nomenclature in organic chemistry, Practice problems for naming inorganic compounds, Chapter 8.

What are the contents of the book Organic Chemistry?

    Organic Chemistry by David Klein PDF Download 3rd edition Contents of This Book 1 A Review of General Chemistry: Electrons, Bonds, and Molecular Properties? 2 Molecular Representations 3 Acids and Bases … Download eBook and Solution Manual on John Mcmurry Organic Chemistry PDF Download 8th and 9th Edition.

What is organic chemistry?

    To the organic chemist this is a meaningless distinction. There are toxic compounds and nutritious ones, stable compounds and reactive ones—but there is only one type of chemistry: it goes on both inside our brains and bodies and also in our flasks and reactors, born from the ideas in our minds and the skill in our hands.

How good is chemistry steps for organic 1 and 2?

    I have been using Chemistry Steps for Organic 1 and 2 and struggled in the first semester before finding this site and I learned here more than in the zoom lectures and the book. The types of practice problems and the solutions are extremely relevant, and the addition of new puzzles is what I was

ORGANIC CHEMISTRY I - PRACTICE EXERCISE

Alkene reactions and mechanisms

FOR QUESTIONS 1-24, GIVE THE MAJOR ORGANIC PRODUCT OF THE REACTION, PAYING PARTICULAR ATTENTION TO REGIO- AND STEREOCHEMICAL OUTCOMES. 1) O HCl CH 3 OH 2) HCl CH 3 3) HCl 4) HCl 5) HBr 6) HCl 7) CH 3 H 3 O 8) H 3 O 9) H 3 O 10)

Hg(OAc)

2 , H 2 O NaBH 4 CH 3 11)

Hg(OAc)

2 , H 2 O NaBH 4 12)

Hg(OAc)

2 , CH 3 OH NaBH 4 13) CH 3 BH 3 THF H 2 O 2 OH 14) (Z)-3-hexene 1) BH 3 / THF 2) H 2 O 2 / OH 15) H 2 Pt 16) Br 2 CH 2 Cl 2 (solvent) CH 3 17) Cl 2 CH 2 Cl 2 (solvent) 18) Cl 2 H 2 O 19) CH 3 1) CH 3 CO 3 H 2) H 3 O 20) PhCO 3 H CH 2 Cl 2 (solvent) 21)
CH 3 OsO 4 H 2 O 2 22)
CH 3 1) O 3

2) (CH

3 2 S 23)
KMnO 4 (hot, conc.) 24)
1) O 3

2) (CH

3 2 S

25) Treatment of cyclopentene with peroxybenzoic acid

A) results in oxidative cleavage of the ring to produce an acyclic compound

B) yields a meso epoxide

C) yields an equimolar mixture of enantiomeric epoxides D) gives the same product as treatment of cyclopentene with OsO 4

E) none of the above

26) Provide a detailed, step-by-step mechanism for the reaction shown below.

HO Br 2 O Br HBr

27) Provide a detailed, step-by-step mechanism for the reaction shown below.

O H 3 O HO

28) Provide the reagents necessary to complete the following transformation. The synthesis may involve

more than one step. Br OH OH

29) Provide the reagents necessary to complete the following transformation. The synthesis may involve

more than one step. Br OH OH enantiomer

30) Provide the reagents necessary to convert 3-methyl-2-butanol to 2-methyl-2-butanol. The synthesis

may involve more than one step.

31) Both (E)- and (Z)-hex-3-ene are subjected to a hydroboration-oxidation sequence. How are the

products from these two reactions related to each other? A) The (E)- and (Z)-isomers generate the same products but in differing amounts. B) The (E)- and (Z)-isomers generate the same products in exactly the same amounts. C) The products of the two isomers are related as constitutional isomers. D) The products of the two isomers are related as diastereomers. E) The products of the two isomers are not structurally related.

32) What alkene would yield the following products upon ozonolysis?

CH 3 CH 2 CH 2 CH 2

CHO + CH

2 O

33) Addition of Br

2 to (E)-hex-3-ene produces

A) a meso dibromide

B) a mixture of enantiomeric dibromides which is optically active C) a mixture of enantiomeric dibromides which is optically inactive

D) (Z)-3,4-dibromo-3-hexene

E) (E)-3,4-dibromo-3-hexene

34) The mechanism for the acid-catalyzed hydration of alkenes is the reverse of the acid-catalyzed

dehydration of alcohols. This illustrates the principle of _______________________.

35) Which of the following is the best reaction sequence to accomplish a Markovnikov addition of water to

an alkene with minimal skeletal rearrangement?

A) water + dilute acid

B) water + concentrated acid

C) oxymercuration-demercuration

D) hydroboration-oxidation

E) none of the above

36) Which of the following additions to alkenes occur(s) specifically in an anti fashion?

A) hydroboration-oxidation

B) addition of Br

2

C) addition of H

2

D) addition of H

2

O in dilute acid

E) both A and B

37) Which of the following additions to alkenes occur(s) specifically in an syn fashion?

A) dihydroxylation using OsO

4 , H 2 O 2

B) addition of H

2

C) hydroboration

D) addition of HCl

E) A, B, and C

38) HBr can be added to an alkene in the presence of peroxides (ROOR). What function does the peroxide

serve in this reaction?

A) nucleophile

B) electrophile

C) radical chain initiator

D) acid catalyst

E) solvent

ANSWERS

1) OH OCH 3 enantiomer 2) CH 3 Cl 3) Cl 4) Cl 5) Br 6) Cl 7) OH CH 3 8) OH 9) OH 10) HO CH 3 11) OH 12) OCH 3 13) CH 3 OH enantiomer 14) HOH or simply HO 15) 16) Br CH 3 Br enantiomer 17) Cl Cl H 3 C H H CH 2 CH 3 enantiomer 18) OH Cl 19) OH CH 3 OH enantiomer 20) O H 3 CH CH 2 CH 3 H enantiomer 21)
OH OH CH 3 enantiomer 22)
CHO O H 3 C 23)
O OH O 24)
CHO H O

25) B

26) This mechanism is best approached by working backwards. The product shown is an ether-bromide,

with the oxygen and the bromine atoms on adjacent carbons. Every time two functional groups are on

adjacent carbons it suggests the possibility that they might be formed by an addition to the C=C double

bond. This can be represented generically thus: AB AB An addition of bromine in the presence of water produces such result, adding Br to one carbon and

OH to the other (section 8-11 in the textbook).

OHBr Br 2 H 2 O This suggests the possibility that an alcohol could be used instead of water, with similar results, except that this would add Br to one carbon and RO to the other one. ORBr Br 2 ROH The mechanism of this reaction would be similar to that with water. Bromine adds first to form a three memebered ring intermediate, followed by nucleophilic attack by the alcohol from the back.

Let's use an unsymmetrical alkene to illustrate the point that the most highly substituted carbon gets

the RO group preferentially. BrBr Br HOR O HR Br Br RO Br HBr The molecule in question has an oxygen (ether group) and a bromine on adjacent carbons. We can make a similar reasoning as above that such arrangement forms from the reaction between a C=C bond and Br 2 in the presence of an alcohol, a group that also happens to be present in the starting material. HO O Br

The ether and bromine groups are on adjacent

carbons, suggesting that the original double bond was between C 1 and C 2.

Notice the oxygen on C

5 1 2 3 4 5 1 2 3 4 5

The starting material also happens to have

5 carbons, with the double bond on C

1 and C 2 and the oxygen on C 5. With this scenario in place, we can now start the mechanism from the first step, which would be the attack of the pi-bond on bromine to form a three membered ring intermediate. HO 1 2 3 4 5 BrBr HO 1 2 3 4 5 Br Br The alcohol group is now poised to attack the three membered ring at the most highly substituted carbon. The carbon chain is long enough to allow for flexibility of movement without introducing strain. O 1 2 3 4 5 Br Br O Hquotesdbs_dbs9.pdfusesText_15
[PDF] organic functional group analysis lab report

[PDF] organic nomenclature packet chemistry answers

[PDF] organic products of t butyl chloride hydrolysis

[PDF] organic reactions chemguide

[PDF] organisation et gestion de l'entreprise pdf

[PDF] organisation et structure de l'entreprise pdf

[PDF] organisation générale de l'entreprise pdf

[PDF] organisation interne de l'entreprise pdf

[PDF] organisational culture model

[PDF] organise hard rubbish collection

[PDF] organisms that reproduce asexually

[PDF] organization and structure of the american legal system

[PDF] organization management book pdf

[PDF] organization of research paper

[PDF] organization theory pdf