log10 6 + log10 2 = log10(6 × 2) = log10 12 The same base, in this case 10, is used throughout the calculation You should verify this by evaluating both sides
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The LOG102 is a versatile integrated circuit that computes the logarithm or log ratio of an input current relative to a reference current The LOG102 is tested over
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1) On va retrouver ici la propriété fondamentale des logarithmes (isomorphisme) par un exemple simple : On a vu que log (10) = 1, log (102) = 2 et log (103) = 3
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log10 2 log10 5 ≈ 0 3010 0 6990 ≈ 0 4306 c log22 14 = log22 10 × log10 14 = log10 14 log10 22 ≈ 1 1461 1 3424 ≈ 0 8538 d log4 8 = log4 10×log10 8 =
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x = log10 32 log10 2 = 1 5051 0 3010 = 5 Hence 25 = 32 Note that this answer can be checked by substitution into the original equation 3 Solving equations
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log10 6 + log10 2 = log10(6 × 2) = log10 12 The same base, in this case 10, is used throughout the calculation You should verify this by evaluating both sides
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The laws of logarithms
mc-logs2-2009-1There are a number of rules which enable us to rewrite expressions involving logarithms in different,
yet equivalent, ways. These rules are known as thelaws of logarithms. You will find that yourlecturers use these laws to present answers in different forms, and so you should make yourself aware
of them and how they are used. The laws apply to logarithms of any base but the same base mustbe used throughout a calculation.The laws of logarithms
The three main laws are stated here:
First Law
logA+ logB= logAB This law tells us how to add two logarithms together. AddinglogAandlogBresults in the logarithm of the product ofAandB, that islogAB.For example, we can write
log106 + log102 = log10(6×2) = log1012
The same base, in this case 10, is used throughout the calculation. You should verify this by evaluating both sides separately on your calculator.Second Law
logAn=nlogASo, for example
log1064= 4log106
You should verify this by evaluating both sides separately on your calculator.Third Law
logA-logB= logA BSo, subtractinglogBfromlogAresults inlogAB.
For example, we can write
log e15-loge3 = loge153= loge5
The same base, in this case e, is used throughout the calculation. You should verify this by evaluating
both sides separately on your calculator. www.mathcentre.ac.uk 1 c?mathcentre 2009