[PDF] [PDF] Question Bank of d & f block - chemistryworkshopjr

Answers:- Very short answer questions:- Q 1 To aquire nearest noble gas configuration Q 2 In transition elements electron enter into penultimate shell and in 



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Question Bank of d & f block

Very short answer type questions:- each carry 1 mark. Q.1. Among the lanthanides, Ce(III) can be easily oxidized to Ce(IV). Explain. Q.2. What is the basic difference between the electronic configuration of transition metals and inner transition elements.

Q.3. Why is separation of lanthanides difficult?

Q.4. Why are the ionization energy of 5d elements than those of 3d eiements.

Q.5. Why copper considered a transition metal.

Short answer type question:- each carry 2 marks.

Q.1. Account for the following:-

I. Zn, Cd & Hg are not considered as transition metals. II. Zn2+salts are white while Cu2+ salts are blue.

Q.2. Explain Solution of

I. Colour of K2Cr2O7 dependson the pH of solution. II. [Ti(H2O)6]3+ is coloured but [Sc(H2O)6]3+ is colourless .

Q.3.What happens when

I. K2Cr2O7 react with an acidified solution of FeSO4?

II. KMnO4 react with an acidified solution of KI?

Short answer type question:- each carry 3 marks.

Q.1. (i) What is lanthanoid contraction? Explain its causes. (ii) Out of Fe2+ and Fe3+ , which is more paramagnetic and why? (iii) Why do transition metals form coloured compound?

Q.2. Explain

I. Transition elements have high melting point and boiling point. II. Transition elements exhibit variable oxidation states. III. A transition metal forms alloys with other transition elements.

Long answer type question:- carry 5 marks.

Q.1. What happens when lanthanoid elements:

a) Burn in oxygen. b) Heated with Sulphur . c) Heated with Carbon. d) React with H2O. e) Heated with N2.

Answers:-

Very short answer questions:-

Q.1. To aquire nearest noble gas configuration.

Q.2. In transition elements electron enter into penultimate shell and in inner transition elements electron enter into antepenultimate shell.

Q.3. almost same ionic radii.

Q.4. Poor shielding effect of f-orbital electrons. Q.5. Because in one of its oxidation state it has partly filled d orbital.

Short answer type questions:-

Ans. 1.

I. Fully filled d-orbitals in its elemental state as well as in its common oxidation state. II. No d-d transition in Zn2+ but in Cu2+ there is d-d transition.

Ans.2.

I. CrO42- H+ Cr2O72- i. OH- II. Because in Sc3+ complex there is not any d-d transition possible but in Ti3+ it is possible.

Ans. 3.

I. Ferrous ion is converted into ferric ion.

II. Iodine is liberated.

Short answer type Question:-

Ans. 1.

I. Almost same size of II and III transition series elements, Poor shielding effect of f- orbital electrons.

II. Fe3+

III. Due to d-d transition.

Ans. 2.

I. Due to strong metallic bonds

II. Because of availability of d and s orbital electrons

III. Because of almost same size

Long ans type Ques.

Ans.

I. Ln2O3

II. Ln2S3

III. Ln2C3

IV. Ln(OH)3

V. LnN

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