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(first) DC bin This results in a RMS valued FFT representing the RMS spectrum depends on signal frequency, sample rate and the number of bins However 



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The Fast Fourier Transform (FFT) and the power spectrum are powerful tools for Frequency lines also can be referred to as frequency bins or FFT bins 



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between two discrete spectrum bins This error may be interpreted as the resolution of an FFT frequency measurement method Denoting the largest frequency



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(first) DC bin This results in a RMS valued FFT representing the RMS spectrum depends on signal frequency, sample rate and the number of bins However 



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in the periodic signal processed by the FFT, causing the energy contained in the signal to 'leak' from the signal frequency bin into adjacent frequency bins



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time domain signal complex FFTbinsRMSspectrumpower spectrumpower spectrum x 10 7 -140 -120 -100 -80 -60 -40 -20 0

256 point FFT, leakage effects, 50 MHz signal with 0 dBm, fs=250 MHz

frequency in Hz power in dBm no window hann window flattop window blackman window ??? ????? ??????? ?? ??? ??????? ?? ????? ?? ???? ????012345 x 10 -7 -1 -0.5 0 0.5 1 time domain: no windowing (rectangle) time in s amplitude in volts

012345

x 10 -7 -1 -0.5 0 0.5 1 time domain: hann window time in s

4.94.924.944.964.9855.025.045.065.085.1frequency in Hz

?? ????? ??????? ???? ???? ?????024681012frequency in Hz

107-50-40-30-20-100power in dBmsmall scalloping loss, signal power: 0dBm16 point FFTtrue spectrum

(here including leakage)024681012frequency in Hz

107-50-40-30-20-100power in dBmlarge scalloping loss, signal power: 0 dBm16 point FFTtrue spectrum

PG[dB] = 10log10N2

107-100-80-60-40-200power in dBmnoisy sine signal with different FFT sizes (hann window)256 point1024 point65k point024681012frequency in Hz

x 10 7-150 -100 -50 0

Overview of errors in FFT

frequency in Hz power in dBm coherent power gain & scalloping loss equivalent noise bandwidth & processing gain P true[dBm] =Pdispl[dBm] +CPG[dB] +scalloping loss[dB]????? P true[dBm] =Pfloor[dBm] +CPG[dB] +PG[dB]ENBWcorr[dB]????? P true[dBm] = 10log10 X iFFT(i)[linear]! +CPG[dB]ENBWcorr[dB] ?????? ??? ?? ???? ????Pdispl= 5:9dBm? ????? ??? ??? ??? ???? ????? ?? ??? ???? ?????? ?? P ??? ???? ?? ???????1:8dB? ?13:02dBm????? ???????024681012 x 10 7-25 -20 -15 -10 -5 0 5 10

1024 point FFT (averaged over 1000 FFTs), window: hann, noisy sine signal

Frequency [Hz]

Power [dBm]

Pdispl = 5.9 dBm

P V rms=(s)

P=var(s) =2(s) =V2rms?????

P[dBm] = 10log10var(s)R1mW

= 10log102(s)R1mWquotesdbs_dbs17.pdfusesText_23