[PDF] [PDF] Practice Solving Literal Equations

To solve literal equations: Use the same process you use to isolate the variable in an algebraic equation with one variable It's just that you are going to be 



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pdf NAME DATE PERIOD 8-6 Skills Practice

8-6 Skills Practice Solving x2 + bx + c = 0 Factor each polynomial 1 t2 + 8t + 12 (t + 2)(t + 6) 3 p2 + 9p + 20 (p + 5)(p + 4) 5 n2 + 3n - 18 (n + 6)(n - 3) 7 y2 - 5y - 6 (y + 1)(y - 6) 9 r2 + 4r - 12 (r - 2)(r + 6) 11 w2 - w - 6 (w - 3)(w + 2) 13 x2 - 8x + 15 (x - 5)(x - 3) 15 t2 - 15t + 56 (t - 7)(t - 8) 2 n2 + 7n + 12



8-6 Solving x2 + bx + c = 0 Review — Multiply using FOIL

Chapter 8 40 Glencoe Algebra 1 Practice Solving x2 + bx + c = 0 Factor each polynomial 1 a 2 + 10a + 24 2 h + 12h + 27 3 x2 + 14x + 33 (a + 4)(a + 6) (h + 3)(h + 9) (x + 11)(x + 3) 4 g2 - 2g - 63 5 w2 + w - 56 6 y2 + 4y - 60 (g + 7)(g - 9) (w + 8)(w - 7) (y + 10)(y - 6) 7 b2 + 4b 2- 32 8 n - 3n - 28 9 t2 + 4t - 45 (b - 4)(b + 8) (n



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8-6 Word Problem Practice - East Brunswick Public Schools

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Chapter 8 Resource Masters - Commack Schools

Look at the factors of 12 -12 or -144 for a pair whose sum is -7 Enter an equation to determine the factors in Y1and an equation to find the sum of factors in Y2 Examine the table to find a sum of -7 12x2- 7x- 12 = 12x2+ 9x+ (-16x) - 12 = 3x(4x+ 3) - 4(4x+ 3) = (4x+ 3)(3x- 4) Thus 12x2- 7x- 12 = (4x+ 3)(3x- 4)

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