Example 4: Find the trigonometric Fourier series for the periodic signal x(t) can be recovered from its Fourier transform X(jw) by using Inverse Fourier transform 2 e−jwtdt = −1 jw [e−jwT 2 −ejwT 2 ] = 2wsin( wT 2 ) X(w) = Tsin(πwT
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[PDF] Fourier transform properties - MIT OpenCourseWare
Figure S9 5-1 rT A X(w) = A e--'' dt - (e -jwT - e )wT -r -Jw - 2j sin coT =A We can compute the function x(t) by taking the inverse Fourier transform of X(w)
[PDF] Fourier Series and Fourier Transform
Example 4: Find the trigonometric Fourier series for the periodic signal x(t) can be recovered from its Fourier transform X(jw) by using Inverse Fourier transform 2 e−jwtdt = −1 jw [e−jwT 2 −ejwT 2 ] = 2wsin( wT 2 ) X(w) = Tsin(πwT
[PDF] Working out Fourier Transforms Pairs
ds Page 2 Fourier Transform Pairs (contd) Because the Fourier transform and the inverse
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which converts a Fourier transform into a time-domain waveform Inverse Fourier transforms are defined by the integral 10 = S Feejur die jwt do (W1-2)
v Advanced Fourier Analysis
s (t-to) = J8 (w) ejw (t-to) dw = J[8 (w) e- jw to] ejwt dw (5) 2n 2n -00 The spectral function Uofj wand the inverse Fourier transform exist only for the spectral
Appendix A The Laplace transform
Setting t - r = T and substituting in the integral yields L[cosOJt] =- -, __ [eJwt-st]~ __ , __ [e-Jwt--st]~ 2 JOJ - S and the inverse Fourier transform is defined as
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a) Determine the function f(t) whose Fourier transform is shown in figure P-3 1 a Solution: The function f(t) can be obtained from F(w) by doing an inverse Fourier transform, F(w)= Le-t/20e –jwt dt = 1 / e-[(62 +j20?wt-o+w2 +0° w?)/ 2021 dt
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(t) and the DTFT X(ejwT) Notation of continuous Fourier transform: forward inverse Assume that the discrete-time signal x(nT) is uniformly sampled from the
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(w)ejwt dw and the inverse FOURIER transform c(w) = F(t) e− jwt −∞ +∞ ∫ dt , respectively Using state-of-the-art algorithms these transformations can be
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Fourier Series and Fourier Transform
2.1 INTRODUCTION
Fourier series is used to get frequency spectrum of a time-domain signal, when signal is a periodic function of
time. We have seen that the sum of two sinusoids is periodic provided their frequencies are integer multiple
of a fundamental frequency,w0.2.2 TRIGONOMETRIC FOURIER SERIES
Consider a signalx(t), a sum of sine and cosine function whose frequencies are integral multiple ofw0
x(t) =a0+a1cos(w0t)+a2cos(2w0t)+··· b1sin(w0t)+b2sin(2w0t)+···
x(t) =a0+¥å n =1(ancos(nw0t)+bnsin(nw0t))(1) a0,a1,...,b1,b2,...are constants andw0is the fundamental frequency.
Evaluation of Fourier Coefficients
To evaluatea0we shall integrate both sides of eqn. (1) over one period(t0,t0+T)ofx(t)at an arbitrary timet0 t 0+T? t0x(t)dt=t
0+T? t 0a0dt+¥å
n=1a nt 0+T? t0cos(nw0t)dt+¥å
n=1b nt 0+T? t0sin(nw0t)dt
Since?t0+T
t0cos(nw0dt) =0
t 0+T? t0sin(nw0dt) =0
a 0=1Tt 0+T? t0x(t)dt(2)
To evaluateanandbn, we use the following result:
t 0+T? t0cos(nw0t)cos(mw0t)dt=?0m?=n
T/2m=n?=0
9496•Basic System Analysis
Multiply eqn. (1) by sin(mw0t)and integrate over one period t 0+T? t0x(t)sin(mw0t)dt=a0t
0+T? t0sin(mw0t)dt+¥å
n=1a nt 0+T? t0cos(nw0t)sin(mw0t)dt+
n=1b nt 0+T? t0sin(mw0t)sin(nw0t)dt
b n=2 Tt 0+T? t0x(t)sin(nw0t)dt(4)
Example 1:
-3-2-1 -1.01.0 1 230-Fig. 2.1.
T→ -1 to 1T=2w0=px(t) =t,-1 a 0=1 21
-1t dt=14(1-1) =0 a n=0 b n=1 -1tsinpntdt=?-tcospnt np-cospntnp? 1 -1 -1 b n=-2 npcosnp=2p? -(-1)nn? b 1b2b3b4b5b6
2 p-22p23p-24p25p-2···6p x(t) =¥å n=12 p? -(-1)nn? sinnpt 2 p? sinpt-12sin 2pt+13sin 3pt-14sin 4pt+···? Fourier Series and Fourier Transform•97
Example 2:
-2π 1.0 2π 4π 6π
0t Fig. 2.2.
x(t) =t 2pT=2pw0=2pT=1
a 0=1 T2p? 0 x(t)dt=14p2? 12t2? 2p 0 =12 a n=2 4p22p?
0 tcosntdt=12p2? tsintn+sinntn? 2p 0 1 2p2? 2psin 2npn+sin 2npn?
=0 b n=2 4p22p?
0 tsinntdt=-12p2? tcosntn+cosntn? 2p 0 -1 2p2? 2pcos 2npn+cos 2npn-1n?
b n=-1 np x(t) =1 2+¥å
n=1? -1np? sinnt=12+1p¥å n=11ncos(nt+p/2) 1 2-1p? sint+sin 2t2+sin 3t3+···? Example 3:
-T/2-T/4T/4A x(t) t T/2 Fig. 2.3.Rectangular waveform
98•Basic System Analysis
Figure shows a periodic rectangular waveform which is symmetrical to the vertical axis. Obtain its F.S.
quotesdbs_dbs2.pdfusesText_3
-1t dt=14(1-1) =0 a n=0 b n=1 -1tsinpntdt=?-tcospnt np-cospntnp? 1 -1 -1 b n=-2 npcosnp=2p? -(-1)nn? b
1b2b3b4b5b6
2 p-22p23p-24p25p-2···6p x(t) =¥å n=12 p? -(-1)nn? sinnpt 2 p? sinpt-12sin 2pt+13sin 3pt-14sin 4pt+···?Fourier Series and Fourier Transform•97
Example 2:
-2π 1.02π 4π 6π
0tFig. 2.2.
x(t) =t2pT=2pw0=2pT=1
a 0=1 T2p? 0 x(t)dt=14p2? 12t2? 2p 0 =12 a n=24p22p?
0 tcosntdt=12p2? tsintn+sinntn? 2p 0 1 2p2?2psin 2npn+sin 2npn?
=0 b n=24p22p?
0 tsinntdt=-12p2? tcosntn+cosntn? 2p 0 -1 2p2?2pcos 2npn+cos 2npn-1n?
b n=-1 np x(t) =12+¥å
n=1? -1np? sinnt=12+1p¥å n=11ncos(nt+p/2) 1 2-1p? sint+sin 2t2+sin 3t3+···?Example 3:
-T/2-T/4T/4A x(t) t T/2Fig. 2.3.Rectangular waveform
98•Basic System Analysis
Figure shows a periodic rectangular waveform which is symmetrical to the vertical axis. Obtain its F.S.
quotesdbs_dbs2.pdfusesText_3