[PDF] [PDF] CBSE NCERT Solutions for Class 9 Mathematics Chapter 4

CBSE NCERT Solutions for Class 9 Mathematics Chapter 4 Back of Chapter Questions Exercise: 4 1 1 The cost of a notebook is twice the cost of pen write a  



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[PDF] CBSE NCERT Solutions for Class 9 Mathematics Chapter 4

CBSE NCERT Solutions for Class 9 Mathematics Chapter 4 Back of Chapter Questions Exercise: 4 1 1 The cost of a notebook is twice the cost of pen write a  



[PDF] LINEAR EQUATIONS IN TWO VARIABLES - NCERT

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Class- XI-CBSE- Linear equations in two variables

P ractice more on Lin ear equations in two variables Page - 1 www.embibe.com CBSE NCERT Solutions for Class 9 Chapter 4

Back of Chapter Questions

Exercise:

4 .1 1.T he cost of a notebook is twice the cost of pen write a linear equation in two variables to represent this statement.

Solution:

Let the cost of a notebook be

Given that cost of a notebook

= 2× cost of a pen Hence, xെ2y= 0 is the representation of the given statement.

2.Express the following linear equations in the form

ax+by+ c= 0 and indicate the values of a,b and c in each case:

F10= 0(iii)െ2x+3y= 6

(iv)x =3y (v)2x=െ5y (vi)3x+ 2= 0 (vii)yെ2 =0 (viii)5 =2x

Solution:

Comparing above equation with

ax+by+ c= 0. (ii)xെ

F10= 0

Comparing above equation with

ax+by+ c= 0. Class- XI-CBSE-Science Linear equations in two variables

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We get, a =1 ,b=െ

,c= െ10 (iii) െ2x+3y= 6

Comparing above equation with

ax+by+ c= 0.

We get, a =െ2,b=3 ,c =െ6

(iv) x =3y

Comparing above equation with

ax+by+ c= 0.

We get, a =1 ,b=െ3,c=0

(v) 2x=െ5y

Comparing above equation with

ax+by+ c= 0.

We get, a =2 ,b=5,c =0

(vi)

3x+ 2= 0

Comparing above equation with

ax+by+ c= 0.

We get, a =3 ,b=0,c =2

(vii) yെ2 =0

Comparing above equation with

ax+by+ c= 0.

We get, a =0 ,b=1,c =െ2

(viii) 5 =2x

Comparing above equation with

ax+by+ c= 0.

We get, a =െ2,b=0 ,c =5

Exercise: 4.2

1. Which one of the following options is true, and why? y =3x+ 5 has (i) a unique solution Class- XI-CBSE-Science Linear equations in two variables

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(ii) only two solutions (iii) infinitely many solutions

Solution:

(iii) is correct y =3x+ 5 has infinitely many solutions

For every xא

Hence infinitely many solutions.

2. Write four solutions for each of the following equations (i)

2x+ y= 7

(ii) Ɏx +y =9 (iii) x =4y

Solution:

(i)

2x+ y= 7

y =7 െ2x

For x =0

(0,7) is a solution.

For x =1

(1,5) is a solution.

For x =2

(2,3) is a solution.

For x =3

(3,1) is a solution. (ii) Ɏx +y =9

For x =

Class- XI-CBSE-Science Linear equations in two variables

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Ɏ= 8

,8ቁ is a solution

For x =

= 7 ,7ቁ is a solution

For x =

= 6 ,6ቁ is a solution

For x =0

(0,9) is a solution (iii) x =4y 4

For x =0

4 = 0

For x =4

= 1

For x =8

= 2

For x =12

Class- XI-CBSE-Science Linear equations in two variables

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4= 3 3. Check which of the following are solutions of the equation xെ2y= 4 and which are not (i) (0,2) (ii) (2,0) (iii) (4,0) (iv) ൫ξ2,4ξ2൯ (v) (1,1)

Solution:

(i) L.H.S xെ2y

Given point

(0,2) Hence (0,2) is not a solution of xെ2y= 4. (ii) L.H.S xെ2y

Given point

(2,0) Hence (2,0) is not a solution of xെ2y= 4. (iii) L.H.S xെ2y

Given point

(4,0) Class- XI-CBSE-Science Linear equations in two variables

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Hence (4,0) is a solution of xെ2y= 4. (iv) L.H.S xെ2y

Given point

൫ξ2,4ξ2൯ Hence , ൫ξ2,4ξ2൯ is a solution of xെ2y= 4. (v) L.H.S xെ2y

Given point

(1,1) Hence (1,1) is not a solution of xെ2y= 4. 4. Find the value of k, if x =2 , y =10 is a solution of the equation 2x+3y= k.

Solution:

Given that

(2,1) is a solution of the equation 2x+3y= k Therefore, if x =2 ,y=1 is a solution of equation 2x+3y= k, then k =7 .

Exercise: 4.3

1. Draw the graph of each of the following linear equations in two variables: (i) x +y =4 (ii) xെy =2 (iii) y =3x (iv)

3 =2x+ y

Solution:Given equation, x +y =4

Class- XI-CBSE-Science Linear equations in two variables

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At x =0 and x =4 we get y =4 and y =0 respectively.

Given equation, xെy =2

At y =0 and y =2 we get x =2 and x =0 respectively. Class- XI-CBSE-Science Linear equations in two variables

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Given equation, y =3x.

At x =0 we get y =0 Similarly, at x =1 and x =2 we get y =3 and y =6 respectively. (0,0),(1,3) and (2,6) are the solutions of y =3x. Class- XI-CBSE-Science Linear equations in two variables

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(iv)

Given equation, 3 =2x+ y.

At x =0 and x = we get y =3 and y =0 respectively. ,0ቁ are solutions of 3 =2x+ y. Class- XI-CBSE-Science Linear equations in two variables

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2.

Give the equations of two lines passing through

(2,14). How many more such lines are there, and why?

Solution:

Given point

(2,14)

Let x =2 and y =14

We can write 14= 7× 2

Similarly, 14= 2+ 12

From above process

we can say that there are different possible combinations of lines which passing through (2,14). Therefore, from a given point (2,14), there are infinite lines passing through it. 3.

If the point

(3,4) lies on the graph of the equation 3y=ax+ 7, find the value of a.

Solution:

Class- XI-CBSE-Science Linear equations in two variables

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Given that point (3,4) lies on graph of the equation 3y=ax+ 7 3 Therefore, if (3,4) is the solution of equation 3y=ax+ 7 then a = 4. total fare as

Solution:

Given

Total distance covered = x km

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