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C H A P T E R12

FourierSeries

In 1807, the French mathematician and physicist Joseph Fourier submitted a paper on heat conduction to the Academy of Sciences of Paris. In this paper Fourier made theclaimthatanyfunctionf functions, f ?x??a0 2 k?1 ?akcos?kx??bksin?kx???for???x?? ? The paper was rejected after it was read by some of the leadingmathematicians of his day. They objected to the fact that Fourier had not presented much in the way of proof for this statement, and most of them did not believe it. In spite of its less than glorious start, Fourier's paper wasthe impetus for major developmentsinmathematicsandintheapplicationofmathematics. Hisideasforced mathematicians to come to grips with the definition of a function. This, together with other metamathematical questions, caused nineteenth-century mathematicians foundation. Fourier's ideas gave rise to a new part of mathematics, called harmonic analysis or Fourier analysis. This, in turn, fostered the introduction at the end of the nineteenth century of a completely new theory of integration, now called the

Lebesgue integral.

One important application pertains to signal analysis. Here,f ?x?could represent the amplitude of a sound wave, such as a musical note, or an electrical signal from a byt). The Fourier series representation of a signal representsa decomposition of this signal into its various frequency components. The terms sinkxand coskx 712

12.1 Computation of Fourier Series713

oscillate with numerical frequency1ofk?2?. Signals are often corrupted by noise, which usually involvesthe high-frequencycomponents(whenkis large). Noise can sometimes be filtered out by setting the high-frequency coefficients (thea kandbkwhenkis large) equal to zero. Data compression is another increasingly important problem. One way to ac- complishdata compressionusesFourierseries. Here thegoalis tobeableto storeor transmit the essential parts of a signal using as few bits of information as possible. The Fourierseries approachto the problemis to store (or transmit)onlythosea kand b kthat are larger than some specified tolerance and discard therest. Fortunately, an the aforementioned approach can lead to significant data compression.

12.1Computation of Fourier Series

The problem that we wish to address is the one faced by Fourier. Suppose thatf?x? is a given function on the interval??? ? ??. Can we find coefficients,anandbn, so that f ?x??a0 2 n?1 [ancosnx?bnsinnx]?for???x??? (1.1)

Noticethat,exceptfortheterma

0 basic terms sinnxand cosnxforna positive integer. These functions are periodic with period 2 ? ?n, so their graphs trace throughnperiods over the interval??? ? ??. Figure 1 shows the graphs of cosxand cos5x, and Figure 2 shows the graphs of sinxand sin5x. Notice how the functions become more oscillatory asnincreases. 1 x -1-π

Figure 1The graphs of cosx

and cos 5x. 1 x -1-π

Figure 2The graphs of sinx

and sin 5x.

The orthogonality relations

Our task of finding the coefficientsanandbnfor which (1.1) is true is facilitated by the following lemma. These orthogonalityrelations are oneof the keys to the whole theory of Fourier series.

1Be sure you know the difference between angular frequency,kin this case, and numerical frequency. It

is explained in Section 4.1.

714Chapter 12 Fourier Series

LEMMA 1.2Letpandqbepositiveintegers. Thenwehavethefollowingorthogonalityrelations. ??sinpx dx? ???cospx dx?0 (1.3) sinpxcosqx dx?0 (1.4) cospxcosqx dx? ? ?ifp?q 0 ?ifp??q(1.5) sinpxsinqx dx? ? ?ifp?q 0 ?ifp? ?q(1.6) We will leave the proof of these identities for the exercises.

Computation of the coefficients

The orthogonality relations enable us to find the coefficientsanandbnin (1.1). Suppose we are given a functionfthat can be expressed as f ?x??a0 2 k?1 ?akcoskx?bksinkx?(1.7) ontheinterval ??? ? ??. Tofinda0, wesimplyintegratetheseries(1.7)termbyterm. Using the orthogonality relation (1.3), we see that f?x?dx?a0 ? ?(1.8)

To finda

nforn?1, we multiply both sides of (1.7) by cosnxand integrate term by term, getting f?x?cosnx dx? ?a0 2 k?1 ?akcoskx?bksinkx? ?cosnx dx ?a0 2 cosnx dx k?1 ak coskxcosnx dx k?1 bk sinkxcosnx dx? (1.9) Using the orthogonality relations in Lemma 1.2, we see that all the terms on the right-hand side of (1.9) are equal to zero, except for a n cosnxcosnx dx?an

12.1 Computation of Fourier Series715

Hence, equation (1.9) becomes

f?x?cosnx dx?an ?? ?forn?1? so, including equation (1.8),2 an ?1 ???f?x?cosnx dx?forn?0?(1.10)

Tofindb

n,wemultiplyequation(1.7)bysinnxandthenintegrate. Byreasoning similar to the computation ofa n, we obtain b n ?1 ???f?x?sinnx dx?forn?1. (1.11)

Definition of Fourier series

Iffis a piecewise continuousfunction on the interval??? ? ??, we can computethe coefficientsa nandbnusing (1.10) and (1.11). Thus we can define the Fourier series for any such function. DEFINITION 1.12Supposethatfis a piecewisecontinuousfunctiononthe interval ??? ? ??. With the coefficients computed using (1.10) and (1.11) , we define theFourier series associated tofby f ?x??a0 2 n?1 [ancosnx?bnsinnx]?(1.13)

The finite sum

S N ?x??a0 2 N n?1 [ancosnx?bnsinnx] (1.14) is called thepartial sum of orderNfor the Fourier series in (1.13). We say that the Fourier series converges atxif the sequence of partial sums converges atxas N ???We use the symbol?in (1.13) because we cannot be sure that the series converges. We will explore the question of convergencein the next section, and we will see in Theorem 2.3 that for functions that are minimallywell behaved, the can be replaced by an equals sign for most values ofx. EXAMPLE 1.15uFind the Fourier series associated with the function f ?x?? ?0?for???x?0, ??x?for 0?x?? ?

2We used the expressiona0

?2 instead ofa0for the constant term in the Fourier series (1.7) so formulas like equation (1.10) would be true forn ?0 as well as for largern.

716Chapter 12 Fourier Series

We compute the coefficienta0using (1.8) or (1.10). We have a 0 ?1 ???f?x?dx?1 ?0 ???x?dx? ?2 Forn?1, we use (1.10), and integrate by parts to get a n ?1 ???f?x?cosnx dx?1 ?0 ???x?cosnx dx ?1 n? ?0 ???x?dsinnx ?1 n? ???x?sinnx 0 ?1 n? ?0sinnx dx ?1 n2 ?1?cosn? ?? Thus, since cosn????1?n, the even numbered coefficients area2n ?0, and the odd numbered coefficients area 2n?1 ?2??? ?2n?1?2 ?forn?0? We computebnusing (1.11). Again we integrate by parts to get b n ?1 ???f?x?sinnx dx?1 ?0 ???x?sinnx dx ??1 n? ?0 ???x?dcosnx ??1 n? ???x?cosnx 0 ?1 n? ?0cosnx dx ?1 n The magnitude of the coefficients is plotted in Figure 3, with?an ?in black and ?bn ?in blue. Notice how the coefficients decay to 0. The Fourier series forfis f ?x?? ?4 ?2 ?n?0 cos?2n?1?x ?2n?1?2 n?1 sinnx n ?(1.16) u Let's examine the experimental evidence for convergence ofthe Fourier series

0 10 20 3001n

|an| and |bn|

Figure 3The Fourier coefficients

for the function in Example 1.15. in Example 1.15. The partial sums of orders 3, 30, and 300 for the Fourier series in Example 1.15 are shown in Figures 4, 5, and 6, respectively. In these figures the functionfis plotted in black and the partial sum in blue. The evidence of these figures is that the Fourier series converges tof ?x?, at least away from the discontinuity of the function atx ?0?

12.1 Computation of Fourier Series717

0 0 x

Figure 4The partial sum of

order 3 for the function in

Example 1.15.

0 0 x

Figure 5The partial sum of

order 30 for the function in

Example 1.15.

0 0 x

Figure 6The partial sum of

order 300 for the function in

Example 1.15.

Fourier series on a more general interval

It is very natural to consider functions defined on??? ? ??when studying Fourier series because in applications the argumentxis frequently an angle. However, in other applications (such as heat transfer and the vibrating string) the argument representsa length. In sucha case it is morenatural to assumethatxis in an interval oftheform ??L?L?. Itis a matterofa simplechangeof variabletogofrom??? ? ?? to a more general integral.

Suppose thatf

?x?is defined for?L?x?L?Then the functionF?y?? f?Ly?? ?is defined for???y??. ForFwe have the Fourier series defined in

Definition 1.20. Using the formulay

??x?L, the coefficientsanare given by a n ?1 ???F?y?cosnydy ?1 ???f ?Ly ?cosnydy ?1 L ?L ?Lf?x?cosn ?x Ldx The formula forbnis derived similarly. Thus equations (1.10) and (1.11) are the special case forL ??of the following more general result.

THEOREM 1.17Iff?x??a0

?2? n?1 ?ancos?n?x?L??bnsin?n?x?L??for?L?x?L, then a n ?1quotesdbs_dbs20.pdfusesText_26