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An angular/linear speed bicycle exampleOn October 1, 2003, Leontien Zijlaand-van Moorsel set a new women"s hour record by

riding a bicycle 46.065 km in one hour on the velodrome at MexicoCity. She rode afixed gearbike which was qualitatively like this one: radius 34cm rear sprocket

14 teeth

radius 3cm front sprocket

54 teethrear wheel

A fixed gear means that there is no freewheel: the rear sprocket isattached directly to the rear wheel, so that if the wheel turns, the rear sprocket (and hencethe front sprocket and pedals) turns. You can"t "coast" on such a bike. These kinds of bikes are standard in track racing. They also have no brakes, to make it difficult to make sudden speed changes. This improvessafety in the close quarters of track racing. Here is the question:If Leontien rode at a constant speed, how fast did she pedal?That is, how quickly must her pedals (and feet) have been going around?In cycling, this rate is known as thecadence. Here"s the idea: if we know how fast the wheels turn, then we"ll knowhow fast the rear sprocket turns, then we"ll know how fast the chain moves, then we"ll know how fast the front sprocket turns, then we"ll know how fast the pedals turn. Any wheel, sprocket, gear, etc., that turns has both anangular speedand alinear speed: The angular speed is the rate at which the thing turns, described in units like revolutions per minute, degrees per second, radians per hour, etc. The linear speed is the speed at which a a point on the edge of the object travels in its circular path around the center of the object. The units can be any usual speed units: meters per second, miles per hour, etc. Ifvrepresents the linear speed of a rotating object,rits radius, andωits angular velocity in units of radians per unit of time, then v=rω. This is an extremely useful formula: it related these three quantities,so that knowing two we can always find the third. Now, the linear speed of a wheel rolling along the ground is also the speed at which the wheel moves along the ground. So if we assume that Leontien moved ata constant speed, then her wheels were always moving 46.065 km/hr, or

46.065km

hr?

1000m1km?

?1hr3600sec? = 12.7958m/sec.

This is the linear speed of her wheels.

Since the rear wheel has a radius ofr= 0.34meters, the angular speed of the rear wheel is given by

ω=v

r=12.7958m/sec0.34m= 37.6347radians/sec. Since the rear sprocket is attached directly to the rear wheel, it rotates exactly as the rear wheel does: every revolution of the rear wheel is a revolution of thesprocket. Hence, the angular speed of the rear sprocket isωrs= 37.6347radians/sec. Knowing that the radius of the rear sprocket is 0.03 m, we can calculate the linear speed of the rear sprocket: v rs=ωrsrrs= (37.6347radians/sec)(0.03m) = 1.12904m/sec. Every point in a sprocket-chain system moves at the same linear speed. Hence every point on the chain has a (linear) speed of 1.12904 m/sec, and the front sprocket has a linear speed of v fs= 1.12904m/sec. We now need the radius of the front sprocket in order to find its angular speed. We can use the fact that the number of teeth on a sprocket must be proportional to itscircumference (so, for instance, if we double the circumference of the sprocket, we double the number of teeth).

Thus,54

rfs=15rrs=150.03m so that r fs=54(0.03m)

15= 0.108m.

With this, we calculate the angular speed of the front sprocket: fs=vfs rfs=1.12904m/sec0.108m= 10.4541rad/sec.

Putting this into more convenient units, we have

fs= 1.6638rev/sec= 99.829rev/min= 99.829rpm. So Leontien was pedalling about 100 revolutions per minute.quotesdbs_dbs14.pdfusesText_20