[PDF] [PDF] Drawing Finite State Automata

18 mar 2002 · {w\ every odd position of w is 1} q0 q1 1 q2 0 0,1 0,1 10 {w\w contains at least two 0s and at most one 1} q0 q1 0 q3 1 q2 0 q4 1 q6 1 q7



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[PDF] COMP 3803 - Assignment 2 Solutions

13 fév 2015 · 1 Q: Let Σ = 1a, bl Write a regular expression for the set of all strings in c 1W : every odd position in W is 1l 0, 1 1 0 0, 1 3 Q: For the NFA 



[PDF] {w every odd position of w is a 1} NFA

{w every odd position of w is a 1} NFA: ∅ 1 2 3 4 ε a a a,b {3} {3,4} b a a b a b DFA equivalent: R E = (1(0∪1))* ∪ (1(0∪1))*1 0 Hint: Consider odd length 



[PDF] Some Theory of Computation Exercises – Week 1

Part i –{w every odd position is 1} This is similar to the even/odd number of as required in question 1 4 above Here we need a gadget to keep track of whether  



[PDF] w every odd position of w is a 1 - FORMAL LANGUAGES

Let L be a regular language with L = ∞ Then there is a positive integer P s t 1 y > 0 (y isn't ε) 2 xy ≤ P 3 For every i ≥ 0, xyiz ∈ L if w ∈ L and w ≥ P



[PDF] Assignment 3

4 déc 2015 · 1 DFAs: Design a DFA for each of the following languages (all over the (a) (5 points) {w every odd position of w is a 0} (the first position is 



[PDF] Solution of Homework 1 (small correction in 14f made on - UF CISE

Figure 3: every odd position of w is a 1 0 0 0 1 1 1 0 0 1 1 1 0 0,1 Figure 4 : w contains at least 2 0 s and at most one 1 vii members - ab, b ; nonmembers 



[PDF] Tutorial Week 8 - Albert Thompson

{ww begins with a 1 and ends with a 0} b c {ww contains the substring 0101, i e , w = x0101y for some strings x, y} 1 {w every odd position of w is a 1} 2 



[PDF] Drawing Finite State Automata

18 mar 2002 · {w\ every odd position of w is 1} q0 q1 1 q2 0 0,1 0,1 10 {w\w contains at least two 0s and at most one 1} q0 q1 0 q3 1 q2 0 q4 1 q6 1 q7



[PDF] CSCE 551 Answers to Midterm Exam I Monday February 16, 2004

16 fév 2004 · 1 (3 points each; 1 2 points total) For each of the following binary (b) {w G {0 , 1 }* ² every odd position of w is a 1 } (Note that ifw /= e, the first 

[PDF] every odd position of w is a 1 regular expression

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